6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

In what time a 360 m. long train moving at the speed of 44 km/hr will cross a 140 m. long bridge ?

A) 36 sec	B) 39 sec
C) 41 sec	D) 43 sec

Answer & Explanation Answer: C) 41 sec

Explanation:

Speed = 44 kmph x 5/18 = 110/9 m/s

We know that, Time = distance/speed

Time = (360 + 140) / (110/9)

= 500 x 9/110 = 41 sec.

Report Error

View Answer Report Error Discuss

Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

12 6722

Q:

A merchant commences with a certain capital and gains annually at the rate of 30 per cent. At the end of 2 years he has worth Rs 10,000. What was the original capital?

A) Rs. 4987	B) Rs. 5148
C) Rs. 5917	D) Rs. 6254

Answer & Explanation Answer: C) Rs. 5917

Explanation:

Let the Original capital amount be Rs. P

Given after 2 years the amount is Rs. 10000

Rate of interest = 30%

According to the question,

$P x \frac{130}{100} x \frac{130}{100} = 10000 = > P = \frac{1000000}{169} = 5917$

Therefore, the capital amount P = Rs. 5917

Report Error

View Answer Report Error Discuss

Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

6 6722

Q:

A school has scheduled three volleyball games, two soccer games, and four basketball games. You have a ticket allowing you to attend three of the games. In how many ways can you go to two basketball games and one of the other events?

A) 25	B) 30
C) 50	D) 75

Answer & Explanation Answer: B) 30

Explanation:

Since order does not matter it is a combination.

The word AND means multiply.

Given 4 basketball, 3 volleyball, 2 soccer.

We want 2 basketball games and 1 other event. There are 5 choices left.

C(n,r)

C(How many do you have, How many do you want)

C(have 4 basketball, want 2 basketball) x C(have 5 choices left, want 1)

C(4,2) x C(5,1) = (6)(5) = 30

Therefore there are 30 different ways in which you can go to two basketball games and one of the other events.

Report Error

View Answer Report Error Discuss

Filed Under: Permutations and Combinations

1 6718

Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years

Then B's age 10 years ago be 2x yeats

$\inline \Rightarrow \frac{x+10}{2x+10}=\frac{3}{4}$

$\inline \Rightarrow 4(x+10)=3(2x+10)$

$\inline \Rightarrow x=5$

$\inline \therefore$ Total of their present ages = $x+10+2x+10$

= $3x+20$

= 35 years

Workspace

Report Error

View answer Workspace Report Error Discuss

Subject: Problems on Ages

9 6717

Q:

The ratio of present ages of Hema and Chinnu is 13:17. Four years ago the ratio of their ages was 11:15. What will be the ratio of their ages six years hence ?

A) 3 : 7	B) 7 : 9
C) 4 : 5	D) 1 : 3

Answer & Explanation Answer: C) 4 : 5

Explanation:

Let their present ages be 13x and 17x.
Then, 13x-4/17x-4 = 11/15.
Solving this, we get x = 2.
Required ratio = 13x2 + 6/17x2 + 6 = 32/40 = 4/5.

Report Error

View Answer Report Error Discuss

Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

9 6710

Q:

The Value of $[\log (\tan (1^{0})) + \log (\tan (2^{0})) + \dots \dots + \log (\tan (89^{0}))]$ is

A) -1	B) 0
C) 1/2	D) 1

Answer & Explanation Answer: B) 0

Explanation:

$= [\log \tan (1^{0}) + \log \tan (89^{0})] + [\log \tan (2^{0}) + \log \tan (88^{0})] + \dots \dots + [\log \tan (45^{0})]$

$= \log [\tan (1^{0}) \times \tan (89^{0})] + \log [\tan (2^{0}) \times \tan (88^{0})] + \dots \dots + \log (1)$

$[∵ \tan (90 - θ) = c o t θ a n d \tan (45^{0}) = 1]$

= log 1 + log 1 +.....+log 1

= 0.

Report Error

View Answer Report Error Discuss

Filed Under: Logarithms
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

27 6709

Q:

If 6 (P's Capital ) = 8 ( Q's Capital ) = 12 ( R's Capital ) , then out of the total profit of Rs 4650 , R will receive ?

A) Rs. 1033.33	B) Rs. 1024
C) Rs. 1148.14	D) Rs. 1245.32

Answer & Explanation Answer: A) Rs. 1033.33

Explanation:

Let
P's capital = p,
Q's capital = q and
R's capital = r.
Then

6p = 8q = 12r
=> 3p = 4q = 6r
=>q = 3p/4
r = 3p/6 = p/2
P : Q : R = p : 3p/4 : p/2
= 4 : 3 : 2
R's share = 4650 * (2/9) = 150*6 = Rs. 1033.33.

Report Error

View Answer Report Error Discuss

Filed Under: Partnership
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

3 6708

Q:

The cash realised on selling a 14% stock is Rs.106.25, brokerage being 1/4% is

A) 123	B) 106
C) 100	D) 156

Answer & Explanation Answer: B) 106

Explanation:

Cash realised= Rs. (106.25 - 0.25)
= Rs. 106.

Report Error

View Answer Report Error Discuss

Filed Under: Stocks and Shares

9 6692

Quantitative Aptitude - Arithmetic Ability Questions

Quick Links