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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

If 50 is subtracted from two-third of a number, the result is equal to sum of 40 and one-fourth of that number. What is the number ?

A) 156 B) 179
C) 198 D) 216
 
Answer & Explanation Answer: D) 216

Explanation:

Let the number be x.

 

Then, 2/3x-50 = 1/4x +50

 

=>  5/12x = 90

 

x = (90 x 12) / 5 = 216 

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Filed Under: Problems on Numbers

6 13312
Q:

If 3x+7=x2+p=7x+5, what is the value of P ?

A) 17/2 B) 25/3
C) 33/4 D) 41/5
 
Answer & Explanation Answer: A) 17/2

Explanation:

 

 

3x+7=7x+5=>7x-3x=2=>4x=2=>x=2

 

Now, 3x+7=x2+p=32+7=14+p=>p=172

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Filed Under: Simplification

11 13279
Q:

In How many ways is it possible to make a selection by taking any number of 15 fruits, namely 3 oranges, 5 apples and 7 mangoes?

A) 131 B) 191
C) 68 D) 3720
 
Answer & Explanation Answer: B) 191

Explanation:

Out of 15 fruits, 7 are alike of one kind, 5 are alike of a second kind and 3 are alike of a third kind.

Hence, the required number of ways = [ (7+1) (5+1) (3+1) -1] =191

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Filed Under: Permutations and Combinations

19 13277
Q:

In Veeru Bhai Pvt.limited company 60% of the employees are men and 48% of the employees are Engineer and 66.6% of these are men. The percentage of women who are not engineers:

A) 33.33% B) 60%
C) 52% D) 46.66%
 
Answer & Explanation Answer: B) 60%

Explanation:

              Men               Women

 

              600x               400x

 

      Total engineers = 480x

 

      Male engineers = 480x X 0.66 = 320

 

   Women who are Engineers  = 160x 

 

  Women are not Engineers  = 400x - 160x = 240x

 

 Required percentage = 240400x100 = 60%

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

14 13269
Q:

If a box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains no defective bulbs.

A) 5/12 B) 7/12
C) 3/14 D) 1/12
 
Answer & Explanation Answer: D) 1/12

Explanation:

Total number of elementary events = 10C5

 

Number of ways of selecting no defective bulbs i.e., 5 non-defective bulbs out of 7 is 7C5.

 

So,required probability =7C5/ 10C5 = 1/12.

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Filed Under: Probability

20 13254
Q:

The highest score in an inning was  3/11 of the total and the next highest was 3/11 of the reminder . If the score  differ by 9, the total score was :

A) 110 B) 121
C) 132 D) 143
 
Answer & Explanation Answer: B) 121

Explanation:

Let the score be x. Then the highest score = 3x/11.

Reminder = (x - 3x/11) = 8x/11 .Next the highest score = 3/11 of 8x/11 = 24x/121.

3x/11 - 24x/11 = 9 <=> 33x - 24x = 9*121 <=> x= 121..

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Filed Under: Simplification

17 13233
Q:

The LCM of 15, 18 and 24 is

 

A) 360 B) 6
C) 3 D) 540
 
Answer & Explanation Answer: A) 360

Explanation:
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Filed Under: HCF and LCM
Exam Prep: Bank Exams

7 13205
Q:

The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is

A) 6.06% B) 6.07%
C) 6.08% D) 6.09%
 
Answer & Explanation Answer: D) 6.09%

Explanation:

Amount of Rs. 100 for 1 year

when compounded half-yearly = Rs.[100*(1+3/100)^2]=Rs.106.09

Effective rate=(106.09-100)%=6.09%

 

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

10 13204