6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

What is the value of (cosec60 - 1/2) ?

A) (4-√3)/2√3	B) (2√3-1)/√3
C) (3√3-1)/3	D) 1/√3

Answer & Explanation Answer: A) (4-√3)/2√3

Explanation:

Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

0 46983

Q:

Compute of 15872/32/4 = ?

A) 142	B) 1984
C) 124	D) 1948

Answer & Explanation Answer: C) 124

Explanation:

Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

2 46958

Q:

∆UVW is right angled at V. If cosU = 8/17, then what is the value of sinW ?

A) 15/17	B) 17/8
C) 8/17	D) 17/15

Answer & Explanation Answer: C) 8/17

Explanation:

Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

1 46844

Q:

Find the value of $\{{(216)}^{\frac{2}{3}} + {(36)}^{\frac{- 1}{2}}\}$

A) 216/6	B) 218/6
C) 215/6	D) 217/6

Answer & Explanation Answer: D) 217/6

Explanation:

Report Error

View Answer Report Error Discuss

Filed Under: Simplification
Exam Prep: Bank Exams

0 46689

Q:

Find the odd man out?

61, 66, 83, 121, 185

A) 185	B) 121
C) 83	D) 66

Answer & Explanation Answer: B) 121

Explanation:

Given number series is 61, 66, 83, 121, 185

Here the given series follows a pattern that,

$61 61 + (2^{2} + 1) = 66 66 + (4^{2} + 1) = 83 83 + (6^{2} + 1) = 120 (not 121) 120 + (8^{2} + 1) = 185$

Hence, the odd man in the given series is 121.

Report Error

View Answer Report Error Discuss

Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

3 46685

Q:

The length of a rectangle is halved, while its breadth is tripled. What is the percentage change in area?

A) 20%	B) 30%
C) 40%	D) 50%

Answer & Explanation Answer: D) 50%

Explanation:

Let original length = x and original breadth = y.

Original area = xy.

New length = x/2 and New breadth=3y

New area = $\frac{3}{2} x y$

Therefore, Increase in area = New area-original area = $\frac{3}{2} x y - x y = \frac{1}{2} x y$

Therefore, Increase % = $\frac{i n c r e a s e i n a r e a}{o r i g i n a l a r e a} * 100 = (\frac{\frac{1}{2} x y}{x y}) * 100 = 50$ %

Report Error

View Answer Report Error Discuss

Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

47 46682

Q:

Find the missing number in the given number series?

2676, 445, ?, 21,6, 2, 1

A) 88	B) 92
C) 96	D) 102

Answer & Explanation Answer: A) 88

Explanation:

The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that,

From right side,

1

1 x 1 + 1 = 2

2 x 2 + 2 = 6

6 x 3 + 3 = 21

21 x 4 + 4 = 88

88 x 5 + 5 = 445

445 x 6 + 6 = 2676

Hence the missing number in the given number series is 88.

Report Error

View Answer Report Error Discuss

Filed Under: Odd Man Out
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

5 46644

Q:

A can contains a mixture of two liquids A and B in the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?

A) 10	B) 20
C) 21	D) 25

Answer & Explanation Answer: C) 21

Explanation:

Suppose the can initially contains 7x and 5x litres of mixtures A and B respectively

Quantity of A in mixture left = $(7 x - \frac{7}{12} \times 9) = (7 x - \frac{21}{4})$ litres.

Quantity of B in mixture left = $(5 x - \frac{5}{12} \times 9) = (5 x - \frac{15}{4})$ litres.

$\frac{(7 x - \frac{21}{4})}{(5 x - \frac{15}{4}) + 9} = \frac{7}{9}$

$\Rightarrow \frac{28 x - 21}{20 x + 21} = \frac{7}{9}$

$\Rightarrow x = 3$

So, the can contained 21 litres of A.

Report Error

View Answer Report Error Discuss

Filed Under: Alligation or Mixture

272 46642

Quantitative Aptitude - Arithmetic Ability Questions

Quick Links