Quantitative Aptitude - Arithmetic Ability Questions

Q:

Den Bosch and Eastbourne are two famous cities 300 km apart. Maradona starts from Den Bosch at 8:24 am . An hour later pele starts from Den Bosch. After travelling for 1 hour , Pele reaches Nottingham that Maradona had passed 40 minutes earlier. Nottingham falls on the way from Den Bosch to Eastbourne. If pele and Maradona just reaches  Eastbourne at the same time, what are thespeeds of the Maradona and Pele Respectively? 

A) 100 km/h , 125 km/h B) 60 km/h , 80 km/h
C) 60 km/h , 75 km/h D) 75 km/h , 100 km/h
 
Answer & Explanation Answer: D) 75 km/h , 100 km/h

Explanation:

Let Pele x km in 1 hour. so Maradona takes (2h-40min)=1 h 20 min to cover x km. Let speed of Maradona and Pele be M and P respectively than 

                            x =M x (4/3)  and x= P x 1

  => M/P = 3/4 

 Again      300M=300P=1

3003k-3004k=1 

 => k= 25

  M= 3k = 75 km/h   and   P= 4k = 100 km/h 

( Through options it is very easy to solve)

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Filed Under: Time and Distance

9 6741
Q:

A sum of Rs. 8,000 is deposited for 3 years at 5% per annum compound interest (compounded annually). The difference of interest for 3 years and 2 years will be

 

A) Rs. 387 B) Rs. 441
C) Rs. 469 D) Rs. 503
 
Answer & Explanation Answer: B) Rs. 441

Explanation:

Given principal amount = Rs. 8000

Time = 3yrs

Rate = 5%

C.I for 3 yrs = 8000 x 105100 x 105100 x 105100 - 8000= Rs. 1261

 

Now, C.I for 2 yrs = 8000 x 105100 x 105100= Rs. 820 

 

Hence, the required difference in C.I is 1261 - 820 = Rs. 441

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14 6740
Q:

The probability that a number selected at random from the first 100 natural numbers is a composite number is  ?

A) 3/2 B) 2/3
C) 1/2 D) 34/7
 
Answer & Explanation Answer: A) 3/2

Explanation:

The number of exhaustive events = 100 C₁ = 100.

We have 25 primes from 1 to 100.

Number of favourable cases are 75.

Required probability = 75/50 = 3/2.

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Filed Under: Probability
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13 6737
Q:

How much does a clock lose per day, if its hands coincide ever 65 minutes ?

A) 1440/143 min B) 184/13 min
C) 1425/18 min D) 541/9 min
 
Answer & Explanation Answer: C) 1425/18 min

Explanation:

55 min. spaces are covered in 60 min.
60 min. spaces are covered in ((60/55) x 60) min = 720/11 min.
Loss in 65 min. = (720/11 - 65 ) = 5/11
Loss in 24 hrs = (5/11 x 1/65 x 24 x 60)min = 1440/143 min.

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Filed Under: Calendar
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21 6736
Q:

One year ago the ratio between Mohan and Ashok's age was 4:3 after one yerar the rato of their ages will be 5:4 . what is the sunm of their present ages in years.

Answer

Let their ages one year  ago be 4x and 3x years


  


   


 Sum of their present ages =(4x +1+3x+1) = 16 years.

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Subject: Problems on Ages

6 6731
Q:

A man sold two flats for Rs. 4.15 lakhs each. On one he gained 2% and on the other he lost 2%. What percent is the effect of the sale on the whole  ?

A) 0.25 % B) 0.04 %
C) 0.5 % D) 0 %
 
Answer & Explanation Answer: B) 0.04 %

Explanation:

In this type cases we always have loss only.

 

Loss% = Common Gain or Loss1022102= 1/25 = 0.04 %

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Filed Under: Profit and Loss
Exam Prep: CAT , Bank Exams , AIEEE
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11 6729
Q:

Two unbiased coin are tossed. What is the probability of getting atmost one head?

A) 1/2 B) 3/2
C) 1/6 D) 3/4
 
Answer & Explanation Answer: D) 3/4

Explanation:

Here, S={HH,HT,TH,TT}
Let E be the event of getting one head
E={TT,HT,TH}
P(E )= n(E)/n(S) =3/4

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Filed Under: Probability

5 6729
Q:

The profit earned by selling an article for Rs.753 is equal to the loss incurred when the same article is sold for Rs.455.What should be the sale price for making 50% profit ?

A) Rs.855 B) Rs.955
C) Rs.906 D) Rs.896
 
Answer & Explanation Answer: C) Rs.906

Explanation:

Let C.P =Rs. x

 

Then as given, (753 - x ) = (x - 455)

=>2x = 1208 => x = 604

 There fore S.P= 150% of 604 => Rs. 150100×604= Rs.906

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Filed Under: Profit and Loss
Exam Prep: CAT
Job Role: Bank PO

14 6726