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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

54, 60  LCM is

A) 600 B) 540
C) 60 D) 54
 
Answer & Explanation Answer: B) 540

Explanation:

Here the LCM of 54, 60 is

 

=> 2 x 3 x 3 x 3 x 10

= 6 x 9 x 10

= 54 x 10

= 540.

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Filed Under: HCF and LCM
Exam Prep: CAT , Bank Exams , AIEEE
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27 6830
Q:

Prithvi spent Rs.89,745 on his college fees, Rs 51,291 on Personality Development Classes, and the remaining 27% of the total amount he had as cash with him. What was the total amount?

A) Rs.1,85,400 B) Rs.1,89,600
C) Rs.1,91,800 D) Rs.1,93,200
 
Answer & Explanation Answer: D) Rs.1,93,200

Explanation:
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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
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19 6825
Q:

If three eighth of a number is 141. What will be the approximately value of 32.08% of this number ?

A) 101 B) 112
C) 104 D) 120
 
Answer & Explanation Answer: D) 120

Explanation:

K x 3/8 = 141 => K = 376

376 x 32.08/100 = 120

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Filed Under: Percentage
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5 6822
Q:

The calendar for the year 2020 will be the same for the year

A) 2040 B) 2076
C) 2096 D) 2044
 
Answer & Explanation Answer: D) 2044

Explanation:
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Filed Under: Calendar
Exam Prep: Bank Exams

63 6821
Q:

If each of the 8 teams in a league must play each other three times,how many games will be played?

A) 72 B) 84
C) 36 D) 79
 
Answer & Explanation Answer: B) 84

Explanation:

Since,each member of the league must meet every other member of the league.If they only played each other once,there would be 8C2 games.Since,each pairing of teams will occur three times,the answer will be triple.

 

Therfore, 8C2*3=84

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Filed Under: Permutations and Combinations

1 6819
Q:

Tickets are numbered from 1 to 18 are mixed up together and then 9 tickets are drawn at random. Find the probability that the ticket has a number, which is a multiple of 2 or 3.

A) 1/3 B) 3/5
C) 2/3 D) 5/6
 
Answer & Explanation Answer: C) 2/3

Explanation:

S = { 1, 2, 3, 4, .....18 } 

=> n(S) = 18

 

E1 = {2, 4, 6, 8, 10, 12, 14, 16, 18}

=> n(E1) = 9

 

E2 = {3, 6, 9, 12, 15, 18 }

=> n(E2) = 6

 

 E3 =E1∩E2={6, 12, 18} 

=> n(E3) = 3

 

∴E=E1 ∪ E2 = E1+E2-E3 

=> n(E) = 9 + 6 - 3 =12

 where E = { 2, 3, 4, 6, 8, 9, 10, 12, 12, 14, 15, 16, 18 }

 

∴P(E)=n(E)n(S)=1218=23

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Filed Under: Probability

5 6818
Q:

Find the number of ways to arrange 6 items in groups of 4 at a time where order matters?

A) 720 B) 640
C) 740 D) 360
 
Answer & Explanation Answer: D) 360

Explanation:

6P4 = 6! / (6-4)! = 360

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Filed Under: Permutations and Combinations

0 6814
Q:

About 4 out of 5 students are left handed. If there are totally 40 students in an class. How many would be left handed ?

A) 40 B) 45
C) 32 D) 30
 
Answer & Explanation Answer: C) 32

Explanation:

Probability of left handed = 4/5
total student = 40
total left handed = 40 x(4/5)
= 32

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Filed Under: Numbers
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12 6809