6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

If $\tan^{4} θ + \tan^{2} θ = 2$ , then $\sec^{4} θ - \sec^{2} θ = ?$

A) 0	B) 3
C) 2	D) 1

Answer & Explanation Answer: C) 2

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

0 44445

Q:

A certain number of men can finish a piece of work in 100 days. If there were 10 men less, it would take 10 days more for the work to be finished. How many men were there originally?

A) 75	B) 82
C) 100	D) 110

Answer & Explanation Answer: D) 110

Explanation:

Originally let there be x men.

Less men, More days (Indirect Proportion)

Therefore, (x-10) : x :: 100 :110

=> (x - 10) * 110 = x * 100 => x= 110

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Filed Under: Chain Rule

96 44435

Q:

The difference between compound interest and simple interest on a sum for two years at 8% per annum, where the interest is compounded annually is Rs.16. if the interest were compounded half yearly , the difference in two interests would be nearly

A) Rs.24.64	B) Rs.21.85
C) Rs.16	D) Rs.16.80

Answer & Explanation Answer: A) Rs.24.64

Explanation:

For 1st year S.I =C.I.

Thus, Rs.16 is the S.I. on S.I. for 1 year, which at 8% is thus Rs.200

i.e S.I on the principal for 1 year is Rs.200

Principle = $R s . \frac{100 * 200}{8 * 1}$ = Rs.2500

Amount for 2 years, compounded half-yearly

$R s . [2500 * {(1 + \frac{4}{100})}^{4}] = R s . 2924.4$

C.I = Rs.424.64

Also, $S . I = R s . (\frac{2500 * 8 * 2}{100}) = R s . 400$

Hence, [(C.I) - (S.I)] = Rs. (424.64 - 400) = Rs.24.64

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

121 44303

Q:

What is the value of $\sqrt{1054 + \sqrt{196} + \sqrt{169} + \sqrt{64}}$ ?

A) 33	B) 37
C) 29	D) 31

Answer & Explanation Answer: A) 33

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

0 44245

Q:

There is 60% increase in an amount in 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate

A) Rs.4972	B) Rs.3972
C) Rs.5972	D) Rs.2972

Answer & Explanation Answer: B) Rs.3972

Explanation:

Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.

R= $\frac{100 * 60}{100 * 6}$ =10% p.a

Now, P = Rs. 12000. T = 3 years and R = 10% p.a.

C.I= $R s . [12000 * {[1 + \frac{10}{100}]}^{3} - 1]$
=Rs.3972

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Filed Under: Compound Interest
Exam Prep: Bank Exams
Job Role: Bank PO

52 44243

Q:

A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is ?

A) 45 kmph	B) 25 kmph
C) 30 kmph	D) 50 kmph

Answer & Explanation Answer: D) 50 kmph

Explanation:

Speed of the train relative to man = (125/10) m/sec = (25/2) m/sec.
[(25/2) x (18/5)] km/hr = 45 km/hr.
Let the speed of the train be 'S' km/hr.
Then, relative speed = (S - 5) km/hr.
S - 5 = 45 => S = 50 km/hr.

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

49 44242

Q:

If $tanα = \sqrt{2} + 1$ , then the value of $tanα - cotα$ is

A) √2 - 1	B) 2√2
C) 2	D) 1

Answer & Explanation Answer: C) 2

Explanation:

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Filed Under: Simplification
Exam Prep: Bank Exams

2 44233

Q:

$4 + (\frac{1}{6}) [\{- 10 x (25 - 13 - 3)\} \div (- 5)] = ?$

A) 8	B) 9
C) 6	D) 7

Quantitative Aptitude - Arithmetic Ability Questions

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