Quantitative Aptitude - Arithmetic Ability Questions

The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.
But, 24th Nov, 2007 is Thursday.
24 - 10 = 14 days.
Therefore, 2 weeks ago it is same day.
Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.

In the word 'CORPORATION', we treat the vowels OOAIO as one letter.

Thus, we have CRPRTN (OOAIO).

This has 7 (6 + 1) letters of which R occurs 2 times and the rest are different.

Number of ways arranging these letters =7!/2!= 2520.

Now, 5 vowels in which O occurs 3 times and the rest are different, can be arranged in 3!/5!= 20 ways.

Required number of ways = (2520 x 20) = 50400.

If the price of the oranges decreases by 10%, the woman would save 10% of the money that is Rs.50 to buy the same amount as before.Now in Rs. 50 she can buy 2 kg more, therefore the current price of 1 kg of oranges is Rs25.Now, this current price is after 10% reduction.

Therefore, the original price =  25/0.9  = Rs. 27.77

Let initially 'X' ticket has been sold.
So now in 2nd week 20% increases, so
=> X x 120/100
In 3rd week 16% increases, so
=> X x (120/100) x (116/100)
In 4th week 20% decrease, so
=> X x (120/100) x (116/100) x (80/100) = 1392
X = 1250.

If we consider the third term to be ‘x”
The 15th term will be (x + 12d)
6th term will be (x + 3d)
11th term will be (x + 8d) and
13th term will be (x + 10d).
Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.
x + 9d will be the 12th term.

Thus, 12th term of the A.P will be zero.

If an object travels at 5 feet per second it covers 5x60 feet in one minute, and 5x60x60 feet in one hour.

Answer = 1800 

Suppose commodity X wil cost 40 paise more than Y after Z  years. Then,

        (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40

=>  0.25Z = 0.40 + 2.10  => Z= 2.50/0.25 = 10

Therefore, X will cost 40 paise more than Y 10  years after 2001 . i.e in 2011