6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

Train A, travelling at 84 kmph, overtook train B, traveling in the same direction, in 10 seconds. If train B had been traveling at twice its speed, then train A would have taken 22.5 seconds to overtake it. Find the length of train B, given that it is half the length of train A.

A) 180 m	B) 100 m
C) 200 m	D) 150 m

Answer & Explanation Answer:

Explanation:

Let speed of train B be x m/s And length of train B be y m
Then length of train A is 2y m
Speed of train A = 84 × 5/18 = 210/9 m/s = 70/3 m/s
A.T.Q, (2y+y)/10 = 70/3 − x .............(i)
and (2y+y)/ 22.5 = 70/3 − 2x ................(ii)
solving (i) and (ii), y = 50 m

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams , GATE

0 4261

Q:

3.2% of 500 × 2. 4% of ? = 312

A) 812.5	B) 829.75
C) 749.85	D) 799.5

Answer & Explanation Answer: A) 812.5

Explanation:

$Given 3.2 % of 500 \times 2 . 4 % of ? = 312 Then, 3.2 x \frac{500}{100} x 2.4 x \frac{?}{100} = 312 16 x \frac{2.4 x ?}{100} = 312 \frac{9.6 x ?}{25} = 312 9.6 x ? = 7800 ? = \frac{7800}{9.6} ? = 812.5$

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Filed Under: Percentage
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO , IT Trainer

7 4259

Q:

The population of a city is 415600.It increased by 25% in the first year and decreased by 30% in the second year.What is the population of the city at the end of second year?

Answer

As per given data, P = 415600, R1= 25% incresed, R2 = 30% decreased

Population of the city at the end of the second year= $p\left ( 1+\frac{R1}{100} \right )\left ( 1-\frac{R2}{100} \right )$

$\Rightarrow$ $415600\left ( 1+\frac{25}{100} \right )\left ( 1-\frac{30}{100} \right )$

$\Rightarrow$ 363650.

Workspace

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Subject: Percentage Exam Prep: CAT
Job Role: Bank Clerk

12 4258

Q:

A loan is made for $4800 with an APR of 12% and payments made monthly for 24 months. What is the payment amount? What is the finance charge?

A) 622.80	B) 522.80
C) 322.80	D) 632.80

Answer & Explanation Answer: A) 622.80

Explanation:

${\color{Blue} A=R\left [(1+i)^{n-1} \right ]/i ( 1+i )^{n}}$

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

0 4256

Q:

A class consists of both boys and girls along with a teacher. After a class, the teacher drinks 9 litres of water, a boy drinks 7 litres of water and a girl drinks 4 litres of water. If after a class 42 litres of water was consumed, find the number of girls in the class ?

A) 8	B) 6
C) 5	D) 3

Answer & Explanation Answer: D) 3

Explanation:

Given teacher drinks 9 ltr
Let number of boys be 'A'.
Let number of girls be 'B'.
Boy drinks 7 ltr and girl drinks 4 ltr
After class total water consumed = 42 ltr
Then,
9 + 7A + 4B = 42
=> 7A + 4B = 33
By trial and error method,
The only integers which satisfy the equation is A = 3 and B = 3
Therefore, number of girls in the class = 3.

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

6 4256

Q:

Dianna deposits $725 into a savings account that pays 2.3% simple annual interest. How much interest will Dianna earn after 18 months?

A) 23.01	B) 24.01
C) 25.01	D) 26.01

Answer & Explanation Answer: C) 25.01

Explanation:

I = Prt

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Filed Under: Quantitative Aptitude - Arithmetic Ability
Exam Prep: Bank Exams
Job Role: Bank PO

0 4256

Q:

K can finish the work in 18 days and L can do the same work in 15 days. L worked for 10 days and left the job. In how many days, K alone can finish the remaining work ?

A) 5.5 days	B) 6 days
C) 4.2 days	D) 5 days

Answer & Explanation Answer: B) 6 days

Explanation:

L's 10 days work = $(\frac{1}{15} \times 10) = \frac{2}{3}$

Remaining work = $(1 - \frac{2}{3}) = \frac{1}{3}$

Now, work is done by K in one day = 1/18

1/3 work is done by K in $(18 \times \frac{1}{3})$ = 6 days

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Filed Under: Time and Work
Exam Prep: GATE , CAT , Bank Exams
Job Role: Bank PO , Bank Clerk

5 4252

Q:

There are two shopkeepers, first shopkeeper calculates his profit percent on the selling price whereas the second shopkeeper calculates his profit percent on the cost price. If the selling price for both the shopkeeper is same and the difference between their profits is Rs.175. Then, calculate the sum of the cost price for both the shopkeeper if the profit percent for the both shopkeeper is 25%?

A) Rs 5425	B) Rs 4875
C) Rs 4675	D) Rs 5275

Answer & Explanation Answer: A) Rs 5425

Explanation:

Let the selling price for each of the shopkeeper be Rs 100x

For 1st shopkeeper

SP= Rs 100x

CP=100

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT

13 4250

Quantitative Aptitude - Arithmetic Ability Questions

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