Quantitative Aptitude - Arithmetic Ability Questions

Q:

Joel travels the first 3 hours of his journey at 60 mph speed and the remaining 5 hours at 24 mph speed. What is the average speed of Joel's travel in kmph ?

A) 38 kmph B) 40 kmph
C) 60 kmph D) 54 kmph
 
Answer & Explanation Answer: C) 60 kmph

Explanation:

Average speed = Total distance / Total time.

Total distance traveled by Joel = Distance covered in the first 3 hours + Distance covered in the next 5 hours.

Distance covered in the first 3 hours = 3 x 60 = 180 miles
Distance covered in the next 5 hours = 5 x 24 = 120 miles

Therefore, total distance traveled = 180 + 120 = 300 miles.

Total time taken = 3 + 5 = 8 hours.

Average speed = 300/8 = 37.5 mph.

we know that 1 mile = 1.6 kms

=> 37.5 miles = 37.5 x 1.6 = 60 kms

Average speed in Kmph = 60 kmph.

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Filed Under: Time and Distance
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Q:

The total number of prime factors in the expansion

Answer

 


2211 x 75 x 112=> 222 x 75 x 112


 Total number of prime factors is (22+5+2) = 29

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Q:

Mohan was married 5 years ago. At present his age is 6/5 times of his age at the time of marriage. His wife is 3 year younger to him. Find his wife’s present age?

A) 21 yrs B) 24 yrs
C) 27 yrs D) 30 yrs
 
Answer & Explanation Answer: C) 27 yrs

Explanation:

Let Mohan present age = p

ATQ,

5/6 x p = p - 5

p = 30

His wifes age = 30 - 3 = 27 yrs.

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Filed Under: Problems on Ages
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Q:

A large cube is formed from the material obtained by melting three smaller cubes of 3,4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?

A) 2 : 1 B) 3 : 2
C) 25 : 18 D) 27 : 20
 
Answer & Explanation Answer: C) 25 : 18

Explanation:

ke

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Q:

Kavya's birthday is on Tuesday 4th July. On what day of the week will be Anika's Birthday in the same year, if Anika was born on 15th August?

A) Wednesday B) Friday
C) Saturday D) Tuesday
 
Answer & Explanation Answer: D) Tuesday

Explanation:
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Filed Under: Calendar
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Q:

Important Time and Distance formulas with examples.

Answer

1. How to find Speed(s) if distance(d) & time(t) is given:


 


 Speed (S) = Distance (D)Time (T)  


 


Ex: Find speed if a person travels 4 kms in 2 hrs?


Speed = D/T = 4/2 = 2 kmph.


 


2.  Similarly, we can find distance (d)  if speed (s) & time (t) is given by


 


Distance (D) = Speed (S) x Time (T)


 


Ex : Find distance if a person with a speed of 2 kmph in 2 hrs?


Distance D = S X T = 2 x 2 = 4 kms. 


 


3.  Similarly, we can find time (t) if speed (s) &  distance (d) is given by


 


Time (T) = Distance (D)Speed (S)


 


Ex : Find in what time a person travels 4 kms with a speed of 2 kmph?


Time T = D/S = 4/2 = 2 hrs.


 


4. How to convert  km/hr into m/sec :


 


P km/hr = P x 518 m/sec


 


Ex : Convert 36 kmph into m/sec?


36 kmph = 36 x 5/18 = 10 m/sec 


 


5. How to convert  m/sec into km/hr :


 


P m/sec = P x 185 kmph.


 


Ex : Convert 10 m/sec into km/hr?


10 m/sec = 10 x 18/5 = 36 kmph.


 


6.  If the ratio of the speeds of A and B is a:b, then the ratio of the times taken by them to cover the same distance is b : a.


 


7.  Suppose a man covers a certain distance at x km/ hr and an equal distance at y km/hr . Then, the average speed during the whole journey is 2xyx+y km/hr.

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Q:

A card is drawn from a pack of 52 cards. The card is drawn at random. What is the probability that it is neither a spade nor a Jack?

A) 9/13 B) 4/13
C) 10/13 D) 8/13
 
Answer & Explanation Answer: A) 9/13

Explanation:
 

There are 13 spade and 3 more jack


Probability of getting spade or a jack:
=13+352=1652=413

 

So probability of getting neither spade nor a jack:
=1−413 = 9/13

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Filed Under: Probability

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Q:

One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn find the probability the card drawn is red.

A) 2/3 B) 1/2
C) 1/52 D) 13/51
 
Answer & Explanation Answer: B) 1/2

Explanation:

We know that:

When one card is drawn from a pack of 52 cards

The numbers of possible outcomes n(s) = 52

We know that there are 26 red cards in the pack of 52 cards
⇒ The numbers of favorable outcomes n(E) = 26

Probability of occurrence of an event: P(E)=Number of favorable outcomes/Numeber of possible outcomes=n(E)/n(S)

∴ required probability = 26/52 = 1/2.

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