6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is

A) 35.55 km/hr	B) 36 km/hr
C) 71.11 km/hr	D) 71 km/hr

Answer & Explanation Answer: C) 71.11 km/hr

Explanation:

Total time taken = (160/64 + 160/8)hrs
= 9/2 hrs.

Average speed = (320 x 2/9) km.hr
= 71.11 km/hr.

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Filed Under: Time and Distance

152 56679

Q:

${(4 x - 7)}^{2} = ?$

A) 4x2 - 56x + 49	B) 4x2 - 14x + 49
C) 16x2 + 14x + 49	D) 16x2 - 56x + 49

Answer & Explanation Answer: D) 16x2 - 56x + 49

Explanation:

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Filed Under: Simplification
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2 56653

Q:

From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?

A) 1/15	B) 1/221
C) 25/57	D) 35/256

Answer & Explanation Answer: B) 1/221

Explanation:

Let S be the sample space

Then, n(S) = $52 C_{2}$ = 1326.

Let E = event of getting 2 kings out of 4.

n(E) = $\frac{52 * 51}{2 * 1}$ = 6.

$4 C_{2}$

=> $\frac{4 * 3}{2 * 1}$

$P (E) = \frac{n (E)}{n (S)} = \frac{6}{1326} = \frac{1}{221}$

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Filed Under: Probability

44 56646

Q:

If $x^{2} + kx + k = 0$ , has two distinct real solutions, then the value of k will satisfy

A) k<0 or k>4	B) k>4 only
C) 0<k<4	D) k<0 only

Answer & Explanation Answer: A) k<0 or k>4

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

0 56634

Q:

Given that $(a^{2} + b^{2}) = 60$ , then find the value of ${(a + b)}^{2} + {(a - b)}^{2}$ ?

A) 90	B) 120
C) 140	D) 150

Answer & Explanation Answer: B) 120

Explanation:

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0 56462

Q:

If ${(x - 7)}^{2} + {(y + 10)}^{2} + {(z - 6)}^{2} = 0$ , then find the value of x + y + z.

A) 1	B) 3
C) 5	D) 7

Answer & Explanation Answer: B) 3

Explanation:

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Filed Under: Simplification
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1 56251

Q:

Which two months in a year have the same calendar?

A) October, December	B) April, November
C) June, October	D) April, July

Answer & Explanation Answer: D) April, July

Explanation:

If the period between the two months is divisible by 7, then that two months will have the same calender .

(a). Oct + Nov = 31 + 30 = 61 (not divisible by 7)

(b). Apr + May + Jun + Jul + Aug + Sep + Oct = 30 + 31 + 30 + 31 + 31 + 30 + 31 = 214 (not divisible by 7)

(c). Jun + July + Aug + Sep = 30 + 31 + 31 + 30 = 122 (not divisible by 7)

(d). Apr + May + June = 30 + 31 + 30 = 91 (divisible by 7)

Hence, April and July months will have the same calendar.

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Filed Under: Calendar
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228 56085

Q:

If (3/2)X = (5/7)Y = (6/5)Z, then what is X : Y : Z?

A) 105 : 50 : 84	B) 24 : 25 : 32
C) 15 : 21 : 25	D) 20 : 42 : 25

Quantitative Aptitude - Arithmetic Ability Questions

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