Quantitative Aptitude - Arithmetic Ability Questions

Q:

What is the equivalent compound ratio of 5:6::7:10::6:5  ?

A) 7 : 9 B) 9 : 7
C) 7 : 4 D) 7 : 10
 
Answer & Explanation Answer: D) 7 : 10

Explanation:

Given 5:6 :: 7:10 :: 6:5

We know that compound ratio is calculated as
a:b :: c:d :: e:f
(axcxe):(bxdxf)

=> (5x7x6):(6x10x5)
=> (210):(300)
= 7:10

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Filed Under: Ratios and Proportions
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11 8251
Q:

A motorboat goes 8 km an hour in still water, but takes thrice as much time in going the same distance against the current than going with the current. Then find the speed of the current?

A) 4 kmph B) 6 kmph
C) 3 kmph D) 2 kmph
 
Answer & Explanation Answer: A) 4 kmph

Explanation:

Let the speed of current = 'C' km/hr

 

Given the speed of boat in still water = 6 kmph

 

Let 'd' kms be the distance it covers.

 

According to the given data,

 

Boat takes thrice as much time in going the same distance against the current than going with the current

 

i.e, d8 - C = 3 × d8 + C

 

 24 - 3C = 8 + C 4C = 16 C = 4 kmph

 

Hence, the speed of the current C = 4 kmph.

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Filed Under: Boats and Streams
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9 8247
Q:

30% of 500 rupees is?

A) Rs. 180 B) Rs. 150
C) Rs. 120 D) Rs. 240
 
Answer & Explanation Answer: B) Rs. 150

Explanation:

Given 30% of 500

= 30100 x 500= 30 x 5= 150

 

Hence, 30% of Rs. 500 = Rs. 150.

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Filed Under: Percentage
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19 8243
Q:

In how many ways can you choose one or more of 12 different candies?

A) 4054 B) 4050
C) 4095 D) 4059
 
Answer & Explanation Answer: C) 4095

Explanation:

Each candy can be dealt with in two ways.It can be chosen or not chosen.This will give 2 possibilites for the first candy, 2 for the second, and so on.by multiplying the cases together we get 212. Since the case of no candy being selected is not an option, we have to subtract 1 from our answer.

 

Therefore,there are 212- 1 = 4095 ways of selecting one or more candies

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0 8242
Q:

Three graziers A,B and C rent a piece of pasture for a month. A puts in 27 cattle for 19 days, B 21 for 17 days and C 24 for 23 days. If at the end of the month the rent amount to Rs.237, how much ought to be paid by each.

Answer

A's cattle = 27 x 19 = 513


B's cattle = 21 x 17 = 357


C's cattle = 24 x 23 = 552


Ratio of cattle = 513 : 357 : 552


                    = 171 : 119 : 184


 


payment to be made by A = \inline 237\times \frac{171}{474}


                                     = Rs.85.50


payment to be made by B = \inline 237\times \frac{119}{474}


                                     = Rs.59.50


payment to be made by C = \inline 237\times \frac{184}{474}


                                     = Rs.92

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Subject: Partnership

7 8239
Q:

Robert is traveling on his cycle and has calculated to reach point A at 2 p.m. if he travels at 10 km/hr; he will reach there at 12 noon if he travels at 15 km/hr. At what speed must he travel to reach A at 1 p.m. ?

A) 20 kmph B) 18 kmph
C) 12 kmph D) 16 kmph
 
Answer & Explanation Answer: C) 12 kmph

Explanation:

Let the distance traveled be x km.
Then, x/10 - x/15 = 2
3x - 2x = 60 => x = 60 km.
Time taken to travel 60 km at 10 km/hr = 60/10 = 6 hrs.
So, Robert started 6 hours before 2. p.m. i.e., at 8 a.m.
Required speed = 60/5 = 12 kmph.

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Filed Under: Time and Distance
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7 8238
Q:

A person starting with 64 rupees and making 6 bets, wins three times and loses three times, the wins and loses occurring in random order. The chance for a win is equal to the chance for a loss. If each wager is for half the money remaining at the time of the bet, then the final result is:

A) A gain of Rs. 27 B) A loss of Rs. 37
C) A loss of Rs. 27 D) A gain of Rs. 37
 
Answer & Explanation Answer: B) A loss of Rs. 37

Explanation:

As the win leads to multiplying the amount by 1.5 and loss leads to multiplying the amount by 0.5, we will multiply the initial amount by 1.5 thrice and by 0.5 thrice (in any order).

The overall resultant will remain same.

So final amount with the person will be (in all cases):

64(1.5)(1.5)(1.5)(0.5)(0.5)(0.5)= Rs. 27

Hence the final result is: 

64 − 27 37

A loss of Rs.37

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Filed Under: Probability
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22 8229
Q:

A laborer is engaged for 30 days on the condition that he receives Rs.25 for each day he works and is fined Rs.7.50 for each day is absent. He gets Rs.425 in all. For how many days was he absent ?

A) 10 days B) 14 days
C) 11 days D) 9 days
 
Answer & Explanation Answer: A) 10 days

Explanation:

For 30 days he receives

30 x 25 = 750
               

Actually he gets 425

Therefore, Fine is 750 - 425 =  325

 

=> No of days absent = 325/(25+7.50)= 10

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Filed Under: Time and Work
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5 8225