6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A shopkeeper’s earning increases by 25% in first year but decreases by 4% in the next and so on. After 5 years his total earnings would be Rs. 72,000. What is his present earning?

A) Rs. 40,000	B) Rs. 45,000
C) Rs. 42,000	D) Rs. 46,000

Answer & Explanation Answer: A) Rs. 40,000

Explanation:

Let his present earnings be Rs. p

ATQ,

(125/100) x (96/100) x (125/100) x (96/100) x (125/100) x p = 72000

p = Rs. 40,000.

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27 5765

Q:

In what time a debt of Rs.7920 due may be cleared by immediate cash down payment of Rs.3600 at 1/2% per month

A) 10years	B) 20years
C) 30years	D) 40years

Answer & Explanation Answer: B) 20years

Explanation:

PW = $\frac{100 \times A m o u n t}{100 + (R \times T)}$

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Filed Under: True Discount
Exam Prep: Bank Exams
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6 5758

Q:

A motorboat takes half time to cover a certain distance downstream than upstream. What is the ratio between rate of current and rate of boat in still water?

A) 1 : 3	B) 3 : 2
C) 2 : 3	D) 3 : 1

Answer & Explanation Answer: A) 1 : 3

Explanation:

Let the speed of the boat in still water is 'w'

Speed of the current is 'c'

Let the distance between two places is 'd'

According to the question, motorboat takes half time to cover a certain distance downstream than upstream.

$\frac{d}{w + c} = \frac{1}{2} (\frac{d}{w - c})$

=> 2w - 2c = w + c

=> w = 3c

=> c : w = 1 : 3

Hence, the ratio between rate of current(c) and rate of boat in still water(w) = 1 : 3

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Filed Under: Boats and Streams
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12 5756

Q:

How many seconds will a 600 m long train take to cross a man walking with a speed of 7 km/hr in the direction of the moving train if the speed of the train is 67 km/hr ?

A) 29 sec	B) 58 sec
C) 36 sec	D) 44 sec

Answer & Explanation Answer: C) 36 sec

Explanation:

Speed of train relative to man = 67 - 7 = 60 km/hr.
= 60 x 5/18 = 50/3 m/sec.

Time taken to pass the man = 600 x 3/50 = 36 sec.

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Filed Under: Problems on Trains
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3 5756

Q:

In a 100 litre of mixture the ratio of milk and water is 6:4. How much milk must be added to the mixture in order to make the ratio 3 : 1?

A) 85	B) 60
C) 55	D) 45

Answer & Explanation Answer: B) 60

Explanation:

Let M litres milk be added

=> $\frac{60 + M}{40} = \frac{3}{1}$

=> 60 + M = 120

=> M = 60 lit.

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Filed Under: Alligation or Mixture
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15 5746

Q:

If a girl cycles at 10 kmph, then she arrives at a certain place at 1 p.m. If she cycles at 15 kmph, she will arrive at the same place at 11 a.m. At what speed must she cycle to get there at noon?

A) 14 kmph	B) 13 kmph
C) 12 kmph	D) 11 kmph

Answer & Explanation Answer: C) 12 kmph

Explanation:

The distance is constant in this case.

Let the time taken for travel with a speed of 10 kmph be 't'.

Now the speed of 15 kmph is 3/2 times the speed of 10 kmph.

Therefore, time taken with the speed of 15 kmph will be 2t/3 (speed is inversely proportional to time)

Extra time taken = t - 2t/3 = t/3

=> 1pm - 11am = 2hrs

=> t/3 = 2h

=> t = 6 hrs.

Now, Distance = speed x time = 10 x 6 = 60 kms

Time he takes to reach at noon = 6 - 1 = 5 hrs

Now, Speed = 60/5 = 12 kmph.

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Filed Under: Time and Distance
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12 5739

Q:

A certain sum is to be divided between A and B so that after 5 years the amount received by A is equal to the amount received by B after 7 years. The rate of interest is 10%, interest compounded annually. Find the ratio of amounts invested by them.

please solve this

Answer

Let the sum(principal) received by A and B are x and y.

(1+r) = $1+\frac{1}{10}$ = $\frac{11}{10}$

Then, $\frac{x}{y}=\left ( \frac{11}{10} \right )^{7-5}$ = $\left ( \frac{11}{10} \right )^2 =\frac{121}{100}$

Hence, the ratio in which the sum is divided =121:100

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Subject: Compound Interest Exam Prep: Bank Exams

26 5738

Q:

Sneha’s weight is 140% of Veena’s weight. Rina’s weight is 90% of Sana’s weight. Sana weighs twice as much as Veena. If Sneha’s weight is x% of Rina’s weight, then x is equal to:

A) 596/9	B) 605/9
C) 645/9	D) 700/9

Answer & Explanation Answer: D) 700/9

Explanation:

Let Veena's weight = 1 kg

Sana's weight = 2 kg

Sneha's weight = 1.4 kg

Rina's weight = 1.8 kg

Now,according to the given data in the question,

$\frac{1.8 x}{100} = 1.4$

x = $\frac{1.4 \times 100}{1.8} = \frac{700}{9} = 77 \frac{7}{9}$ .

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Filed Under: Percentage
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