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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

Find the simple interest charged on borrowing $325 for 5 years at 3% p.a. (per annum or per year) interest.

A) 59 B) 46
C) 48.75 D) 34.75
 
Answer & Explanation Answer: C) 48.75

Explanation:

I= PTR100

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Filed Under: Simple Interest
Exam Prep: Bank Exams
Job Role: Bank PO

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Q:

There are 41 students in a class, number of girls is one more than number of guys. we need to form a team of four students. all four in the team cannot be from same gender. number of girls and guys in the team should NOT be equal. How many ways can such a team be made ?

A) 49450 B) 50540
C) 46587 D) 52487
 
Answer & Explanation Answer: B) 50540

Explanation:

Given G + B= 41 and B = G-1
Hence, G = 21 and B = 20
Now we have 2 options,
1G and 3M
(or)
3G and 1M
(2G and 2M or 0G and 4M or 4G and oM are not allowed),

 

Total : C121×C320+C321×C120= 50540 ways.

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Filed Under: Permutations and Combinations
Exam Prep: GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk

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Q:

Kashundra Jones plans to make a lump sum deposit so that she can withdraw $3,000 at the end of each quarter for 10 years. Find the lump sum if the money earns 10% per year compounded quarterly

A) 75263.64 B) 76345
C) 76389 D) 56897
 
Answer & Explanation Answer: A) 75263.64

Explanation:

 

 

A=R[(1+i)^n-1]/i(1+i)^n

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

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Q:

A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by

A) 100 m B) 111m
C) 25 m D) 50 m
 
Answer & Explanation Answer: A) 100 m

Explanation:

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Filed Under: Races and Games

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Q:

If each vowel of the word NICELY is changed to the next letter in the English alphabetical series and each consonant is changed to the previous letter in the English alphabetical series and then the alphabets are arranged in alphabetical order, which of the following will be fourth from the left?

A) M B) J
C) B D) O
 
Answer & Explanation Answer:

Explanation:

Thus after arranging the letters as per English alphabetical series; we get; Thus 4th letter from the left end will be K.

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Filed Under: Permutations and Combinations

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Q:

Total 100 members are writing exam. In that 48 members are writing first exam, 45 members are writing second exam and 38 members are writing third exam. 5 members are writing all the three exams. How many members are writing 2 exams ?

A) 26 B) 23
C) 27 D) 21
 
Answer & Explanation Answer: D) 21

Explanation:

Total number of exams written by 100 students = 48 + 45 + 38 = 131
Now let us say x members are writing only 1 exam, y members are writing only 2 exams, z members are writing only 3 exams.
Therefore, x + 2y + 3z = 131 also x + y + z = 100.
Given that z = 5. So x + 2y = 116 and x + y = 95.
Solving we get y = 21.
So 21 members are writing exactly 2 exams.

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Filed Under: Problems on Numbers
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

6 4243
Q:

A sum of Rs. 10,000 is lent partly at 6% and the remaining at 10% p.a. If the yearly interest on the average is 9.2%, the money lent at 10% is:-

A) Rs. 8000 B) Rs. 8500
C) Rs. 5000 D) Rs. 2000
 
Answer & Explanation Answer: A) Rs. 8000

Explanation:

Let the amount at 6% be x
Amount at 10% be (10000 –x)
At 9.2 % interest, SI = 10000 X 9.2 X 1/100 = 920
Amount = 10920
⇒ 6x/100 + (10000 – x)10/100 = 920
⇒ 6x – 10x + 100000 = 92000
⇒ 4x = 8000
⇒ x = 2000
Money lent at 10 % = 10000 – 2000 = 8000

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Filed Under: Simple Interest
Exam Prep: Bank Exams

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Q:

Two boxes contain 4 and 16 balls respectively. Two balls in the first box and four in the second, are black. If a box is chosen randomly and two balls are drawn at random from it, what is the
probability that at least one ball is black if the ball is not replaced?

A) 11/20 B) 43/120
C) 77/120 D) 9/20
 
Answer & Explanation Answer: C) 77/120

Explanation:

At least one black can be chosen in two ways from each box:
Now, probability of choosing at least one black ball from first box 

= 1/2 × [ (2C1× 2C1)/4C2 + 2C2/ 4C2 ]= 5/12

Probability of choosing at least one black ball from 2nd box
= 1/2 × [(4C1×12C1)/16C2 + 4C2/ 16C2] = 9/40

Final probability

= 5/12 + 9/40 = (50 + 27)/120 = 77/120

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

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