FACTS  AND  FORMULAE  FOR  AREA  QUESTIONS

 

 

FUNDAMENTAL CONCEPTS :

I. Results on Triangles:

1. Sum of the angles of  a triangle is 180o

2. The sum of any two sides of a triangle is greater than the third side.

3. Pythagoras Theorem : In a right - angled triangle,

Hypotenuse2=Base2+Height2

4. The line joining the mid-point of a side of a triangle to the opposite vertex is called the median.

5. The point where the three medians of a triangle meet, is called Centroid. The centroid divides each of the medians in the ratio 2 : 1.

6. In an Isosceles triangle, the altitude from the vertex bisects the base.

7. The median of a triangle divides it into two triangles of the same area.

8. The area of the triangle formed by joining the mid-points of the sides of a given triangle is one-fourth of the area of the given triangle.

 

II.Results on Quadrilaterals :


1. The diagonals of a parallelogram bisect each other

2. Each diagonal of a parallelogram divides it into two triangles of the same area.

3. The diagonals of a rectangle are equal and bisect each other.

4. The diagonals of a square are equal and bisect each other at right angles

5. The diagonals of a rhombus are unequal and bisect each other at right angles

6. A parallelogram and a rectangle on the same base and between the same parallels are equal in area.

7. Of all the parallelogram of given sides, the parallelogram which is a rectangle has the greatest area.

 

IMPORTANT FORMULAE

I. 

1. Area of a rectangle = (length x Breadth)

Length =AreaBreadth  and  Breadth=AreaLength

2. Perimeter of a rectangle = 2( length + Breadth)

 

 

II. Area of square = side2=12diagonal2 

 

III. Area of 4 walls of a room = 2(Length + Breadth) x Height

 

 

IV.

1. Area of a triangle =12×base×height

2. Area of a triangle = s(s-a)(s-b)(s-c), where a, b, c are the sides of the triangle and s=12a+b+c

3. Area of an equilateral triangle =34×side2

4. Radius of incircle of an equilateral triangle of side a=a23

5. Radius of circumcircle of an equilateral triangle of side a=a3

6. Radius of incircle of a triangle of area  and semi-perimeter s=s

 

 

V.

1. Area of a parallelogram = (Base x Height)

2. Area of a rhombus = 12×Product of diagonals

3. Area of a trapezium = 12×(sum of parallel sides)×distance between them

    

 

VI.

1. Area of a cicle = πR2, where R is the radius.

2. Circumference of a circle = 2πR.

3. Length of an arc = 2πRθ360, where θ is the central angle.

4. Area of a sector = 12arc×R=πR2θ360 

 

VII.

1. Area of a semi-circle = πR22

2. Circumference of a semi - circle = πR

Q:

In two triangles, the ratio of the areas is 4 : 3 and the ratio of their heights is 3 : 4. Find the ratio of their bases.

A) 13:9 B) 16:9
C) 15:9 D) 14:9
 
Answer & Explanation Answer: B) 16:9

Explanation:

Let the bases of the two triangles be x and y and their heights be 3h and 4h respectively.
Then, 12×x×3h12×y×4h=43xy=43×43=169 

 

Required ratio = 16 : 9.

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24 20252
Q:

The area of a square is 42.25 cm². Find its perimeter (in cm).

 

A) 52 B) 26
C) 28 D) 56
 
Answer & Explanation Answer: B) 26

Explanation:
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0 20226
Q:

The tangent at any point of the circle is _________________ to the radius through the point of contact.

 

A) parallel B) intersecting
C) perpendicular D) equal
 
Answer & Explanation Answer: C) perpendicular

Explanation:
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0 20189
Q:

A man runs round a circular field of radius 50m at the speed of 12 km/hr. What is the time taken by the man to take twenty rounds of the field?

A) 220/7 min B) 110/7 min
C) 90/7 min D) 230/7 min
 
Answer & Explanation Answer: A) 220/7 min

Explanation:

speed = 12 km/h = 12×518=103m/s 

 

distance covered = 20×2×227×50=440007m 

 

time taken  = distance /speed =  440007×310sec=4400×37×160min=2207min 

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31 19909
Q:

The no of revolutions a wheel of diameter 40cm makes in traveling a distance of 176m is

A) 240 B) 140
C) 40 D) 340
 
Answer & Explanation Answer: B) 140

Explanation:

distance covered in 1 revolution = 2πr = 2 x (22/7) x 20 = 880/7 cm
required no of revolutions = 17600 x (7/880) = 140

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21 19859
Q:

The breadth of a rectangular field is 60% of its length. If the perimeter of the field is 800 m.What is the area of the field?

A) 47500 B) 37500
C) 57500 D) 77500
 
Answer & Explanation Answer: B) 37500

Explanation:

Let length = x meters, then breadth = 0.6x 

Given that  perimeter = 800 meters 

=> 2[ x + 0.6x] = 800 

=> x = 250 m 

Length = 250m and breadth = 0.6 x  250 = 150m 

Area = 250 x 150 = 37500 sq.m

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19 19847
Q:

Which of the following represents the sides of an acute angled triangle?

 

A) 6, 9, 16   B) 7, 8, 10  
C) 5, 12, 13   D) None of these
 
Answer & Explanation Answer: B) 7, 8, 10  

Explanation:
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1 19847
Q:

The ratios of areas of two squares, one having its diagonal double than the other is

A) 2:1 B) 2:3
C) 3:1 D) 4:1
 
Answer & Explanation Answer: D) 4:1

Explanation:

ratio = 1/2×2d212d2=4:1

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49 19643