6500+ Quantitative Aptitude Questions and Answers With Explanation

Q:

The ratio of petrol and kerosene in the container is 3:2 when 10 liters of the mixture is taken out and is replaced by the kerosene, the ratio become 2:3. Then total quantity of the mixture in the container is:

A) 25	B) 30
C) 45	D) cannot be determined

Answer & Explanation Answer: B) 30

Explanation:

pool : kerosene

3 : 2(initially)

2 : 3(after replacement)

$\frac{R e m a i n i n g Q u a n t i t y}{I n i t i a l Q u a n t i t y} = (1 - \frac{R e p l a c e d Q u a n t i t y}{T o t a l Q u a n t i t y})$

(for petrol) $\frac{2}{3} = (1 - \frac{10}{k})$

=> K = 30

Therefore the total quantity of the mixture in the container is 30 liters.

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Filed Under: Alligation or Mixture

83 33721

Q:

Two trains started at the same time, one from A to B and the other from B to A . If they arrived at B and A respectively 4 hours and 9 hours after they passed each other the ratio of the speeds of the two trains was

A) 2:1	B) 3:2
C) 4:3	D) 5:4

Answer & Explanation Answer: B) 3:2

Explanation:

Note : If two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively, then: (A's speed) : (B's speed) = (b : a)

Therefore, Ratio of the speeds of two trains = $\sqrt{9} : \sqrt{4}$ = 3 : 2

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Filed Under: Problems on Trains
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

76 33679

Q:

Find the volume (in cm3) of a right circular cone of diameter 7 cm and height 7 cm.

A) 69.06	B) 16.43
C) 11.15	D) 89.83

Answer & Explanation Answer: D) 89.83

Explanation:

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Filed Under: Volume and Surface Area
Exam Prep: Bank Exams

0 33666

Q:

A and B can do a piece of work in 30 days , while B and C can do the same work in 24 days and C and A in 20 days . They all work together for 10 days when B and C leave. How many days more will A take to finish the work?

A) 18 days	B) 24 days
C) 30 days	D) 36 days

Answer & Explanation Answer: A) 18 days

Explanation:

2(A+B+C)'s 1 day work = 1/30 + 1/24 + 1/20 = 1/8

=>(A+B+C)'s 1 day's work= 1/16

work done by A,B and C in 10 days=10/16 = 5/8

Remaining work= 3/8

A's 1 day's work= $(\frac{1}{16} - \frac{1}{24}) = \frac{1}{48}$

Now, 1/48 work is done by A in 1 day.

So, 3/8 work wil be done by A in =48 x (3/8) = 18 days

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Filed Under: Time and Work

138 33662

Q:

(x-2) men can do a piece of work in x days and (x+7) men can do 75% of the same work in (x-10)days. Then in how many days can (x+10) men finish the work?

A) 27 days	B) 12 days
C) 25 days	D) 18 days

Answer & Explanation Answer: B) 12 days

Explanation:

$\frac{3}{4} \times (x - 2) x = (x + 7) (x - 10)$

$\Rightarrow x^{2} - 6 x - 280 = 0$

=> x= 20 and x=-14

so, the acceptable values is x=20

Therefore, Total work =(x-2)x = 18 x 20 =360 unit

Now 360 = 30 x k

=> k=12 days

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Filed Under: Time and Work

77 33580

Q:

(2,14,16), (3,21,24), (8,56,64), (5,35,41)

The set that does NOT belong to the group is

A) (5,35,41)	B) (2,14,16)
C) (3,21,24)	D) (8,56,64)

Answer & Explanation Answer: A) (5,35,41)

Explanation:

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Filed Under: Odd Man Out
Exam Prep: Bank Exams

0 33557

Q:

Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of rajeev?

A) 12	B) 14
C) 22	D) 10

Answer & Explanation Answer: D) 10

Explanation:

Let Rajeev's present age be x years.

Rajeev's age after 15 years = (x + 15) years.

Rajeev's age 5 years back = (x - 5) years

Then ATQ,

x + 15 = 5 (x - 5)

x + 15 = 5x - 25

=> x = 10

Hence, Rajeev's present age = x = 10 years.

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Filed Under: Problems on Ages
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

57 33547

Q:

The angle between the minute hand and the hour hand of a clock when the time is 8:30

A) 80 Degrees	B) 75 Degrees
C) 60 Degrees	D) 105 Degrees

Answer & Explanation Answer: B) 75 Degrees

Explanation:

Angle traced by hour hand in 17/2 hrs = ${(\frac{360}{12} \times \frac{17}{2})}^{o}$ = 255

Angle traced by min hand in 30 min = ${(\frac{360}{60} \times 30)}^{o}$ = 180

Therefore, Required angle = (255 - 180) = $75^{o}$

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Filed Under: Clocks

76 33484

Quantitative Aptitude - Arithmetic Ability Questions

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