6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

From a container of wine, a thief has stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus, in three attempts the ratio of wine and water became 343 : 169. The initial amount of wine in the container was:

A) 75 litres	B) 100 litres
C) 150 litres	D) 120 litres

Answer & Explanation Answer: D) 120 litres

Explanation:

$\frac{w i n e (l e f t)}{w i n e (a d d e d)} = \frac{343}{169}$

It means $\frac{w i n e (l e f t)}{w i n e (i n i t i a l a m o u n t)} = \frac{343}{512}$ (since 343 + 169 = 512)

Thus, $343 x = 512 x {(1 - \frac{15}{k})}^{3}$

$\frac{343}{512} = {(\frac{7}{8})}^{3} = {(1 - \frac{15}{k})}^{3}$

$(1 - \frac{15}{k}) = \frac{7}{8} = (1 - \frac{1}{8})$

Thus the initial amount of wine was 120 liters.

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Filed Under: Alligation or Mixture
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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29 8319

Q:

A fast moving superfast express crosses another pasenger train in 20 seconds. The speed of faster train is 72 km/hr and speeds of slower train is 27 km/h. Also the length of faster ntrain is 100m, then find the length of the slower train if they are moving in the same direction.

A) 100 m	B) 125 m
C) 150 m	D) 175 m

Answer & Explanation Answer: C) 150 m

Explanation:

$T i m e = \frac{S u m o f l e n g t h o f t h e t w o t r a i n s}{D i f f e r e n c e i n s p e e d s}$

$20 = \frac{(100 + x)}{\frac{25}{2}}$

$\Rightarrow$ X=150m

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Filed Under: Logarithms

45 8308

Q:

In how many different ways can 6 different balls be distributed to 4 different boxes, when each box can hold any number of ball?

A) 2048	B) 1296
C) 4096	D) 576

Answer & Explanation Answer: C) 4096

Explanation:

Every ball can be distributed in 4 ways.

Hence the required number of ways = 4 x 4 x 4 x 4 x 4 x 4 = 4096

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Filed Under: Permutations and Combinations

0 8300

Q:

If sum of upstream and downstream speed of a boat is 82 kmph, and the boat travels 105 km. upstream in 3 hr, Find the time taken by boat to cover 126 km downstream.

A) 2.8 hrs	B) 2.7 hrs
C) 2.6 hrs	D) 2.5 hrs

Answer & Explanation Answer: B) 2.7 hrs

Explanation:

Let Speed of boat in still water = b

Let Speed of still water = w

Then we know that,

Speed of Upstream = U = boat - water

Speed of Downstream = D = boat + water

Given, U + D = 82

b - w + b + w = 82

2b = 82

=> b = 41 kmph

From the given data,

41 - w = 105/3 = 35

w = 6 kmph

Now,

b + w = 126/t

=> 41 + 6 = 126/t

=> t = 126/47 = 2.68 hrs.

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Filed Under: Boats and Streams
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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21 8296

Q:

P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?

A) 99	B) 100
C) 89	D) 1

Answer & Explanation Answer: A) 99

Explanation:

Let, Distance between A and B = d

Distance travelled by P while it meets Q = d + 11

Distance travelled by Q while it meets P = d – 11

Distance travelled by Q while it meets R = d + 9

Distance travelled by R while it meets Q = d – 9

Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11

The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9

But given Ratio of speeds of P & R => P : R = 3 : 2

$\frac{S P}{S R} = \frac{S P}{S Q} x \frac{S Q}{S R} = \frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$

=> $\frac{(d + 11) (d + 9)}{(d - 11) (d - 9)}$ = 3/2

=> d = 1, 99

=> d = 99 satisfies.

Therefore, Distance between A and B = 99

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Filed Under: Time and Distance
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

16 8292

Q:

The value of $\sqrt{10 + \sqrt{25 + \sqrt{108 + \sqrt{154 + \sqrt{225}}}}}$ is:

A) 4	B) 6
C) 8	D) 10

Answer & Explanation Answer: A) 4

Explanation:

$\sqrt{10 + \sqrt{25 + \sqrt{108 + \sqrt{154 + \sqrt{225}}}}} \sqrt{10 + \sqrt{25 + \sqrt{108 + \sqrt{154 + 15}}}} \sqrt{10 + \sqrt{25 + \sqrt{108 + 13}}} \sqrt{10 + \sqrt{25 + 11}} \sqrt{10 + 6} \sqrt{16} = 4$

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Filed Under: Square Roots and Cube Roots
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Analyst , Bank Clerk , Bank PO

29 8290

Q:

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated ?

A) 15	B) 20
C) 5	D) 10

Answer & Explanation Answer: B) 20

Explanation:

Since each number to be divisible by 5, we must have 5 0r 0 at the units place. But in given digits we have only 5.

So, there is one way of doing it.

Tens place can be filled by any of the remaining 5 numbers.So, there are 5 ways of filling the tens place.

The hundreds place can now be filled by any of the remaining 4 digits. So, there are 4 ways of filling it.

Required number of numbers = (1 x 5 x 4) = 20.

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Filed Under: Permutations and Combinations
Exam Prep: GATE , CAT , Bank Exams
Job Role: Project Manager , Bank PO , Bank Clerk

12 8289

Q:

The calendar of the year 2006 was used before in the year?

A) 1990	B) 1995
C) 2002	D) 2000

Answer & Explanation Answer: B) 1995

Explanation:

Given year 2006, when divided by 4 leaves a remainder of 2.

NOTE: When remainder is 2, 11 is subtracted to the given year to get the result.

So, 2006 - 11 = 1995

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Filed Under: Calendar

7 8285

Quantitative Aptitude - Arithmetic Ability Questions

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