Quantitative Aptitude - Arithmetic Ability Questions

Q:

A certain amount is divided among P, Q and R in the ratio of 3 : 7 : 6 respectively. If the difference between share of P and Q is Rs. 2700, what is R's share?

A) Rs. 4050 B) Rs. 2121
C) Rs. 5040 D) Rs. 3550
 
Answer & Explanation Answer: A) Rs. 4050

Explanation:

Let the ratio amount be 'p'

7p - 3p = 2700

4p = 2700

p = 675

R's Share = 675 × 6 = Rs. 4050

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Q:

In a simultaneous throw of two dice, what is the probability of getting a total of 7 ?

A) 1/6 B) 1/4
C) 1/20 D) 3/4
 
Answer & Explanation Answer: A) 1/6

Explanation:

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Filed Under: Probability

16 9170
Q:

The ratio of efficiencies of P, Q and R is 2 : 3 : 4. While P and R work on alternate days and Q work for all days. Now the work completed in total 10 days and the total amount they get is Rs. 1200. Find the amount of each person(respectively).

A) 200, 600, 400 B) 400, 600, 200
C) 600, 200, 400 D) 400, 200, 600
 
Answer & Explanation Answer: A) 200, 600, 400

Explanation:

Ratio of efficiencies of P, Q and R = 2 : 3 : 4

From the given data,

Number of working days of P, Q, R = 5 : 10 : 5

Hence, ratio of amount of p, Q, R = 2x5 : 3x10 : 4x5 = 10 : 30 : 20

Amounts of P, Q, R = 200, 600 and 400.

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Q:

A man can row upstream at 16 km/hr and downstream at 24 km/hr. Find the speed of the current.

A) 4 kmph B) 6 kmph
C) 5 kmph D) 3 kmph
 
Answer & Explanation Answer: A) 4 kmph

Explanation:

Speed of the current = 24-16/2

= 8/2

= 4 km/hr.

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Q:

The Present worth of Rs.2310 due 212 years hence ,the rate of interest being 15% per annum, is :

A) Rs.1440 B) Rs.1750
C) Rs.1680 D) Rs.1840
 
Answer & Explanation Answer: C) Rs.1680

Explanation:

P.W=Rs.100×2310100+15×52 = Rs.1680

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Q:

A man can row against the current three fourth of a kilometer in 15 min and returns same distance in 10 min, then ratio of his speed to that of current?

A) 5:1 B) 3:1
C) 4:1 D) 2:1
 
Answer & Explanation Answer: A) 5:1

Explanation:

Let the speed of the man in still water = p kmph

Speed of the current = s kmph

Now, according to the questions

(p + s) x 10 = (p - s) x 15

2p + 2s = 3p - 3s

=> p : s = 5 : 1

 

Hence, ratio of his speed to that of current = 5:1.

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Q:

A jogger running at 9 km/hr along side a railway track is 260 m ahead of the engine of a 140 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger ?

A) 25 sec B) 40 sec
C) 38 sec D) 32 sec
 
Answer & Explanation Answer: B) 40 sec

Explanation:

Speed of train relative to jogger = 45 - 9 = 36 km/hr.
= 36 x 5/18 = 10 m/sec.

Distance to be covered = 260 + 140 = 400 m.

Time taken = 400/10 = 40 sec.

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Q:

Three taps I, J and K can fill a tank in 20,30and 40 minutes respectively. All the taps are opened simultaneously and after 5 minutes tap A was closed and then after 6 minutes tab B was closed .At the moment a leak developed which can empty the full tank in 70 minutes. What is the total time taken for the completely full ?

A) 24.315 minutes B) 26.166 minutes
C) 22.154 minutes D) 24 minutes
 
Answer & Explanation Answer: B) 26.166 minutes

Explanation:

Upto first 5 minutes I, J and K will fill => 5[(1/20)+(1/30)+(1/40)] = 65/120


For next 6 minutes, J and K will fill => 6[(1/30)+(1/40)] = 42/120


So tank filled upto first 11 minutes = (65/120) + (42/120) = 107/120
So remaining tank = 13/120


Now at the moment filling with C and leakage @ 1/60 per minute= (1/40) - (1/70) = 3/280.
So time taken to fill remaining 13/120 tank =(13/120) /(3/280) = 91/6 minutes

 

Hence total time taken to completely fill the tank = 5 + 6 + 91/6 = 26.16 minutes.

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