6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Two persons Shyam and Rahim can do a job in 32 days together. Rahim can do the same job in 48 days alone. They started working together and after working 8 days Rahim is replaced by a third person Ram whose efficiency is half that of Rahim. Find in how many days the remaining work will be completed by both Shyam and Ram together?

A) 16 days	B) 72/5 days
C) 15 days	D) 96/5 days

Answer & Explanation Answer: B) 72/5 days

Explanation:

Work done by Shyam and Rahim in 8 days = 8/32 = 1/4

Remaining work to be done by Shyam and Ram = 1 - 1/4 = 3/4

Given efficieny of Ram is half of Rahim i.e, as Rahim can do the work in 48 days, Ram can do the work in 24 days.

One day work of Ram and Shyam = (1/32 - 1/48) + 1/24 = 5/96

Hence, the total work can be done by Shyam and Ram together in 96/5 days.

Therefore, remaining work 3/4 can be done by them in 3/4 x 96/5 = 72/5 = 14.4 days.

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Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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8 7161

Q:

Four persons are to be choosen from a group of 3 men, 2 women and 4 children. Find the probability of selecting 1 man,1 woman and 2 children.

A) 2/7	B) 3/7
C) 4/7	D) 3/7

Answer & Explanation Answer: A) 2/7

Explanation:

Total number of persons = 9

Out of 9 persons 4 persons can be selected in $9 C_{4}$ ways =126

1 man,1 woman and 2 children can be selected in $3 C_{1} * 2 C_{1} * 4 C_{1}$ ways =36

So,required probability = 36/126 =2/7

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Filed Under: Probability

3 7154

Q:

A man has only 20-paise and 25-paise coins in a bag. If he has 50 coins in all totaling to Rs.10.25, then the number of 20-paise coins is

A) 42	B) 45
C) 38	D) 36

Answer & Explanation Answer: B) 45

Explanation:

Let number of 20 ps coins = x and

number of 25 ps coins = y

Given total coins in the bag = 50

x + y = 50.......(1)

But the total money in the bag = Rs. 10.25

0.20x + 0.25y = 10.25

20x + 25y = 1025.........(2)

Now multiplying (1) by 25 we get

25x+25y=1250.............(3)

By solving (2) and (3)

20x + 25y = 1025;

=> x = 45;

Then, the no. of 20 ps coins are 45.

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

5 7152

Q:

If $\sqrt{18225} = 135$ , then the value of $(\sqrt{182.25} + \sqrt{1.8225} + \sqrt{0.018225} + \sqrt{0.00018225})$ is:

A) 1.49985	B) 14.9985
C) 149.985	D) 1499.85

Answer & Explanation Answer: B) 14.9985

Explanation:

Given exp = $\sqrt{\frac{18225}{10^{2}}} + \sqrt{\frac{18225}{10^{4}}} + \sqrt{\frac{18225}{10^{6}}} + \sqrt{\frac{18225}{10^{8}}}$

= $\frac{\sqrt{18225}}{10} + \frac{\sqrt{18225}}{10^{2}} + \frac{\sqrt{18225}}{10^{3}} + \frac{\sqrt{18225}}{10^{4}}$

= $\frac{135}{10} + \frac{135}{100} + \frac{135}{1000} + \frac{135}{10000}$

= 13.5+1.35+0.135+0.0135=14.9985

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Filed Under: Square Roots and Cube Roots

25 7147

Q:

What is the difference between the biggest and the smallest fraction among 2/3 , 3/4 , 4/5 and 5/6?

A) 1/6	B) 1/12
C) 1/20	D) 1/30

Answer & Explanation Answer: A) 1/6

Explanation:

Converting each of the given fractions into decimal form, we get

2/3 = 0.66, 3/4 = 0.75, 4/5 = 0.8, 5/6 = 0.833

Since 0.833>0.8>0.75>0.66

So, 5/6 > 4/5 > 3/4 > 2/3

Therefore, Required Difference = 5/6 - 2/3 = 1/6

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Filed Under: Decimal Fractions

5 7146

Q:

An alloy of copper and bronze weight 50g. It contains 80% Copper. How much copper should be added to the alloy so that percentage of copper is increased to 90%?

A) 45 gm	B) 50 gm
C) 55 gm	D) 60 gm

Answer & Explanation Answer: B) 50 gm

Explanation:

Initial quantity of copper = $\frac{80}{100} x 50$ = 40 g

And that of Bronze = 50 - 40 = 10 g

Let 'p' gm of copper is added to the mixture

=> $(50 + p) x \frac{90}{100}$ = 40 + p

=> 45 + 0.9p = 40 + p

=> p = 50 g

Hence, 50 gms of copper is added to the mixture, so that the copper is increased to 90%.

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Filed Under: Alligation or Mixture
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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20 7140

Q:

At 3% annual interest compounded monthly, how long will it take to double your money?

A) 20.1	B) 21.1
C) 22.1	D) 23.1

Answer & Explanation Answer: D) 23.1

Explanation:

At first glance it might seem that this problem cannot be solved because we do not have enough
information. It can be solved as long as you double whatever amount you start with. If we start with
$100, then P = $100 and FV = $200.

FV=P(1+r/n)^nt

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

6 7139

Q:

(10.3 * 10.3 * 10.3 + 1)/(10.3 * 10.3 - 10.3 + 1) is :

A) 11.3	B) 12.3
C) 13.3	D) 14.3

Answer & Explanation Answer: A) 11.3

Explanation:

a^3 + b^3 = (a+ b) * (a^2 + b^2 - ab)

[ (10.3)^3 + (1)^3 ] / [(10.3)^2 + (1)^2 - (1 * 10.3)]

=> a + b = 10.3 + 1 = 11.3

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Filed Under: Decimal Fractions

6 7137

Quantitative Aptitude - Arithmetic Ability Questions

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