6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

An alloy contains gold and silver in the ratio 5 : 8 and another alloy contains gold and silver in the ratio 5 : 3. If equal amount of both the alloys are melted together, then the ratio of gold and silver in the resulting alloy is ?

A) 113/108	B) 105/103
C) 108/115	D) 103/113

Answer & Explanation Answer: B) 105/103

Explanation:

As given equal amounts of alloys are melted, let it be 1 kg.

Required ratio of gold and silver = $\frac{\frac{5}{13} + \frac{5}{8}}{\frac{8}{13} + \frac{3}{8}} = \frac{105}{103} .$

Hence, ratio of gold and silver in the resulting alloy = 105/103.

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Filed Under: Alligation or Mixture
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15 8407

Q:

A sector of 120, cut out from a circle, has an area of $\frac{66}{7} c m^{2}$ . Find the radius of the circle ?

A) 1	B) 2
C) 3	D) 4

Answer & Explanation Answer: C) 3

Explanation:

Let the radius of the circle be r cm. Then,

$\frac{120}{360} {πr}^{2} = \frac{66}{7}$

$r^{2} = \frac{66}{7} * \frac{7}{22} * 3$

r=3.

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Filed Under: Area
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2 8404

Q:

In an election between two candidates K and L, the number of valid votes received by K exceeds those received by L by 15% of the total number of votes polled. If 20% of the votes polled were invalid and a total of 8720 votes were polled, then how many valid votes did L get ?

A) 3241	B) 2457
C) 2642	D) 2834

Answer & Explanation Answer: D) 2834

Explanation:

Let the total number of votes polled in the election be 100k.
Number of valid votes = 100k - 20% (100k) = 80k
Let the number of votes polled in favour of K and L be a and b respectively.
a - b = 15% (100k) => a = b + 15k
=> a + b = b + 15k + b
Now, 2b + 15k = 80k and hence b = 32.5k
It is given that 100k = 8720
32.5k = 32.5k/100k x 8720 = 2834

The number of valid votes polled in favour of L is 2834.

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Filed Under: Percentage
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7 8397

Q:

Find the odd one out of the group ?

A) 708	B) 392
C) 618	D) 816

Answer & Explanation Answer: B) 392

Explanation:

The sum of the digits in 708, 618 and 816 is 15, but not in 392.

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Filed Under: Odd Man Out
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8 8379

Q:

The average age of a couple was 26 years at the time of marriage. After 11 years of marriage, the average age of the family with 3 children become 19 years. The average age of the children is

Answer

The average age of a couple = 26 years.

Total age of couples = 26 x 2 = 52 years

$\therefore$ Total age of couple after 11 years = (52 + 2 * 11 ) = 74 years

Suppose average age of 3 children after 11 years is 3x years.

$\Rightarrow \frac{74+3x}{5}=19 \Rightarrow x=7$

The average age of children is 7 years.

Workspace

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Subject: Problems on Ages

10 8376

Q:

Two pipes A and B can separately fill a cistern in 60 min and 75 min respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 min. In how much time, the third pipe alone can empty the cistern ?

A) 85 min	B) 95 min
C) 105 min	D) 100 min

Answer & Explanation Answer: D) 100 min

Explanation:

Work done by the third pipe in 1 min = 1/50 - (1/60 + 1/75) = - 1/100.
[-ve sign means emptying]

The third pipe alone can empty the cistern in 100 min.

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7 8372

Q:

A rectangular grassy plot 120 m. by 60 m has a gravel path 1.5 m wide all round it on the inside. Find the cost of gravelling the path at 65 paise per sq. metre ?

A) Rs. 345.15	B) Rs. 245.1
C) Rs. 234.18	D) Rs. 456.65

Answer & Explanation Answer: A) Rs. 345.15

Explanation:

area of the plot = 120m x 60m = 7200 sq.m
area of plot excluding gravel = 117m x 57m = 6669 sq.m
area of gravel = 7200 sq.m - 6669 sq.m = 531 sq.m
cost of building it = 531 sq.m x 65 ps = 34515 ps
In Rs. = 34515/100 = Rs. 345.15.

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Filed Under: Area
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4 8363

Q:

In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ?

A) 2101 hrs	B) 4125 hrs
C) 5124 hrs	D) 6011 hrs

Answer & Explanation Answer: D) 6011 hrs

Explanation:

From March 6th to November 11th,
there are 250 days and
Thus 250 x 24 hours
So from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.

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Filed Under: Calendar
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27 8356

Quantitative Aptitude - Arithmetic Ability Questions

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