Quantitative Aptitude - Arithmetic Ability Questions

The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.
But, 24th Nov, 2007 is Thursday.
24 - 10 = 14 days.
Therefore, 2 weeks ago it is same day.
Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.

a : b =(1/2 * x * H) : (1/2 * y * h) 

bxH = ayh        => H/h =ay/bx 

Hence H:h = ay:bx

Given when she sells at Rs. 160 for 20 articles, she get 40% loss.

Then, to get 20% profit selling at Rs. 240 for let 'P' articles

=> 1602060=240p120

=> 120 x 160 x P = 20 x 70 x 240

=> P =  15 articles.

We can't determine the last day of the next month which has 31 days because we don't know the days in present month which may be 30 or 31. And the next month may be March which contains 31 days  which implies that the present month may be February which contains 28 or 29 days.

Let 'P' be the original population at the beginning

P x (95/100) x (85/100) = 3553

P = 4400.

Let x litre pepsi is required.

(10-9)=1           :                3=(9-6)

Therefore  in 1:3 one part = 5 

=>  x= 5 litres

Numbers of students in section A = x
∴ Numbers of students in section B and C = (100 – x)
∴ x 70 + (100 – x) 87.5 = 84 100
=> 70x + 87.5 100 – 87.5x = 8400
=> 8750 – 17.5x = 8400
=> 17.5x = 8750 – 8400 => x = 20.