6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

A boy multiplied 987 by a certain number and obtained 559981 as his answer. If in the answer both 98 are wrong and the other digits are correct , then the correct answer would be :

A) 553681	B) 555181
C) 555681	D) 556581

Answer & Explanation Answer: C) 555681

Explanation:

987 = 3 * 7 * 47.
So, the required number must be divisible by each one of 3, 7, 47
553681 => (Sum of digits = 28, not divisible by 3)
555181 => (Sum of digits = 25, not divisible by 3)
555681 is divisible by each one of 3, 7, 47.

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Filed Under: Numbers

61 36074

Q:

If S is the midpoint of a straight line PQ and R is a point different from S, such that PR =RQ, then

A) ∠PRS = 90°	B) ∠QRS = 90°
C) ∠PSR = 90°	D) ∠QSR = 90°

Answer & Explanation Answer: C) ∠PSR = 90°

Explanation:

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Filed Under: Area
Exam Prep: Bank Exams

1 36062

Q:

The average salary of all the workers in a workshop is Rs. 8000. The average salary of 7 technicians is Rs. 12000 and the average salary of the rest is Rs. 6000. The total number of workers in the workshop is :

A) 20	B) 21
C) 23	D) 24

Answer & Explanation Answer: B) 21

Explanation:

Lot the total number of workers be v Then,

8OOOv = (12000 * 7) + 6000 (v - 7) <=> 2000v = 42000 <=> v = 21.

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Filed Under: Average

65 36033

Q:

1100 boys and 700 girls are examined in a test; 42% of the boys and 30% of the girls pass. The percentage of the total who failed is :

A) 58	B) 62 *2/3
C) 64	D) 67

Answer & Explanation Answer: B) 62 *2/3

Explanation:

Total number of students = 1100 + 700 = 1800.

Number of students passed = (42% of 1100 + 30% of 700) - (462 + 210) = 672.

Number of failues = 1800-672 = 1128.

Percentage failure = (1128/1800 * 100 )% = 62 * 2/3 %.

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Filed Under: Percentage

102 36024

Q:

Which of the following fractions is greater than 3 /4 and less than 5 / 6 ?

A) 3 / 5	B) 4 / 5
C) 7 / 5	D) 9 / 5

Answer & Explanation Answer: B) 4 / 5

Explanation:

3 /4 = 0.75, 5/6 = 0.833, 1/2 = .5, 2/3 = 0.66, 4/5 = 0.8, 9/10 = 0.9.

clearly 0.8 lies between 0.75 and .833.

4/5 lies between 3/4 and 5/6..

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Filed Under: Decimal Fractions

56 36020

Q:

2 men and 7 boys can do a piece of work in 14 days; 3 men and 8 boys can do the same in 11 days. Then, 8 men and 6 boys can do three times the amount of this work in

A) 18 days	B) 21 days
C) 24 days	D) 30 days

Answer & Explanation Answer: B) 21 days

Explanation:

(2 x 14) men +(7 x 14) boys = (3 x 11) men + (8 x 11) boys

=>5 men= 10 boys => 1man= 2 boys

Therefore, (2 men+ 7 boys) = (2 x 2 +7) boys = 11 boys

( 8 men + 6 boys) = (8 x 2 +6) boys = 22 boys.

Let the required number of days be x.

More boys , Less days (Indirect proportion)

More work , More days (Direct proportion)

$\begin{array}{r} \begin{matrix} B o y s & 22 : 11 \end{matrix} \\ \begin{matrix} W o r k & 1 : 3 \end{matrix} \end{array}\} ⋮ ⋮ 14 : x$

Therefore, (22 * 1 * x) = (11 * 3 * 14)

=> x = 21

Hence, the required number of days = 21

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Filed Under: Chain Rule

90 35920

Q:

The difference between the place value and the face value of 7 in the numeral 967452 is

A) 6393	B) 5831
C) 6993	D) 6339

Answer & Explanation Answer: C) 6993

Explanation:

(Place value of 7)-(face value of 7)
=7000-7=6993.

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Filed Under: Numbers

106 35885

Q:

The Indian Cricket team consists of 16 players. It includes 2 wicket keepers and 5 bowlers. In how many ways can a cricket eleven be selected if we have to select 1 wicket keeper and atleast 4 bowlers?

A) 1024	B) 1900
C) 2000	D) 1092

Answer & Explanation Answer: D) 1092

Explanation:

We are to choose 11 players including 1 wicket keeper and 4 bowlers or, 1 wicket keeper and 5 bowlers.

Number of ways of selecting 1 wicket keeper, 4 bowlers and 6 other players in $2 C_{1} * 5 C_{4} * 9 C_{6}$ = 840

Number of ways of selecting 1 wicket keeper, 5 bowlers and 5 other players in $2 C_{1} * 5 C_{5} * 9 C_{5}$ =252

Quantitative Aptitude - Arithmetic Ability Questions

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