Quantitative Aptitude - Arithmetic Ability Questions

Q:

One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn find the probability the card drawn is red.

A) 2/3 B) 1/2
C) 1/52 D) 13/51
 
Answer & Explanation Answer: B) 1/2

Explanation:

We know that:

When one card is drawn from a pack of 52 cards

The numbers of possible outcomes n(s) = 52

We know that there are 26 red cards in the pack of 52 cards
⇒ The numbers of favorable outcomes n(E) = 26

Probability of occurrence of an event: P(E)=Number of favorable outcomes/Numeber of possible outcomes=n(E)/n(S)

∴ required probability = 26/52 = 1/2.

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Q:

A large cube is formed from the material obtained by melting three smaller cubes of 3,4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?

A) 2 : 1 B) 3 : 2
C) 25 : 18 D) 27 : 20
 
Answer & Explanation Answer: C) 25 : 18

Explanation:

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Q:

In a box, there are four marbles of white color and five marbles of black color. Two marbles are chosen randomly. What is the probability that both are of the same color?

A) 2/9 B) 5/9
C) 4/9 D) 0
 
Answer & Explanation Answer: C) 4/9

Explanation:

Number of white marbles = 4

Number of Black marbles = 5

Total number of marbles = 9

Number of ways, two marbles picked randomly = 9C2

Now, the required probability of picked marbles are to be of same color = 4C2/9C2  +  5C2/9C2

= 1/6 + 5/18

= 4/9.

 

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13 5597
Q:

In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ?

A) 18 B) 14
C) 22 D) 24
 
Answer & Explanation Answer: B) 14

Explanation:

1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14
Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between them
So minimum no. of boys standing in the queue = 14

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Q:

What will be added to the unit digits of the number 86236 so that number will be divisible by 9  ?

A) 1 B) 2
C) 3 D) 0
 
Answer & Explanation Answer: B) 2

Explanation:

A number is divisible by 9 only if the sum of the digits of the number is divisible by 9.

Here 86236 = 8 + 6 + 2 + 3 + 6 = 25

We must add 2 to 25 to become 27 which is divisible by 9.

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4 5589
Q:

Important Time and Distance formulas with examples.

Answer

1. How to find Speed(s) if distance(d) & time(t) is given:


 


 Speed (S) = Distance (D)Time (T)  


 


Ex: Find speed if a person travels 4 kms in 2 hrs?


Speed = D/T = 4/2 = 2 kmph.


 


2.  Similarly, we can find distance (d)  if speed (s) & time (t) is given by


 


Distance (D) = Speed (S) x Time (T)


 


Ex : Find distance if a person with a speed of 2 kmph in 2 hrs?


Distance D = S X T = 2 x 2 = 4 kms. 


 


3.  Similarly, we can find time (t) if speed (s) &  distance (d) is given by


 


Time (T) = Distance (D)Speed (S)


 


Ex : Find in what time a person travels 4 kms with a speed of 2 kmph?


Time T = D/S = 4/2 = 2 hrs.


 


4. How to convert  km/hr into m/sec :


 


P km/hr = P x 518 m/sec


 


Ex : Convert 36 kmph into m/sec?


36 kmph = 36 x 5/18 = 10 m/sec 


 


5. How to convert  m/sec into km/hr :


 


P m/sec = P x 185 kmph.


 


Ex : Convert 10 m/sec into km/hr?


10 m/sec = 10 x 18/5 = 36 kmph.


 


6.  If the ratio of the speeds of A and B is a:b, then the ratio of the times taken by them to cover the same distance is b : a.


 


7.  Suppose a man covers a certain distance at x km/ hr and an equal distance at y km/hr . Then, the average speed during the whole journey is 2xyx+y km/hr.

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Q:

Mohan was married 5 years ago. At present his age is 6/5 times of his age at the time of marriage. His wife is 3 year younger to him. Find his wife’s present age?

A) 21 yrs B) 24 yrs
C) 27 yrs D) 30 yrs
 
Answer & Explanation Answer: C) 27 yrs

Explanation:

Let Mohan present age = p

ATQ,

5/6 x p = p - 5

p = 30

His wifes age = 30 - 3 = 27 yrs.

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Q:

Out of sixty students, there are 14 who are taking Economics and 29 who are taking Calculus. What is the probability that a randomly chosen student from this group is taking only the Calculus class ?

A) 8/15 B) 7/15
C) 1/15 D) 4/15
 
Answer & Explanation Answer: B) 7/15

Explanation:

Given total students in the class = 60
Students who are taking Economics = 24 and
Students who are taking Calculus = 32
Students who are taking both subjects = 60-(24 + 32) = 60 - 56 = 4
Students who are taking calculus only = 32 - 4 = 28
probability that a randomly chosen student from this group is taking only the Calculus class = 28/60 = 7/15.

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