6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Two motor bikes cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower bike takes 1 hour more than the faster bike ?

A) 1102 km	B) 1060 km
C) 960 km	D) 1250 km

Answer & Explanation Answer: C) 960 km

Explanation:

60(x + 1) = 64x

X = 15

60 x 16 = 960 km

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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7 7922

Q:

The value of $\sqrt{10 + \sqrt{25 + \sqrt{108 + \sqrt{154 + \sqrt{225}}}}}$ is:

A) 4	B) 6
C) 8	D) 10

Answer & Explanation Answer: A) 4

Explanation:

$\sqrt{10 + \sqrt{25 + \sqrt{108 + \sqrt{154 + \sqrt{225}}}}} \sqrt{10 + \sqrt{25 + \sqrt{108 + \sqrt{154 + 15}}}} \sqrt{10 + \sqrt{25 + \sqrt{108 + 13}}} \sqrt{10 + \sqrt{25 + 11}} \sqrt{10 + 6} \sqrt{16} = 4$

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Filed Under: Square Roots and Cube Roots
Exam Prep: AIEEE , Bank Exams , CAT
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29 7919

Q:

A box contains 90 screws each of 100 gms and 100 bolts each of 150 gms. If the entire box weighs 35.5 kg, then the weight of the empty box is ?

A) 10.5 kgs	B) 12 kgs
C) 9.6 kgs	D) 11.5 kgs

Answer & Explanation Answer: D) 11.5 kgs

Explanation:

Screws weight = 90x100 = 9000gms
bolts weight = 100 x 150 = 15000gms
weight = screws + bolts => 24000 gms =>24 kg
Given entire box weight = 35.5kg
empty box = entire box weight - weight => 35.5kg - 24kg => 11.5kg
so the empty box is 11.5kg.

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Filed Under: Numbers
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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8 7919

Q:

A person travels from K to L a speed of 50 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ?

A) 55 kmph	B) 58 kmph
C) 60 kmph	D) 66 kmph

Answer & Explanation Answer: C) 60 kmph

Explanation:

Speed on return trip = 150% of 50 = 75 km/hr.

Average speed = (2 x 50 x 75)/(50 + 75) = 60 km/hr.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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4 7912

Q:

The bankers discount and the true discount of a sum at 10% per annum simple interest for the same time are Rs.100 and Rs.80 respectively. What is the sum and the time?

A) Sum = Rs.400 and Time = 5 years	B) Sum = Rs.200 and Time = 2.5 years
C) Sum = Rs.400 and Time = 2.5 years	D) Sum = Rs.200 and Time = 5 years

Answer & Explanation Answer: C) Sum = Rs.400 and Time = 2.5 years

Explanation:

BD = Rs.100

TD = Rs.80

R = 10%

$F = \frac{B D \times T D}{B D - T D} = \frac{100 \times 80}{100 - 80} = R s . 400$

BD = Simple interest on the face value of the bill for unexpired time= FTR/100

$\Rightarrow 100 = \frac{400 \times T \times 10}{100}$

=> T = 2.5 years

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Filed Under: Banker's Discount

4 7911

Q:

A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ?

A) 45	B) 24
C) 42	D) 54

Answer & Explanation Answer: D) 54

Explanation:

By trial and error method from the given options,

as 54 - 45 = (1/11) x (45+54) = 99/11 = 9

Hence this satisfies the given conditions.

Then the woman's husband age is 54.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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10 7909

Q:

One third of a Number is 96. What will 67% of that Number be?

A) 192.96	B) 181.44
C) 169.92	D) 204.48

Answer & Explanation Answer: A) 192.96

Explanation:

Let the Number be x.

Given that one third of a Number is 96.

i.e x = 3 x 96 = 288.

67% of x = $\frac{x \times 67}{100} = \frac{288 \times 67}{100} = 192.96$

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

3 7900

Q:

A jar was full with honey. A person used to draw out 20% of the honey from the jar and replaced it with sugar solution. He has repeated the same process 4 times and thus there was only 512 gm of honey left in the jar, the rest part of the jar was filled with the sugar solution. The initial amount of honey in the jar was:

A) 1.25 kg	B) 1 kg
C) 1.5 kg	D) None of these

Answer & Explanation Answer: A) 1.25 kg

Explanation:

Let the initial amount of honey in the jar was k, then

$512 = k {(1 - \frac{1}{5})}^{4} o r 512 = k {(\frac{4}{5})}^{4}$

=> $k = \frac{512 \times 625}{256}$

=> k = 1250

Hence initially the honey in the jar = 1.25 kg

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Filed Under: Alligation or Mixture
Exam Prep: CAT , Bank Exams , AIEEE
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23 7890

Quantitative Aptitude - Arithmetic Ability Questions

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