Quantitative Aptitude - Arithmetic Ability Questions

Concentration of glucose are in the ratio = 12:35:45

Quantity of glucose taken from A = 1 liter out of 2

Quantity of glucose taken from B = 3/5 x 3 = 1.5 lit

Quantity of glucose taken from C = 0.8 lit

So, total quantity of glucose taken from A,B and C = 3.6 lit

So, quantity of alcohol = (2 + 3 + 1) - 3.6 = 2.4 lit

Ratio of glucose to alcohol = 3.6/2.4 = 3:2

Let the Cost of Production of the article = 100

Then, Labour Cost = 20

Raw Material = 10

Other Expenditure = 100 - 10 – 20 = 70

Selling Price of the article  = 120

After increasing Labour and Raw material cost by 40% & 20% respectively,

New Labour cost = 28

New Raw material cost = 12

New Cost of Production = 70 + 28 + 12 = 110

Then, New SP = 110% of 120 = 120 x 110/100 = 132

=> New Gain = 132 - 110 = 22

=> New Profit % = 22 x 100/110 = 20%

   Sum = [(B.D.xT.D.)/ (B.D.-T.D.)]

              = [(B.D.xT.D.)/B.G.]

T.D./B.G.  = Sum/ B.D.

   =1650/165

               =10

Thus, if B.G. is Re 1, T.D. = Rs. 10.

If B.D.is Rs. ll, T.D.=Rs. 10.

If B.D. is Rs. 165, T.D. = Rs. [(10/11)xl65]

            =Rs.150

 And, B.G. = Rs. (165 - 150) = Rs, 15.

Santhosh's investment = 6000 x 70/100 = Rs.4200
Rajitha's investment = 4200 x 5/4 = Rs.5250
Therefore, total amount invested = 6000 + 4200 + 5250 = Rs.15450.
Required ratio = 5250 : 15450 = 35 : 103.

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days

Jan. Feb. March April May

(31 + 28 + 31 + 30 + 28 ) = 148 days

148 days = (21 weeks + 1 day) 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.

Given day is Sunday.

Suppose total earnings = Rs. 10000
10% saving = 10000 x (10/100) = Rs. 1000
This year 5% more income than prev year = Rs. 10500
12% saving = 10500 x (12/100) = Rs. 1260
Percentage of amount saved = (1260/1000) x 100 = 126%

6.72/100 = 672/10000 = 42/625