6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Sriram was conducting an experiment in which the average of 11 observations came to be 92, while the average of first five observations was 89, and that of the last five was 86. What was the measure of the 6th observation ?

A) 134	B) 137
C) 139	D) 141

Answer & Explanation Answer: B) 137

Explanation:

This can be done as,

(11 × 92) - (5 × 89) - (5 × 86)

= 1012- 445 - 430 = 137

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Filed Under: Average
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11 6419

Q:

Josh borrowed $250 from his mother to buy an electric scooter. Josh will pay her back in 1 year with 3% simple annual interest. How much interest will Josh pay?

A) 7.50	B) 8.50
C) 9.50	D) 10.50

Answer & Explanation Answer: A) 7.50

Explanation:

I=prt/100

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Filed Under: Compound Interest
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1 6419

Q:

A certain sum of money is invested for one year at a certain rate of simple interest. If the rate of interest is 3% higher, then the invest earned will be 25% more than the interest earned earlier. What is the earlier rate of interest ?

A) 4% p.a.	B) 6% p.a.
C) 8% p.a.	D) 12% p.a.

Answer & Explanation Answer: D) 12% p.a.

Explanation:

If the interest earned is 25% more than the earlier interest then the rate of interest also should be 25% higher than the earlier rate.
Let the earlier rate of interest be x%.
Now it will be (x + 3)%
% increase = (x + 3) - x/x * 100 = 25
=> x = 12%

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Filed Under: Profit and Loss
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5 6407

Q:

In a race of 800m Kaushik gives Piyush a start of 200m and then loses the race by 20 seconds. What is the speed of Piyush and Kaushik respectively ? If the ratio of respective speeds be 3:2.

Answer

Let the speed of Kaushik be Sk and speed of Piyush be Sp and let the time taken by Piyush be t second then,

$\frac{Sk}{Sp} = \frac{\frac{800}{t + 20}}{\frac{600}{t}} = \frac{2}{3} (since given ratio)$

t = 20 s

Speed of Piyush = Sp = 600/20 = 30 m/s

and Speed of Kaushik = 800/40 = 20 m/s

Workspace

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Subject: Time and Distance Exam Prep: AIEEE , Bank Exams , CAT
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8 6406

Q:

A passenger train covers the distance between station K and L, 40 minutes faster than a goods train. Find this distance between K and L if the average speed of the passenger train is 50 km/h and that of goods train is 30 km/h?

A) 50 kms	B) 48 kms
C) 46 kms	D) 44 kms

Answer & Explanation Answer: A) 50 kms

Explanation:

Let the distance be 'd' kms.

According to the given data,

$\frac{d}{30} - \frac{d}{50} = \frac{40}{60} hrs = > 6 d = 300 = > d = 50 kms .$

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16 6400

Q:

How many six digit odd numbers can be formed from the digits 0, 2, 3, 5, 6, 7, 8, and 9 (repetition not allowed)?

A) 8640	B) 720
C) 3620	D) 4512

Answer & Explanation Answer: A) 8640

Explanation:

Let the 6 digits of the required 6 digit number be abcdef

Then, the number to be odd number the last digit must be odd digit i.e 3, 5, 7 or 9

The first digit cannot be ‘0’ => possible digits = 3, 5, 7, 2, 6, 8

Remaining 4 places can be of 6 x 5 x 4 x 3 ways

This can be easily understood by

Therefore, required number of ways = 6 x 6 x 5 x 4 x 3 x 4 = 36 x 20 x 12 = 720 x 12

= 8640 ways.

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Filed Under: Permutations and Combinations
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10 6395

Q:

A girl want to read a complete book. She read 2/5 part of a book on 1st day, 34% on second day and remaining pages in next two days. On those two days she read equal number of pages. If she read 52 pages on last day, then find out total number of pages that the book contain ?

A) 400	B) 525
C) 325	D) 475

Answer & Explanation Answer: A) 400

Explanation:

Let the total number of pages in the book be 'x'.

From given data,

2x/5 + 34x/100 + 52 + 52 = x

=> 40x + 34x + 10400 = 100x

=> 26x = 10400

=> x = 400.

Hence, total pages in the book are 400.

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Filed Under: Percentage
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7 6393

Q:

The compound interest on a certain sum for 2 years at 10% per annum is Rs. 1155. The simple interest on the same sum for double the time at half the rate percent per annum is ?

A) Rs. 1100	B) Rs. 5500
C) Rs. 1400	D) Rs. 4120

Answer & Explanation Answer: A) Rs. 1100

Explanation:

Let the sum be Rs.x. Then,

$[x {(1 + \frac{10}{100})}^{2} - x] = 1155$

$\Rightarrow x [{(\frac{11}{10})}^{2} - 1] = 1155$

=> x =5500

sum = Rs. 5500.

So, S.I = Rs. $(\frac{5500 \times 5 \times 4}{100})$ = 1100

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Filed Under: Compound Interest
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2 6382

Quantitative Aptitude - Arithmetic Ability Questions

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