6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ?

A) 2413 sq.m	B) 1234 sq.m
C) 4312 sq.m	D) 2143 sq.m

Answer & Explanation Answer: C) 4312 sq.m

Explanation:

Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively.

$2 πs$ = 264 and $2 πl$ = 352

s = $\frac{264}{2 π}$ and l = $\frac{352}{2 π}$

Difference between the areas = $π l^{2} - π s^{2}$

= $π (\frac{176^{2}}{π^{2}} - \frac{132^{2}}{π^{2}})$

= $\frac{1762}{π} - \frac{1322}{π}$

= (176 - 132)(176 + 132) / $π$

= (44 x 308) / (22/7) = 4312 sq.m

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

18 11051

Q:

If a solid sphere of radius 10 cms is moulded into 8 spherical solid balls of equal radius, then surface area of each ball (in sq.cm) is ?

A) 100 π	B) 101/π
C) 99 π/12	D) 54/13π

Answer & Explanation Answer: A) 100 π

Explanation:

4/3 π x 10 x 10 x 10 = 8 x 4/3 π x r x r x r
r = 5
4π x 5 x 5 = 100π

Report Error

View Answer Report Error Discuss

Filed Under: Volume and Surface Area
Exam Prep: CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

17 11048

Q:

Sonika invested an amount of Rs.5800 for 2 years. At what rate of compound interest will she get an amount of Rs.594.50 at the end of 2 years ?

A) 6.5%	B) 6%
C) 5%	D) 4.5%

Answer & Explanation Answer: C) 5%

Explanation:

C.I = $P [{(1 + \frac{r}{100})}^{t} - 1]$

594.5 = $5800 [{(1 + \frac{r}{100})}^{2} - 1]$

$\frac{594.5}{5800} + 1 = {(1 + \frac{r}{100})}^{2}$

$\frac{r}{100} = 1.05 - 1 = 0.05 = > r = 5$ % .

Report Error

View Answer Report Error Discuss

Filed Under: Compound Interest
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

13 11032

Q:

Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of Interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?

A) 3.6	B) 6
C) 18	D) cannot be determined

Answer & Explanation Answer: B) 6

Explanation:

Let rate = R% and time = R years.

Then, $(\frac{1200 \times R \times R}{100}) = 432$

$12 R^{2} = 432$

=> R = 6.

Report Error

View Answer Report Error Discuss

Filed Under: Simple Interest
Exam Prep: GRE
Job Role: Bank PO

6 11021

Q:

In what time would a cistern be filled by three pipes which diameters are 2 cm, 3 cm and 4 cm running together, when the largest alone can fill it is 58 minutes? The amount of water flowing in each pipe is proportional to the square of its diameter.

A) 26 min	B) 32 min
C) 36 min	D) 42 min

Answer & Explanation Answer: B) 32 min

Explanation:

Given that the diameters of the three pipes are 2 cm, 3 cm and 4 cm

From the given data,

Amount of water from three pipes is 4 units, 9 units and 16 units.

Let the capacity of cistern be 'p' units.

∴ p/58 = 16

⇒ p = 928 units.

In 1 minute, quantity to be filled by 3 pipes = 29 units

∴ Total time required = 928/29 = 32 minutes.

Report Error

View Answer Report Error Discuss

Filed Under: Pipes and Cistern
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

11 11000

Q:

A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook ?

A) 15	B) 20
C) 10	D) 8

Answer & Explanation Answer: C) 10

Explanation:

Let the price of each note book be Rs.x.

Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.

Hence xy = 300

=> y = 300/x

(x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy

=>5(300/x) - 10x - 50 = 0 => $- 150 + x^{2} + 5 x$

multiplying both sides by -1/10x

=> $x^{2} + 15 x - 10 x - 150 = 0$

=> x(x + 15) - 10(x + 15) = 0

=> x = 10 or -15

As x>0, x = 10.

Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

9 10998

Q:

The circumference of a circle, whose area is 24.64 sq.m

A) 14.64	B) 16.36
C) 17.60	D) 18.40

Answer & Explanation Answer: C) 17.60

Explanation:

${πr}^{2} = 26.64$

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

11 10997

Q:

A man saves Rs. 200 in each of the first three months of his service. In each of the subsequent months his saving increases by Rs. 40 more than the saving of immediately previous month. His total saving from the start of service will be Rs. 11040 after ?

A) 19 months	B) 21 months
C) 18 months	D) 20 months

Answer & Explanation Answer: B) 21 months

Explanation:

Total savings = 200 + 200 + 200 + 240 + 280 + ... to n months = 11040

= 120 + 80 + 160 + 40 + 200 + 240 + ....n terms
= 40 + 80 + 120 + 160 + 200 + 240 + ...n terms
= n/2[2a + (n-1)d] + 80 + 40 = 11040
= n/2[240 + (n-1)40] = 10920
= n[6+n-1] = 546
= n[n+5] = 546
n = 21

Report Error

View Answer Report Error Discuss

Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk

10 10980

Quantitative Aptitude - Arithmetic Ability Questions

Quick Links