6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

If the true discount on s sum due 2 years hence at 14% per annum be Rs. 168, the sum due is ?

A) Rs.948	B) Rs.876
C) Rs.768	D) Rs.658

Answer & Explanation Answer: C) Rs.768

Explanation:

P.W. = $\frac{100 \times T . D}{R \times T}$ = $\frac{100 \times 168}{14 \times 2}$ = 600.

Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.

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Filed Under: True Discount
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

17 13072

Q:

If 50 is subtracted from two-third of a number, the result is equal to sum of 40 and one-fourth of that number. What is the number ?

A) 156	B) 179
C) 198	D) 216

Answer & Explanation Answer: D) 216

Explanation:

Let the number be x.

Then, 2/3x-50 = 1/4x +50

=> 5/12x = 90

x = (90 x 12) / 5 = 216

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Filed Under: Problems on Numbers

6 13065

Q:

The average age of A and B, 2 years ago was 26. If the age of A, 5 years hence is 40 yrs, and B is 5 years younger to C, then find the difference between the age of A and C?

A) 11 yrs	B) 9 yrs
C) 7 yrs	D) 13 yrs

Answer & Explanation Answer: B) 9 yrs

Explanation:

Let the present ages of A and B be 'x' and 'y' respectively

From the given data,

[(x-2) + (y-2)]/2 = 26

=> x+y = 56

But given the age of A, 5 years hence is 40 yrs => present age of A = 40 - 5 = 35 yrs

=> x = 35 => y = 56 - 35 = 21

=> Age of B = 21 yrs

Given B is 5 years younger to C,

=> Age of C = 21 + 5 = 26 yrs

=> Required Difference between ages of A and C = 35 - 26 = 9 yrs.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

17 13064

Q:

What will be compounded amount?
I. Rs. 200 was borrowed for 192 months at 6% compounded annually.
II. Rs. 200 was borrowed for 16 years at 6%.

A) I alone sufficient while II alone not sufficient to answer	B) II alone sufficient while I alone not sufficient to answer
C) Either I or II alone sufficient to answer	D) Both I and II are not sufficient to answer

Answer & Explanation Answer: C) Either I or II alone sufficient to answer

Explanation:

I. Amount = $R s . [200 * {(1 + \frac{6}{100})}^{16}]$

II. Amount = $R s [200 * {(1 + \frac{6}{100})}^{16}]$

Thus, I as well as II gives the answer.

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

2 13048

Q:

How many iron rods, each of length 7 mts and diameter 2 cms can be made out of 0.88 cubic metre of iron ?

A) 500	B) 600
C) 400	D) 300

Answer & Explanation Answer: C) 400

Explanation:

Given length of iron rod =7 mts and and diameter of rod = 2 cms

=> r = 1/100 mts

Therefore, Volume of one rod = ${πr}^{2} h$ cu. m = $(\frac{22}{7} \times {[\frac{1}{100}]}^{2} \times 7)$ cu. m = $\frac{11}{5000}$ cu. m

Given volume of iron = 0.88 cu. m

Therefore, Number of rods = $(0.88 \times \frac{5000}{11})$ = 400.

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Filed Under: Volume and Surface Area
Exam Prep: CAT
Job Role: Bank PO

17 13044

Q:

The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is:

A) 153600	B) 143600
C) 13600	D) 16300

Answer & Explanation Answer: A) 153600

Explanation:

Let length = 3x metres and breadth = 2x metres.

Then, 2(3x + 2x) = 1600 or x = 160.

Length = 480 m and Breadth = 320 m.Area = (480 x 320) sq.m = 153600 sq.m

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

4 13039

Q:

What will be the ratio of simple interest earned by certain amount at the same rate of interest for 6 years and that for 9 years?

A) 1:3	B) 1:4
C) 2:3	D) data is inadequate

Answer & Explanation Answer: C) 2:3

Explanation:

Let the principal be P and rate of interest be R%.

Required ratio = $[(\frac{\frac{P * R * 6}{100}}{\frac{P * R * 9}{100}})] = \frac{6 P R}{9 P R} = \frac{6}{9} = \frac{2}{3}$

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Filed Under: Simple Interest
Exam Prep: GRE

14 13036

Q:

If $3 x + 7 = x^{2} + p = 7 x + 5$ , what is the value of P ?

A) 17/2	B) 25/3
C) 33/4	D) 41/5

Answer & Explanation Answer: A) 17/2

Explanation:

$3 x + 7 = 7 x + 5 = > 7 x - 3 x = 2 = > 4 x = 2 = > x = 2$

Now, $3 x + 7 = x^{2} + p = \frac{3}{2} + 7 = \frac{1}{4} + p = > p = \frac{17}{2}$

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Filed Under: Simplification

11 13030

Quantitative Aptitude - Arithmetic Ability Questions

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