Quantitative Aptitude - Arithmetic Ability Questions

Q:

The ratio of present ages of R and S is 11:17. Before 11 years the ratio of their ages was 11:20. What is R's present age (in years)?

A) 51 B) 33
C) 22 D) 40
 
Answer & Explanation Answer: B) 33

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Q:

The ratio of ages of the father and mother was 11:10 when their son was born. The ratio of ages of the father and mother will be 19:18 when the son will be twice his present age. What is the ratio of present ages of father and mother?

A) 15 : 14 B) 14 : 13
C) 16 : 15 D) 17 : 16
 
Answer & Explanation Answer: A) 15 : 14

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Q:

The ratio of ages of father and son is 7:2. Five years ago the product of their ages was 150. What is the age of the father?

A) 30 years B) 45 years
C) 35 years D) 40 years
 
Answer & Explanation Answer: C) 35 years

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Q:

Rakesh’s present age is 36 years. If 12 years ago, Deepak’s age was one-fourth of Rakesh’s age, then after 27 years what will be the age (in years) of Deepak?

A) 47 B) 52
C) 45 D) 46
 
Answer & Explanation Answer: C) 45

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Q:

Present age of Anil and Rajesh are in the ratio of 11 : 6 respectively. 9 years ago, their ages were in the ratio of 7 : 3. If the Pankaj’s present age is 1/4 of the Anil’s present age, then what is the Pankaj’s present age (in years)?

A) 9 B) 22
C) 13 D) 11
 
Answer & Explanation Answer: D) 11

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Q:

A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train?
     

A) 42 kmph B) 43 kmph
C) 40 kmph D) 45 kmph
 
Answer & Explanation Answer: C) 40 kmph

Explanation:

We know that,  Speed = Distance/time

 

Let the speed of the train be = x kmph

           NORMAL SPEED                           SPEED 5 KMPH MORE

          Distance = 360 Km                         Distance =360
 
          speed    =  X Kmph                        Speed = (x+5)
 
            Time =360/X                              Time =360/(x+15)
          

 

For the same journey if the speed increased 10 kmph more it will take 1 hour less

 


Time with original speed - time with increased speed = 1

 => (360/x) - (360/x+10) =  1                               

 =>  (360(x+5)-360x)/x(x+5) =1

 =>   360X + 1800 -360X  = X(X+5)

  =>   X^2 + 5x - 1800 = 0

  X = 40 or -45

 X cannot be negetive value
                  

 X = 40 kmph.

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Q:

A passenger train running at the speed of 80 kms/hr leaves the railway station 6 hours after a goods train leaves and overtakes it in 4 hours. What is the speed of the goods train?

A) 32 kms/hr B) 50 kms/hr
C) 45 kms/hr D) 64 kms/hr
 
Answer & Explanation Answer: A) 32 kms/hr

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Q:

Two trains are moving in the opposite direction at speed of 30 km/hr and 45 km/hr respectively, whose lengths are 450 m and 550 m respectively. What is the time taken (in seconds) by slower train to cross the faster train?

A) 48 B) 54
C) 62 D) 72
 
Answer & Explanation Answer: A) 48

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