Quantitative Aptitude - Arithmetic Ability Questions

Cost Price = Rs.100125×8750 = Rs. 7000. Let the labelled price be Rs. x. 

Then, 70100*x=7000 ⇒x=Rs.7000*10070 

= Rs.10000

Given number of boxes = 14

Number of workers = 4

Now, number of whole boxes per worker = 14/4 = 3.5 

Hence, number of whole boxes per each coworker = 3

Let the total profit be Rs. x. Then, B = 2x/7 and A = (x - 2x /7) =  5x / 7.

So, A : B = 5x/7 : 2x/7 = 5 : 2.

Let B s capital be Rs. y. Then, (16000 * 8) / ( y * 4) = 5/2  <=> (16000 * 8 * 2) / (5 * 4) = 12800..  

Let C.P be Rs. x 

900 - x = 2(x - 450)     => x = Rs.600   

C.P = 600 gain required is 25% 

S.P = [(100+25) x 600] / 100 = Rs.750

The given series follows a pattern that,

$$\begin{gathered} 4 + 32 = 4 + 9 = 13 \\ 13 + 52 = 13 + 25 = 38 \\ 38 + 72 = 38 + 49 = 87 \\ 87 + 92 = 87 + 81 = 198 \end{gathered}$$ 

Hence, the odd man in the given number series is 12.

Other side = [(17 x 17) - (15 x 15)] = (289 - 225) = 8m
Area = 15 x 8 =120 sq. m

3 * 5 + 5 * 3 = (2 * 3 - 3 * 5 + 3 * 5) + ( 2 * 5 - 3 * 3 + 5 * 3)

                    = (6 + 10 - 9 + 15) = 22.