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 Quantitative Aptitude - Arithmetic Ability Questions

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Q:

Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?

A) 3.6 B) 6
C) 18 D) Cannot be determined
 
Answer & Explanation Answer: B) 6

Explanation:

Explanation:

 

Let rate = R% and time = R years.

 

Then, 1200*R*R100=432

 

12R2=432

 

=>R2=36⇔R=6

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Filed Under: Compound Interest

117 50420
Q:

Reena and Shaloo are partners in a business, Reena invests Rs, 35,000 for 8 months and Shaloo invests Rs. 42,000 for 10 months, out of a profit of  Rs. 31,570, Reena's share is :

A) 12628 B) 18245
C) 11235 D) 10253
 
Answer & Explanation Answer: A) 12628

Explanation:

Ratio of their shares = (35000 * 8) : (42000 * 10) = 2 : 3.

Reena's share Rs. 31570 * (2 / 5) = Rs. 12628.

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Filed Under: Partnership

31 50368
Q:

Compute of 29292 x 9999 = ?

 

 

A) 222890708  B) 298290708 
C) 292809708  D) 292890708
 
Answer & Explanation Answer: D) 292890708

Explanation:
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Filed Under: Simplification
Exam Prep: Bank Exams

0 50360
Q:

If A's height is 40% less than that of B, how much percent B's height is more than that of A?

A) 66.66% B) 76.66%
C) 96.66% D) 86.66%
 
Answer & Explanation Answer: A) 66.66%

Explanation:

Excess of B's height over A's = [(40/(100 - 40)] x 100% =  66.66%

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Filed Under: Percentage

198 50264
Q:

Direction: What value should come in place of the question mark (?) in the following question?

534.596 + 61.472 - 496.708 = ? + 27.271

A) 126.631  B) 62.069
C) 72.089 D) 132.788
 
Answer & Explanation Answer: C) 72.089

Explanation:

534.596 + 61.472 – 496.708 = ? + 27.271

596.068 – 496.708 = ? + 27.271

? = 99.36 – 27.271

? = 72.089.

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Filed Under: Simplification
Exam Prep: AIEEE , Bank Exams , GATE

0 50141
Q:

A certain sum of money amounts to Rs 1008 in 2 years and to Rs 1164 in 3 ½  years. Find the sum and the rate of interest.

A) 800, 14% B) 800, 13%
C) 800, 12% D) 800, 19%
 
Answer & Explanation Answer: B) 800, 13%

Explanation:

S.I. for 1 ½ years = Rs (1164 - 1008) = Rs 156 . 

S.I. for 2 years = Rs (156 x 23 x 2)= Rs 208. 

Therefore, Principal = Rs (1008 - 208) = Rs 800. 

Now, P = 800, T= 2 and S.I. = 208.

Therefore, Rate = (100 x S.I.) / (P x T) = [ (100 x 208)/(800 x 2)]% = 13%

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Filed Under: Simple Interest
Exam Prep: GRE

143 50116
Q:

What annual instalment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?

A) Rs.325 B) Rs.545
C) Rs.560 D) Rs.550
 
Answer & Explanation Answer: A) Rs.325

Explanation:

Let each instalment be Rs.x .

 

1st year =  [x + (x * 12 * 2)/100] 

2nd year = [ x + (x *12 * 1)/100] 

3rd year = x 

Then, [x + (x * 12 * 2)/100] + [ x + (x *12 * 1)/100] + x =1092 

3x + ( 24x/100 ) + ( 12x/100 )  = 1092 

336x =109200

Therefore, x = 325 

Each instalment = Rs. 325

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Filed Under: Simple Interest
Exam Prep: GRE

204 49930
Q:

L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :

A) -2 B) -1
C) 1 D) 2
 
Answer & Explanation Answer: A) -2

Explanation:

 H. C. F of two prime numbers is 1.  Product of numbers = 1 x 161 = 161.

 Let the numbers be a and b . Then , ab= 161.

 Now, co-primes with  product 161 are (1, 161) and (7, 23).

 Since x and y are prime numbers and x >y , we have x=23 and y=7.

 Therefore,  3y-x = (3 x 7)-23 = -2

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Filed Under: HCF and LCM

119 49904