6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B ?

A) 10 yrs	B) 11 yrs
C) 12 yrs	D) 13 yrs

Answer & Explanation Answer: A) 10 yrs

Explanation:

Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25 => x = 5
Hence, B's age = 2x = 10 years.

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Filed Under: Problems on Ages
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4 10023

Q:

8 years ago Rama's mother was five times older than her daughter. After 8 years the mother will be twice older than her daughter . Find the present age of Rama?

Answer

Let Rama's age 8 years ago be x years and mother's age 8 years ago be 5x

$\Rightarrow 2(x+16)= 5x+16$

$2x+32=5x+16$

$3x=16$

$x=\frac{16}{3}$ years

Hence, present age of Rama = $x+8=\frac{16}{3}+8=\frac{40}{3}=13\frac{1}{3}$ years

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Subject: Problems on Ages

29 10013

Q:

Sony is one-fifth the age of her mother 15 years ago and Sony’s brother is three-fifth the age of his mother 10 years ago. If the sum of Sony and her brother’s ages is 31 then how old is Sony's mother ?

A) 40	B) 50
C) 60	D) 70

Answer & Explanation Answer: B) 50

Explanation:

Sony and her brother's age sum is 31
Let Sony's mother's age be 'x'.
Now the conditions given for both of their ages related to their mom is
1/5(x-15) + 3/5(x-10) = 31
x-15 + 3x-30 = 155
4x-45 = 155
4x = 200
x = 50
So, Mother's age = 50.

Cross verification : 15 years ago age = 35 => Sony age = 7
10 years ago age = 40 => bro age = 24

Sum = 24 + 7 = 31.

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Filed Under: Problems on Ages
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9 10000

Q:

A man buys Rs. 25 shares in company which pays 9 % dividend. The money invested is such that it gives 10 % on investment. At what price did he buy the shares?

A) 22.50	B) 22
C) 20.45	D) 12.50

Answer & Explanation Answer: A) 22.50

Explanation:

Suppose he buys each share for Rs. x.

Then, $R s . (25 * \frac{9}{100}) = (x * \frac{10}{10})$ or x = Rs. 22.50.

Cost of each share = Rs. 22.50.

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Filed Under: Stocks and Shares

5 9997

Q:

A man pays Rs. 6.40 per litre of milk. He adds water and sells the mixture at Rs. 8 per litre, thereby making 37.5% profit. The proportion of water to milk received by the customers is

A) 1 : 10	B) 10 : 1
C) 9 : 11	D) 11 : 9

Answer & Explanation Answer: A) 1 : 10

Explanation:

Customer ratio of Milk and Water is given by

Milk :: Water

6.4 0

$\frac{8}{1 + \frac{3}{8}} = \frac{64}{11}$

$\frac{64}{11}$ $\frac{64}{10} - \frac{64}{11}$

=> Milk : Water = 110 : 11 = 10 : 1

Therefore, the proportionate of Water to Milk for Customer is 1 : 10

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Filed Under: Alligation or Mixture
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29 9974

Q:

If 60% of total articles are sold at a loss of 50% and remaining articles are sold at a profit of 50%, then what will be the overall loss percentage?

A) 20	B) 15
C) 25	D) 10

Answer & Explanation Answer: D) 10

Explanation:

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Filed Under: Profit and Loss
Exam Prep: Bank Exams

3 9972

Q:

If 6 men and 3 boys working together, can do four times as much work per hour as a man and a boy together. Find the ratio of the work done by a man and that of a boy for a given time ?

A) 1 : 2	B) 2 : 1
C) 3 : 1	D) 1 : 3

Answer & Explanation Answer: A) 1 : 2

Explanation:

6M + 3B = 4(1M + 1B)
6M + 3B = 4M + 4B
2M = 1B

M/B = 1/2

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Filed Under: Ratios and Proportions
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19 9958

Q:

If x is chosen at random from the set {1,2,3,4} and y is to be chosen at random from the set {5,6,7}, what is the probability that xy will be even?

A) 1/2	B) 2/3
C) 3/4	D) 4/3

Answer & Explanation Answer: B) 2/3

Explanation:

S ={(1,5),(1,6),(1,7),(2,5),(2,6),(2,7),(3,5),(3,6),(3,7),(4,5),(4,6),(4,7)}
Total element n(S)=12

xy will be even when even x or y or both will be even.
Events of x, y being even is E.
E ={(1,6),(2,5),(2,6),(2,7),(3,6),(4,5),(4,6),(4,7)}
n(E) = 8

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