Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If (-1/2) * ( x - 5) + 3 = -5/2, then what is the value of x?

A) 16 B) 4
C) -6 D) -4
 
Answer & Explanation Answer: A) 16

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Q:

For which value of ‘g’ the linear graph of 6x + 12y +9 = 0 and 2x + gy + 3 = 0 has infinite number of solutions?

A) 3 B) 4
C) 6 D) 9
 
Answer & Explanation Answer: B) 4

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Q:

If (tanA + tanB)/(1 ­ tanAtanB) = x, then the value of x is

A) tan(A + B) B) tan(A -­ B)
C) cot(A + B) D) cot(A ­- B)
 
Answer & Explanation Answer: A) tan(A + B)

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Q:

If M = 0.1 + (0.1)2 + (0.01)2 and N = 0.3 + (0.03)2 + (0.003)2, then what is the value of M + N?

A) 0.411009 B) 0.413131
C) 0.313131 D) 0.131313
 
Answer & Explanation Answer: A) 0.411009

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Q:

What is the equation of the line whose y­-intercept is 4 and making an angle of 45° with the positive x-­axis?

A) x + y = -­4 B) x -­ y = 4
C) x + y = 4 D) x -­ y = ­-4
 
Answer & Explanation Answer: D) x -­ y = ­-4

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Q:

If 4(x + 1) - 3 < 3 - x < 2x + 5; then the value of x is

A) -1 B) 0
C) -2 D) 3
 
Answer & Explanation Answer: B) 0

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Q:

If (8 - 10x) - (13x - 2) = -9, then the value of x is

A) -19/23 B) 19/23
C) -1/23 D) 1/23
 
Answer & Explanation Answer: B) 19/23

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Q:

If sec2A cosec2A = x, then x is

A) sec2A + cosec2A + 2 B) tan2A + cot2A - 2
C) tan2A + cot2A + 2 D) sec2A + cosec2A - 2
 
Answer & Explanation Answer: C) tan2A + cot2A + 2

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