6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of the father of the younger boy. Similarly, we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divide the figure by 2, we get the age of the mother of the younger boy. The mother of the younger boy is younger than his father by 3 years. Then, what are the ages of elder and younger boys ?

A) E = 15 & Y = 3	B) E = 14 & Y = 12
C) E = 40 & Y = 22	D) E = 4 & Y = 2

Answer & Explanation Answer: D) E = 4 & Y = 2

Explanation:

Let the the age of the elder boy = E

Let the the age of the younger boy = Y

Given that Y = cube root of EY

=> $Y^{3}$ = EY => E = $Y^{2}$ .....(1)
By the condition of number replacement the age of the father is YE

The Mother's age = EY/2

But she is 3 years less than father => EY/2 + 3 = YE
2YE = EY + 6 ......(2)

Then now from the given options we can identify which satisfies the all the conditions.

Here Y =2 and E = 4 satisfies all the conditions.

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Filed Under: Problems on Ages
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8 8329

Q:

A sum of Rs. 731 is divided among A,B and C, such that 'A' receives 255 more than 'B' and 'B' receives 25% less than 'C'. What is 'C' s share in the amount?

A) Rs.172	B) Rs.200
C) Rs.262	D) None of these

Answer & Explanation Answer: D) None of these

Explanation:

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
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19 8327

Q:

Avanthi’s age is 1/6th of her father’s age. Her father’s age will be twice of Kapil’s age after 10 years. If Kapil’s eighth birthday was celebrated two years ago, then what is Avanthi’s present age ?

A) 6 years	B) 4 years
C) 7 years	D) None

Answer & Explanation Answer: D) None

Explanation:

As given Kapil's 8th birthday was celebrated 2 years ago,

Kapil’s present age = 8 + 2 = 10 years.

Father's age is twice of Kapil’s age after 10 years.
=> F + 10 = 2 (K + 10) = 2 (10+ 10)
F = 30years,

Avanthi's age =1/6(F) = 30/6 = 5 years.

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Filed Under: Problems on Ages
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10 8325

Q:

The volume of a rectangular solid is to be increased by 50% without altering its base. To what extent the height of the solid must be changed.

A) 50%	B) 40%
C) 30%	D) 20%

Answer & Explanation Answer: A) 50%

Explanation:

Let l, b the sides of the base, so that the area of the base = lb
remains constant.
Let ‘h’ be the height of the solid.
Volume of the solid, V = l× b× h.
Since the volume is to be increased by 50%

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Filed Under: Volume and Surface Area
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8 8298

Q:

640 ml of a mixture contains milk and water in ratio 6:2. How much of the water is to be added to get a new mixture containing half milk and half water ?

A) 360 ml	B) 320 ml
C) 310 ml	D) 330 ml

Answer & Explanation Answer: B) 320 ml

Explanation:

Here total parts of milk and water in the solution is 6+2 = 8 parts.

1part = 640/8 = 80

old mixture contains 6parts of milk and 2 parts of water(6:2).

To get new mixture containing half milk and half water, add 4parts of water to the old mixture then 6:(2+4) to make the ratio same.

i.e, 4 x 80 = 320 ml.

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Filed Under: Alligation or Mixture
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9 8297

Q:

If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. What is the sum of the digits of N ?

A) 6	B) 8
C) 4	D) 9

Answer & Explanation Answer: C) 4

Explanation:

N = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305)

= H.C.F. of 3360, 2240 and 5600 = 1120.

Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4

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Filed Under: HCF and LCM
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17 8272

Q:

From a container of wine, a thief has stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus, in three attempts the ratio of wine and water became 343 : 169. The initial amount of wine in the container was:

A) 75 litres	B) 100 litres
C) 150 litres	D) 120 litres

Answer & Explanation Answer: D) 120 litres

Explanation:

$\frac{w i n e (l e f t)}{w i n e (a d d e d)} = \frac{343}{169}$

It means $\frac{w i n e (l e f t)}{w i n e (i n i t i a l a m o u n t)} = \frac{343}{512}$ (since 343 + 169 = 512)

Thus, $343 x = 512 x {(1 - \frac{15}{k})}^{3}$

$\frac{343}{512} = {(\frac{7}{8})}^{3} = {(1 - \frac{15}{k})}^{3}$

$(1 - \frac{15}{k}) = \frac{7}{8} = (1 - \frac{1}{8})$

Thus the initial amount of wine was 120 liters.

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Filed Under: Alligation or Mixture
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29 8270

Q:

The calendar for the year 2013 was the same as the year :

A) 1998	B) 2017
C) 2009	D) 2002

Answer & Explanation Answer: D) 2002

Explanation:

Given year, 2013 when divided by 4 leaves a remainder of 1.

NOTE: When the remainder is 1, 11 is substracted from the given year to get the result.

So, 2013 - 11 =2002

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Filed Under: Calendar

13 8267

Quantitative Aptitude - Arithmetic Ability Questions

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