Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If xy = 56 and x2+ y2= 113, then what will be the value of (x + y)?

A) 29 B) 21
C) 36 D) 15
 
Answer & Explanation Answer: D) 15

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Q:

What is the value of cosec -150°?

A) -2 B) 2/√3
C) 2 D) -2/√3
 
Answer & Explanation Answer: A) -2

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Q:

A bag has Rs 30.8 in the form of 1 rupee, 50 paise and 10 paise coins in the ratio of 6:3:2. What is the number of 50 paise coins?

A) 8 B) 24
C) 12 D) 4
 
Answer & Explanation Answer: C) 12

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Q:

What is the value of sin (630 + A) + cos A?

A) √3/2 B) 1/2
C) 0 D) 2/√3
 
Answer & Explanation Answer: C) 0

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Q:

6 times a fraction is greater than 7 times its reciprocal by 11. What is the fraction?

A) 5/3 B) 7/3
C) 5/4 D) 4/5
 
Answer & Explanation Answer: B) 7/3

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Q:

1/(tanA + cotA) is equal to

A) (cosecA + sinA)(secA - cosA) B) √[(cosecA - sinA)(secA - cosA)]
C) √[(cosecA + sinA)(secA - cosA)] D) (cosecA - sinA)(secA - cosA)
 
Answer & Explanation Answer: D) (cosecA - sinA)(secA - cosA)

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Q:

If cosec 240° = x, then the value of x is

A) √2 B) 2
C) -2/√3 D) -√2
 
Answer & Explanation Answer: C) -2/√3

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Q:

If cosC + cosD = x, then value of x is

A) 2cos[(C+D)/2]cos[(C-D)/2] B) 2sin[(C+D)/2]sin[(C-D)/2]
C) 2cos[(C+D)/2]sin[(C-D)/2] D) 2sin[(C+D)/2]cos[(C-D)/2]
 
Answer & Explanation Answer: A) 2cos[(C+D)/2]cos[(C-D)/2]

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