Quantitative Aptitude - Arithmetic Ability Questions

He sold 4 cycles for Rs. 8400
[It means each cycle price is Rs. 2100]
And again he sold 3 cycles for Rs. 1900 each
If he want to gain avg profit on each cycle is Rs. 320 per cycle.
So profit for 10 cycles is @ Rs.320 is,
10 x 320 = Rs. 3200
He already got Rs. 1850 profit by selling 7 cycles.
Now, remaining amount is 3200 - 1850 = 1350
So from remaining 3 cycles we want to get Rs. 1350 profit ,
1350/3 = 450
so he must sell remaining 3 cycles at Rs. 2200 each one.

Let x = the youngest child. Each of the other four children will then be x+3, x+6, x+9, x+12. 

We know that the sum of their ages is 50 .

so, x+(x+3)+(x+6)+(x+9)+(x+12) = 50

=>  x= 4

 The youngest child is 4 years old.

Here from the given information,

The ratio of investments of Rajeev, Deepu & Shakti is

R : D : S = (10000 × 12) : (12000 × 10) : (7200 × 8)

= 25 : 25 : 12

Now the Profit = 2 × (72000-10000) = 124000

Share of Rajeev = 124000 x 25/62 = 48000

Profit of Rajeev = 48000 - 10000 = 38000

Second gun shot take 30 sec to reach rahul imples distance between two.

given speed of sound = 330 m/s

Now, distance = 330 m/s x 30 sec 

Hence, speed of the bus = d/t = 330x30/(14x60 + 30) = 330/29 m/s.

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27 x meters, and

length of the second train = 17 y meters.

(27 x + 17 y) / (x + y) = 23

=> 27 x + 17 y = 23 x + 23 y

=> 4 x = 6 y

=> x/y = 3/2.

nS= C4 12=495

nE= C28×C14=112

∴P(E)=112495

Required Sum = PW of Rs.702 due 6 months hence + PW of Rs.702 due 1 year hence 

= Rs.[ (100 x 702) / (100+(8 x 1/2)) ] + [ (100 x 702) / (100+(8 x 1)) ]  

= Rs.1325

Let the 1 day work of a boy=b and a girl=g, then
2b + g = 1/5 ---(i) and
b + 2g = 1/6 ---(ii)
On solving (i) & (ii), b=7/90, g=2/45
As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week,
so a girl will be paid 28×245790 = 16 $.