Quantitative Aptitude - Arithmetic Ability Questions

Q:

A cuboid of dimension 24cm x 9cm x 8 cm is melted and smaller cubers are of side 3 cm is formed.find how many such cubes can be formed ?

A) 64 B) 56
C) 48 D) 40
 
Answer & Explanation Answer: A) 64

Explanation:

Volume of cuboid = (24 x 9 x 8) cm = 1728 cu.cm
Volume of small cube = (3 x 3 x 3) cm = 27 cu.cm


So, No. of small cubes formed = 1728/27 = 64.

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Filed Under: Volume and Surface Area
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5 9799
Q:

A man pays Rs. 6.40 per litre of milk. He adds water and sells the mixture at Rs. 8 per litre, thereby making 37.5% profit. The proportion of water to milk received by the customers is

A) 1 : 10 B) 10 : 1
C) 9 : 11 D) 11 : 9
 
Answer & Explanation Answer: A) 1 : 10

Explanation:

Customer ratio of Milk and Water is given by

Milk          ::        Water

  6.4                         0

         81 + 38 =6411

 6411                      6410 - 6411 

=> Milk : Water = 110 : 11 = 10 : 1

 

Therefore, the proportionate of Water to Milk for Customer is 1 : 10

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Filed Under: Alligation or Mixture
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29 9789
Q:

An item is sold at a loss of 10%. Had it sold for Rs. 9 more, a profit of 25/2% would have gained. What is the cost price of the item?

A) Rs. 90 B) Rs. 75
C) Rs. 55 D) Rs. 40
 
Answer & Explanation Answer: D) Rs. 40

Explanation:

Let the cost price of the item = Rs. 50

Sold at 10% loss => for Rs. 50 loss  S.P = Rs. 45

From the  given data,

25/2 % gain if it is sold at Rs. 9 more

56.25 - 45 = 9

=> 11.25 = 9

=> 22.5 = 18

=> 45 = 36

=> 50 = ?

=> C.P = 50 x 3645 = 40

 

Hence, the Cost price of the item = Rs. 40.

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Filed Under: Profit and Loss
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15 9777
Q:

A train is traveling at 48 kmph . It crosses another train having half of its length , traveling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. What is the length of the platform ?

A) 500 B) 400
C) 360 D) 480
 
Answer & Explanation Answer: B) 400

Explanation:

Speed of train 1 = 48 kmph
Let the length of train 1 = 2x meter

Speed of train 2 = 42 kmph
Length of train 2 = x meter (because it is half of train 1's length)

Distance = 2x + x = 3x
Relative speed= 48+42 = 90 kmph = (90*5/18)  m/s = 25 m/s 


Time = 12 s

Distance/time = speed 

=>3x/12 = 25 (25*12)/3 

Length of the first train = 2x = 200 meter
Time taken to cross the platform= 45 s

Speed of train 1 = 48 kmph = 480/36 = 40/3 m/s

Distance = 200 + y     [where y is the length of the platform] 

x =100m => 200+y = 45* 40/3
y = 400m

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Filed Under: Problems on Trains

13 9775
Q:

The certain worth of a certain sum due sometime hence is Rs. 1600 and the true discount is

Rs. 160. The banker's gain is:

A) 15 B) 16
C) 14 D) 13
 
Answer & Explanation Answer: B) 16

Explanation:

B.G. =(T.D.)^2/P.W.

      = Rs. (160*160)/1600 = Rs. 16.

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Filed Under: Banker's Discount

1 9767
Q:

HCF of 1, 2, 3?

A) 3 B) 2
C) 1 D) 0
 
Answer & Explanation Answer: C) 1

Explanation:

Given numbers are 1, 2 and 3

Factors of 1 = 1

Factors of 2 = 1, 2

Factors of 3 = 1, 2 and 3

Common factors = 1

 

Hence, the HCF of 1, 2 and 3 = 1.

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Filed Under: HCF and LCM
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31 9764
Q:

Divide Rs.6500 among A,B and C so that after spending 90% , 75% and 60% of their respective saving were in the ratio of 3: 5: 6

Answer

A's spending 90%              \inline \therefore   saving = 10%


B's spending 75%              \therefore   saving = 25%


C's spending 60%              \inline \therefore   saving = 40%


Let us suppose A, B and C saves Rs. 3.5 and 6 respectively.


\inline \therefore 10% of A's saving = Rs.3


100% of A's saving = \inline \frac{3}{10}\times 100 = Rs. 30


25% of B's saving = Rs. 5


100% of B's saving = \inline \frac{5}{25}\times 100 = Rs. 20


40% of C's saving = Rs.6


100% of C's saving = \inline \frac{6}{40}\times 100 = Rs. 15


Divide Rs. 6500 in the ratio of 30 : 20 : 15 as


A's Share  =  \inline \frac{30}{65}\times 6500 = Rs. 3000


B's Share   = \inline \frac{20}{65}\times 6500 = Rs. 2000


C's Share  = \inline \frac{15}{65}\times 6500 = Rs. 1500

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Subject: Ratios and Proportions
Job Role: Bank PO

66 9730
Q:

In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?

A) 50 B) 40
C) 30 D) 20
 
Answer & Explanation Answer: C) 30

Explanation:

There is a meal for 200 children. 150 children have taken the meal.

 

Remaining meal is to be catered to 50 children.

 

Now, 200 children = 120 men.

 

50 children = 12020050 =30men

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Filed Under: Chain Rule

8 9691