Quantitative Aptitude - Arithmetic Ability Questions

Let the required number be 'p'.

From the given data,

p + 12 = 160 x 1/p

=> p + 12 = 160/p

=> p(p + 12) = 160

=> P^2 + 12p - 160 = 0

=> p^2 + 20p - 8p - 160 = 0

=> P(p + 20) - 8(p + 20) = 0

=> (p + 20)(p - 8) = 0

=> p = -20 or p = 8

As, given the number is a natural number, so it can't be negative.

Hence, the required number p = 8.

Let the cost price of the bottle = Rs. 100

Selling price of the bottle = Rs. 100 - Rs. 9 = Rs. 91

Then, from the given data,

=> 112 (1/2) - 91 = 15

=> 21 (1/2) = 15

=> 43 = 15

Then 100 = ?

1500/43 = 34.885 =~ 35

Hence, the cost price of the bottle = Rs. 35

Let the smaller number be 'm'

Then, from the given data, the larger number is '3m'

Given that m + 3m = 44

=> 4m = 44

m = 44/4 = 11

=> m = 11

=> 3m = 3 x 11 = 33

Hence, the two numbers are 11 and 33.

   1 1
   8 A 9
+ 4 C 6
-  6 B 2
   7 2 3
We may represent the given sum, as shown below:

1 + A + C - B = 12
A + C - B = 11

Now,giving the maximum values to A and C, i.e.

A = 9 and C = 9, we get B = 7.