Ratios and Proportions Questions

FACTS  AND  FORMULAE  FOR  RATIO  AND  PROPORTION  QUESTIONS

 

 

1. RATIO: The ratio of two quantities a and b in the same units, is the fraction a/b and we write it as a:b.

In the ratio a:b, we call a as the first term or antecedent and b, the second term or consequent.

Ex. The ratio 5: 9 represents 5/9 with antecedent = 5, consequent = 9.

Rule: The multiplication or division of each term of a ratio by the same non-zero number does not affect the ratio. Ex. 4: 5 = 8: 10 = 12: 15 etc. Also, 4: 6 = 2: 3.

 

2. PROPORTION : The equality of two ratios is called proportion

If a: b = c: d, we write, a: b :: c : d and we say that a, b, c, d are in proportion . Here a and d are called extremes, while b and c are called mean terms.

Product of means = Product of extremes.

Thus, a: b :: c : d <=> (b x c) = (a x d).

 

 3(i) Fourth Proportional : If a : b = c: d, then d is called the fourth proportional to a, b, c.

     (ii) Third Proportional : If a: b = b: c, then c is called the third proportional to a and b.

     (iii) Mean Proportional : Mean proportional between a and b is ab

 

 4. (i) COMPARISON OF RATIOS : We say that (a: b) > (c: d)  (a/b)>(c /d).

     (ii) COMPOUNDED RATIO : The compounded ratio of the ratios (a: b), (c: d), (e : f)  is    (ace: bdf)

 

5. (i) Duplicate ratio of (a : b) is a2:b2.

    (ii) Sub-duplicate ratio of (a : b) is (√a : √b).

    (iii)Triplicate ratio of (a : b) is a3:b3.

    (iv) Sub-triplicate ratio of (a : b) is a13: b13.

    (V) If ab=cd, thena+ba-b=c+dc-d (Componendo and dividendo)

 

 6. VARIATION:

(i) We say that x is directly proportional to y, if x = ky for some constant k and we write, xy

(ii) We say that x is inversely proportional to y, if xy = k for some constant k and we write, x1y

Q:

Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ?

A) 7 : 12 B) 8 : 13
C) 9 : 4 D) 2 : 5
 
Answer & Explanation Answer: B) 8 : 13

Explanation:

To get the solution that contains 1 part of milk and two parts of water,
they must be mixed in the ratio as
7x+6x/5y+11y = 1/2
26x = 16y
x/y = 16/26
x/y = 8/13

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19 9727
Q:

If k : l = 4 : 3 and l : m = 5 : 3, then find k : l : m ?

A) 18 : 24 : 11 B) 9 : 15 : 1
C) 20 : 15 : 9 D) 21 : 7 : 3
 
Answer & Explanation Answer: C) 20 : 15 : 9

Explanation:

Given k : l = 4 : 3
l : m = 5 : 3

Then k : l : m = 20 : 15 : 9

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12 9329
Q:

A mixture contains alcohol and water in the ratio 4:3. If 5 liters of water is added to the mixture, the ratio becomes 4:5. Find the quantity of alcohol in the given mixture.

A) 8 Liters B) 10 Liters
C) 18 Liters D) 22 Liters
 
Answer & Explanation Answer: B) 10 Liters

Explanation:

Let the quantity of alcohol and water be 4x liters and 3x liters respectively. Then,

 

(4x)/(3x+5) = 4/5

 

=> 20x = 4(3x+5) 

 

=> x = 2.5 

 

Quantity of alcohol = (4 * 2.5) liters = 10 liters.

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12 8547
Q:

Divide Rs.6500 among A,B and C so that after spending 90% , 75% and 60% of their respective saving were in the ratio of 3: 5: 6

Answer

A's spending 90%              \inline \therefore   saving = 10%


B's spending 75%              \therefore   saving = 25%


C's spending 60%              \inline \therefore   saving = 40%


Let us suppose A, B and C saves Rs. 3.5 and 6 respectively.


\inline \therefore 10% of A's saving = Rs.3


100% of A's saving = \inline \frac{3}{10}\times 100 = Rs. 30


25% of B's saving = Rs. 5


100% of B's saving = \inline \frac{5}{25}\times 100 = Rs. 20


40% of C's saving = Rs.6


100% of C's saving = \inline \frac{6}{40}\times 100 = Rs. 15


Divide Rs. 6500 in the ratio of 30 : 20 : 15 as


A's Share  =  \inline \frac{30}{65}\times 6500 = Rs. 3000


B's Share   = \inline \frac{20}{65}\times 6500 = Rs. 2000


C's Share  = \inline \frac{15}{65}\times 6500 = Rs. 1500

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65 8518
Q:

80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ? 

A) 120 lit B) 140 lit
C) 110 lit D) 150 lit
 
Answer & Explanation Answer: D) 150 lit

Explanation:

To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres.

=> the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres

However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity.

i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too.

Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.

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13 8210
Q:

If Rs. 782 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is:

A) Rs. 408 B) Rs. 204
C) Rs. 412 D) Rs. 220
 
Answer & Explanation Answer: B) Rs. 204

Explanation:

Given ratio = 1/2:2/3:3/4 = 6:8:9

1st part = 782 x 6/23 = Rs. 204.

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10 8181
Q:

A sum is divided among K, L and M in such a way that for each rupee K gets, L gets 45 paisa and M gets 30 paisa. If the share of L is Rs. 27,  what is the total amount  ?

A) Rs. 159 B) Rs. 96
C) Rs. 147 D) Rs. 105
 
Answer & Explanation Answer: D) Rs. 105

Explanation:

K : L : M = 100 : 45 : 30
              = 20 : 9 : 6

Given L share is 27

=> 9  ------  27
      35 ------  ?

      => 105

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11 8072
Q:

If (2a + 3b)/(5a - 3b) = 23/5 , then the value of ba is ?

A) 5 B) 4
C) 20 D) 28
 
Answer & Explanation Answer: C) 20

Explanation:

Given (2a + 3b)/(5a - 3b) = 23/5
=> 10a + 15b = 115a - 69b
=> 105a = 84b => 5a = 4b
a/b = 4/5 => a=4 & b=5
=> bxa = 5x4 = 20.

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7 7997