6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm, What portion of the block is immersed in the fluid ?

A) 22/7 x 24/35	B) 22/7 x 36 x 4
C) 22/7 x 36/5	D) 22/7 x 37/21

Answer & Explanation Answer: A) 22/7 x 24/35

Explanation:

Since level of water increased in cylinder by height 4.

This is because of the rectangular block .

Therefore , area of rectangular block immersed in water is

= $\frac{22}{7} \times 6 \times 6 \times 4$

Thats why portion of block immersed in water is

= (22/7 * 36 * 4) / total vol. of rectangle

= (22/7 * 36 * 4)/ (7*5*6)

= (22/7 * 24)/ 35.

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Filed Under: Volume and Surface Area
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
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7 9066

Q:

Half the people on a bus get off at each stop after the first, and no one gets on after the first stop. If only one person gets off at stop number 7, how many people got on at the first stop?

A) 128	B) 64
C) 32	D) 16

Answer & Explanation Answer: B) 64

Explanation:

7th stop only one was left and in each preceding stop twice the nos... there were so 6 stops before 7th.

so $2^{6} = 64$

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Filed Under: Problems on Numbers
Exam Prep: GRE

6 9060

Q:

A rectangular box measures internally 1.6m long, 1m broad and 60cm deep. The number of cubical box each of edge 20cm that can be packed inside the box is:

A) 30	B) 60
C) 90	D) 120

Answer & Explanation Answer: D) 120

Explanation:

Number of blocks = $(\frac{160 \times 100 \times 60}{20 \times 20 \times 20})$ =120

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams
Job Role: Bank PO

10 9048

Q:

A boat while travelling upstream covers a distance of 29 km at the speed of 6 km/h, whereas while travelling downstream it covers the same distance at a speed of 12 km/h. What is the speed of the boat in still water?

A) 6 kmph	B) 8 kmph
C) 9 kmph	D) 11 kmph

Answer & Explanation Answer: C) 9 kmph

Explanation:

Speed of boat in still water = 1/2 (12 + 6) = 9 kmph.

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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10 9047

Q:

Ramu rides his bike at an average speed of 45 km/hr and reaches his desitination in four hours. Somu covers the same distance in six hours. If Ramu covered his journey at an average speed which was 9 km/hr less and Somu covered his journey at an average speed which was 10 km/hr more, then the difference in their times taken to reach the destination would be (in minutes).

A) 18 min	B) 30 min
C) 27 min	D) 32 min

Answer & Explanation Answer: B) 30 min

Explanation:

Distance travelled by Ramu = 45 x 4 = 180 km

Somu travelled the same distance in 6 hours.

His speed = 180/6 = 30 km/hr

Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 30 + 10 = 40km/hr.

Therefore travel time of Ramu and Somu would be 5 hours and 4.5 hours respectively.

Hence difference in the time taken = 0.5 hours = 30 minutes.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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6 9033

Q:

A tin a mixture of two liquids A and B in the proportion 4 : 1. If 45 litres of the mixture is replaced by 45 litres of liquid B, then the ratio of the two liquids becomes 2 : 5. How much of the liquid B was there in the tin? What quantity does the tin hold?

A) 58 l	B) 65 l
C) 50 l	D) 62 l

Answer & Explanation Answer: C) 50 l

Explanation:

Let the tin contain 5x litres of liquids

$\frac{(5 x - 45) x \frac{4}{5}}{(5 x - 45) x \frac{1}{5} + 45} = \frac{2}{5}$

=> 5(4x - 36) = 2(x + 36)

=> 20x - 180 = 2x + 72

=> x = 14 litres

Hence, the initial quantity of mixture = 70l

Quantity of liquid B

= $(70 - 45) x \frac{1}{5} + 45$

= 50 litres.

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Filed Under: Alligation or Mixture
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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29 9011

Q:

A bill for Rs. 6000 is drawn on July 14 at 5 months. It is discounted on 5th October at 10%. Find the banker's discount, true discount, banker's gain and the money that the holder of the bill receives.

A) 4390	B) 6580
C) 5880	D) 5350

Answer & Explanation Answer: C) 5880

Explanation:

Face value of the bill = Rs. 6000.

Date on which the bill was drawn = July 14 at 5 months. Nominally due date = December 14.

Legally due date = December 17.

Date on which the bill was discounted = October 5.

Unexpired time : Oct. Nov. Dec.

26 + 30 + 17 = 73 days =1/ 5Years

B.D. = S.I. on Rs. 6000 for 1/5 year

= Rs. (6000 x 10 x1/5 x1/100)= Rs. 120.

T.D. = Rs.[(6000 x 10 x1/5)/(100+(10*1/5))]

=Rs.(12000/102)=Rs. 117.64.

B.G. = (B.D.) - (T.D.) = Rs. (120 - 117.64) = Rs. 2.36.

Money received by the holder of the bill = Rs. (6000 - 120) = Rs. 5880.

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Filed Under: Banker's Discount

5 9008

Q:

The diagonal of the floor of a rectangular closet is $7 \frac{1}{2}$ feet. The shorter side of the closet is $4 \frac{1}{2}$ feet. What is the area of the closet in square feet?

A) 5 .5	B) 13.5
C) 27	D) 37

Answer & Explanation Answer: C) 27

Explanation:

Other side= $\sqrt{[{(\frac{15}{2})}^{2} - (\frac{9^{2}}{2})]} f t$ = $\sqrt{\frac{225}{4} - \frac{81}{4}} f t$ = $\sqrt{\frac{144}{4}}$ = 6ft

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