Problems on Ages Questions

Q:

The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A ?

A) 12 B) 13
C) 14 D) 15
 
Answer & Explanation Answer: A) 12

Explanation:

(A+B) - (B-C) = 12 <=> A - C = 12.

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Q:

Present ages of Deepa and Hyma are in the ratio of 5:6 respectively. After four years, this ratio becomes 6: 7. What is the difference between their present ages?

A) 6 yrs B) 4 yrs
C) 8 yrs D) 2 yrs
 
Answer & Explanation Answer: B) 4 yrs

Explanation:

Let the present age of Deepa = 5p

Let the present age of Hyma = 6p

After four years their ratio = 6 : 7

=> 5p + 46p + 4 = 67

=> 35p + 28 = 36p + 24

=> p = 4

Therefore, the difference between their ages = 24 - 20 = 4 years.

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Q:

The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age og the youngest child ?

A) 8 yrs B) 16 yrs
C) 6 yrs D) 4 yrs
 
Answer & Explanation Answer: D) 4 yrs

Explanation:

Let the age of the youngest child is 'X' years.
Then the child elder than the yongest is 'X + 3' yrs
Since each have 3yrs difference upto 5 children
And given that
=> X + X+3 + X+6 + X+9 + X+12 = 50
=> 5X + 30 = 50
=> X = 4 yrs.

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Q:

5 years ago, the mother's age was 3 times of her son's age. 5 years hence, the ratio between the ages of mother and the son becomes 11:5. Find the mother's present age?

Answer

Let the present age's of mother be 'M' and that of her son be 'S'.


According to the given data in the question,


M - 5 = 3(S - 5)


F - 3S = -10  ...............(1)


Then given ,


M + 5 : S + 5 = 11 : 5 


=> 5M - 11S = 30 ..............(2)


 


From (1) & (2), we get


S = 20


Then by substituting S = 20 in (1) or (2), we get


M = 50.


 


Hence, the present age of mother is M = 50 years.

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7 4373
Q:

The age of Manisha and Sudeshna are in the ratio of 5 : 6 respectively. After 8 years the ratio  of their ages will be 7 : 8. What is the difference of their ages ?

A) 6 B) 4
C) 8 D) 10
 
Answer & Explanation Answer: B) 4

Explanation:

Let the age of Manisha and Sudeshna is 5x and 6x years respectively.

According to the given data,

5x+8/6x+8 = 7/8

42x + 56 = 40x + 64

x = 4

Required Difference of their ages = (6 × 4)  –  (5 × 4)

= 4 years.

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Q:

Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, then what will be the total of their present ages?

Answer

Let A's age 10 years ago be x years . Then B's age 10 years ago be 2x years





 Total of their present ages = x + 10 + 2x + 10


= 3x+20


= 3 * 5 + 20 = 35 years


 

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Q:

The ratio between present ages of Renuka and Sony is 5 : 4 . 4 years ago, Sony's age was 24 years. What will be Renuka's age after 5 years ?

A) 25 B) 30
C) 35 D) 40
 
Answer & Explanation Answer: D) 40

Explanation:

Present age of Sony = 24 + 4 = 28 years

After 5 years Renuka's age = 7×5 + 5 = 40 years

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Q:

The average of ages of threee persons is 60 years . Those ages are in the proportion of 1:2:3. what is the age of the youngest one among them?

Answer

Suppose the ages of three persons are x, 2x, 3x years respectively 





Hence, age of youngest person = x = 30 years.

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