Quantitative Aptitude - Arithmetic Ability Questions

Q:

Find out the wrong term in the given series of numbers ?
6, 15, 35, 77, 165, 221

A) 35 B) 165
C) 221 D) 77
 
Answer & Explanation Answer: B) 165

Explanation:

The given series follow the rule that :

Multiplying consecutive prime numbers
2,3,5,7,11,13,17,19....
2x3 = 6
3x5 = 15
5x7 = 35
7x11 = 77
11x13 = 143
13x17 = 221
So, the wrong term is 165.

Report Error

View Answer Report Error Discuss

Filed Under: Odd Man Out
Exam Prep: Bank Exams , CAT , GATE , GRE
Job Role: Bank Clerk , Bank PO

6 6784
Q:

What is the SI on Rs.2500/- at the rate of 12% per annum for 8 years?

A) 2200 B) 2300
C) 2400 D) 2500
 
Answer & Explanation Answer: C) 2400

Explanation:

S.I=PNR/100

Report Error

View Answer Report Error Discuss

Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

13 6774
Q:

Two unbiased coin are tossed. What is the probability of getting atmost one head?

A) 1/2 B) 3/2
C) 1/6 D) 3/4
 
Answer & Explanation Answer: D) 3/4

Explanation:

Here, S={HH,HT,TH,TT}
Let E be the event of getting one head
E={TT,HT,TH}
P(E )= n(E)/n(S) =3/4

Report Error

View Answer Report Error Discuss

Filed Under: Probability

5 6770
Q:

A school has scheduled three volleyball games, two soccer games, and four basketball games. You have a ticket allowing you to attend three of the games. In how many ways can you go to two basketball games and one of the other events?

A) 25 B) 30
C) 50 D) 75
 
Answer & Explanation Answer: B) 30

Explanation:

Since order does not matter it is a combination. 

 

The word AND means multiply. 

 

Given 4 basketball, 3 volleyball, 2 soccer. 

 

We want 2 basketball games and 1 other event. There are 5 choices left. 

C(n,r) 

C(How many do you have, How many do you want) 

C(have 4 basketball, want 2 basketball) x C(have 5 choices left, want 1) 

C(4,2) x C(5,1) = (6)(5) = 30

 

Therefore there are 30 different ways in which you can go to two basketball games and one of the other events.

Report Error

View Answer Report Error Discuss

1 6762
Q:

23x12+49x15312+50 = ?

A) 0.5 B) 1
C) 2 D) 3
 
Answer & Explanation Answer: B) 1

Explanation:

276+35961+50 = 10111011 = 1

Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

2 6753
Q:

The cash realised on selling a 14% stock is Rs.106.25, brokerage being 1/4% is

A) 123 B) 106
C) 100 D) 156
 
Answer & Explanation Answer: B) 106

Explanation:

Cash realised= Rs. (106.25 - 0.25)
                      = Rs. 106.

Report Error

View Answer Report Error Discuss

Filed Under: Stocks and Shares

9 6750
Q:

Uma sold an article for 3400 and got a profit of 25%. If he had sold the article for Rs. 3265. How much profit% would Uma have got ?

A) 22% B) 27%
C) 20% D) 18%
 
Answer & Explanation Answer: C) 20%

Explanation:

Given

      125% ---- 3400

=> 100% ---- ?

=> ? = 3400x100/125 = 2720

=> Cost price of the article = Rs. 2720

Profit when article sold at Rs. 3265 = 3265 - 2720 = 545

Hence, Profit% = Gain x 100/cost price

=> P% = 545 x 100/2720

=> P% = 20%

Report Error

View Answer Report Error Discuss

Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

15 6748
Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years 


Then B's age 10 years ago  be 2x yeats


\inline \Rightarrow \frac{x+10}{2x+10}=\frac{3}{4}


\inline \Rightarrow 4(x+10)=3(2x+10)


\inline \Rightarrow x=5


\inline \therefore Total of their present ages =                                        


                                          = 


                                          = 35 years

Report Error

View answer Workspace Report Error Discuss

Subject: Problems on Ages

9 6734