6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Two trains namely X & Y leave station 'A' at 6.30am and 7.40am and travel at 30km/hr and 40 km/hr respectively. How many kms from 'A' will the trains meet ?

A) 140 kms	B) 120 kms
C) 96 kms	D) 142 kms

Answer & Explanation Answer: A) 140 kms

Explanation:

It is given train X leave station A at 6:30 am, here it is asked to calculate the distance from A when the trains meet, the
Distance traveled by train left at 6:30 am upto 7:40 am i.e. in 1 hr. 10 min. or 7/6 hours = 30 x 7/6 = 35 km
So train leaving at 7:40 am will meet first train after covering a distance of 35 km. with relative speed of 40-30=10 km/hr.
Hence time taken = 35/10 = 3.5 hours or 3 hours 30 minutes
So distance from A = Distance traveled by 2nd train in 3 hr. 30 min
= 40 x 3.5 = 140 km.

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Filed Under: Problems on Trains
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15 9236

Q:

Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

A) 648	B) 1800
C) 2700	D) 10800

Answer & Explanation Answer: B) 1800

Explanation:

Let the required number of bottles be x.

More machines, More bottles (Direct Proportion)

More minutes, More bottles (Direct Proportion)

$\begin{array}{r} \begin{matrix} m a c h i n e s & 6 : 10 \end{matrix} \\ \begin{matrix} t i m e (i n m i n) & 1 : 4 \end{matrix} \end{array}\} ⋮ ⋮ 270 : x$

=> 6 * 1 * x = 10 * 4 * 270

=> x= 1800

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Filed Under: Chain Rule

3 9231

Q:

If $\frac{a}{b} = \frac{4}{5}$ and $\frac{b}{c} = \frac{15}{16}$ , then $\frac{c^{2} - a^{2}}{c^{2} + a^{2}}$ is :

A) 7/5	B) 7/25
C) 7/125	D) 7

Answer & Explanation Answer: B) 7/25

Explanation:

$\frac{a}{b} \times \frac{b}{c} = \frac{4}{5} \times \frac{15}{16} = \frac{3}{4} = \frac{16 - 9}{16 + 9}$

= $\frac{7}{25}$

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Filed Under: Simplification

7 9231

Q:

There is an empty reservoir whose capacity is 30 litres. There is an inlet pipe which fills at 5 L/min and there is an outlet pipe which empties at 4 L/min. Both the pipes function alternately for 1 minute. Assuming that the inlet pipe is the first one to function, how much time will it take for the reservoir to be filled up to its capacity?

A) 49.5 min	B) 50 min
C) 51 min	D) 52 min

Answer & Explanation Answer: C) 51 min

Explanation:

The work to be done = Capacity of reservoir = 30 litres.

1^st Minute ---> inlet pipe opened ---> 5 lit filled

2^nd minute ---> inlet pipe closed; outlet pipe opened ---> 4 lit emptied

In 2 minutes (5 litres - 4 litres = 1lit) is filled into the reservoir.

It takes 2 minutes to fill 1lit ---> it takes 50 minutes to fill 25 litres into the reservoir.

In the 51^st minute inlet pipe is opened and the reservoir is filled.

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Filed Under: Pipes and Cistern
Exam Prep: CAT
Job Role: Bank PO

24 9223

Q:

A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken ?

A) 4/3 hrs	B) 2/3 hrs
C) 3/2 hrs	D) 1/4 hrs

Answer & Explanation Answer: B) 2/3 hrs

Explanation:

Let the original speed and time is S and T
then distance = S x T
Now the speed changes to 2/3S and T is T+20
As the distance is same
S x T = 2/3Sx(T+20)
solving this we get t = 40 minutes
=40/60 = 2/3 hour

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5 9216

Q:

A man sells Rs.5000, 12 % stock at 156 and uinvests the proceeds parity in 8 % stock at 90 and 9 % stock at 108. He hereby increases his income by Rs. 70. How much of the proceeds were invested in each stock?

A) 4000	B) 4200
C) 4002	D) 4020

Answer & Explanation Answer: B) 4200

Explanation:

S.P of Rs. 5000 stock = $R s . (\frac{156}{100} * 5000)$ = Rs. 7800.

Income from this stock = $R s . (\frac{12}{100} * 5000)$ = Rs. 600.

Let investment in 8 % stock be x and that in 9 % stock = (7800 - x).

Therefore,

$(x * \frac{8}{90}) + (7800 - x) * \frac{9}{108} = [600 + 70]$

$\frac{4 x}{45} + \frac{7800 - x}{12} = 670 \Leftrightarrow x = 3600$

Therefore, Money invested in 8 % stock at 90 = Rs. 3600.

Money invested in 9 % at 108 = Rs. (7800-3600) = Rs. 4200.

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Filed Under: Stocks and Shares

14 9213

Q:

Rs. 7444 is divided among 5 ladies, 3 gents and 3 girls. The ratio of share of a lady, a gents and a girl is 7: 4: 3. What is the share of gents ?

A) Rs. 1595.14	B) Rs. 1793.4
C) Rs. 595.14	D) Rs. 1551.5

Answer & Explanation Answer: A) Rs. 1595.14

Explanation:

Ratio of the share of a lady, a gents and a girl is 7 : 4 : 3
No of ladies, gents and girls are 5, 3, 3
Thus effective ratio of ladies, gents and girls is 7 x 5 : 4 x 3 : 3 x 3 = 35 : 12 : 9
so part of gents = (12/56) x 7444 = Rs. 1595.142
so part of 1 gents = 1595.142/3 = Rs. 531.71.

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Filed Under: Ratios and Proportions
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9 9211

Q:

When the price of whear was increased by 32%, a family reduced its consumption in such a way that the expenditure on wheat was only 10% more than before. If 30 kg per month were consumed before, find the new monthly consumption of family?

A) 27 kgs	B) 25 kgs
C) 24 kgs	D) 21 kgs

Answer & Explanation Answer: B) 25 kgs

Explanation:

Initial wheat per kg cost be Rs. 100

Then, monthly expenditure of the family = 30 x 100 = 3000

After increase in cost,

Let P be new monthly consumption of family.

P x 132 = 110/100 x 3000

=> P = 25 kg.

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Filed Under: Percentage
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7 9202

Quantitative Aptitude - Arithmetic Ability Questions

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