Quantitative Aptitude - Arithmetic Ability Questions

Q:

A and B started a business investing the money in ratio 4:6, after 6 months B withdraw his investment and C joins him with twice the amount of B. At the end of the year total profit is Rs.3315. Find share of C ?

A) Rs. 450 B) Rs. 1020
C) Rs. 765 D) Rs. 1530
 
Answer & Explanation Answer: D) Rs. 1530

Explanation:

Ratio of investments of A, B & C =>

bank

Share of C = 1530

Share of B = 765

Share of A = 1020

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Filed Under: Partnership
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22 11628
Q:

The value of 1log360+1log460+1log560is

A) 0 B) 1
C) 5 D) 60
 
Answer & Explanation Answer: B) 1

Explanation:

            => log60(3*4*5)

                              =>     log6060

                                   = 1

 

                                                       

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Filed Under: Logarithms
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Q:

A can do a work in 24 days. B is 20% more efficient than A. If C can do the work in 10 more days than B, find the time taken by A and C together to complete the work.

A) 43/3 days B) 40/3 days
C) 50/3 days D) 41/2 days
 
Answer & Explanation Answer: B) 40/3 days

Explanation:

A takes 24 days to complete a work.
B is 20% more efficient than A,
hence B will take (24*100)/120 = 20 days.
C takes (20+10) = 30 days.
Time taken by A & C in completing the work = (24*30)/(24+30) = (24*30)/54 = 40/3 days.

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Filed Under: Time and Work
Exam Prep: Bank Exams

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Q:

What smallest number of 6 digit is divisible by 111?

Answer

Smallest number of 6 digits is 100000


on dividing 100000 by 111 we get 100 as remainder 


\inline \fn_jvn \therefore Number to be added = (111 -100) = 11


\inline \fn_jvn \therefore Required Number  = 100011

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Subject: Numbers

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Q:

There are two mixtures of honey and water in which the ratio of honey and water are as 1:3 and 3:1 respectively. Two litres are drawn from first mixture and 3 litres from second mixture, are mixed to form another mixture. What is the ratio of honey and water in it ?

A) 111:108 B) 11:9
C) 103:72 D) None
 
Answer & Explanation Answer: B) 11:9

Explanation:

From the given data,

 

The part of honey in the first mixture = 1/4

 

The part of honey in the second mixture = 3/4

 

Let the part of honey in the third mixture = x

 

Then,

 

1/4             3/4

 

           x

 

(3/4)-x     x-(1/4) 

 

Given from mixtures 1 & 2 the ratio of mixture taken out is 2 : 3

 

=> 34-xx-14=23

 

=> Solving we get the part of honey in the third mixture as 11/20

 

=> the remaining part of the mixture is water = 9/20

 

Hence, the ratio of the mixture of honey and water in the third mixture is 11 : 9 .

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Filed Under: Alligation or Mixture
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20 11568
Q:

A farmer divides his herd of k cows among his 4 sons, so that one son gets one half of the herd, the second gets one-fourth, the third gets one-fifth and the fourth gets 9 cows. Then k is equal to ?

A) 160 B) 120
C) 140 D) 180
 
Answer & Explanation Answer: D) 180

Explanation:

Given total number of cows = k
Now, 1st son share = k/2
2nd son share = k/4
3rd son share = k/5
4th son share = 9

(k) + (k/4) + (k/5) + 9 = k
=> k - (19k/20) = 9
=> (20k-19k)/20 = 9
=> k = 180.

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Filed Under: Percentage
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Q:

The average of 9 results is 50. The average of first four results is 52 and average of last four results is 49 . what is the fifth result?

Answer

Total of results = 50 x 9 = 450


Total of first four results = 52 x 4 = 208


Total of Last four results = 49 x 4 = 196


Hence the fifth result = 450 - (208 + 196) = 46

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Subject: Average

22 11558
Q:

If y/(x - z) = (y + x)/z = x/y then find z : y : x ?

A) 1:2:3 B) 3:2:4
C) 4:3:2 D) 2:3:4
 
Answer & Explanation Answer: B) 3:2:4

Explanation:

Given, y/(x - z) = (y + x)/z = x/y
yz = xy + x2 - yz - xz ....(1)
Also xy = yx-z x2 -xz = y2 ....(2)
Using (1) and (2), we get yz = xy - yz + y2
2yz = xy + y2
2z = x + y
Only option (B) satisfies the equation.

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Filed Under: Ratios and Proportions
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