Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If Cot θ = 21/20, then what is the value of Sec θ?

A) 29/21 B) 21/29
C) 29/20 D) 20/29
 
Answer & Explanation Answer: A) 29/21

Explanation:
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1 1916
Q:

If A = 30°, B = 60° and C = 135°, then what is the value of sin3A + cos3B + tan3C  3sin A cos B tan C?

A) 0 B) 1
C) 8 D) 9
 
Answer & Explanation Answer: A) 0

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1 1915
Q:

In each of the following questions two equations I and II are given. Solve both the equations and give answer:
I. x2+2x-195=0II. y2+30y+225=0

A) x = y or relation can’t be established between x and y B) x > y
C)  x < y D)  x ≥ y
 
Answer & Explanation Answer: D)  x ≥ y

Explanation:

 I. x2 + 2x - 195 = 0 = (x+15) (x-13) => x = -15, 13

II. y2 + 30y + 225 = 0 = (y+15) (y+15) => y = -15, -15

So x ≥ y

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0 1914
Q:

If a2sec2x - b2tan2x = c2 then the value of sec2x + tan2x is equal to (assume b2 ≠ a2 )

A) b2-a2+2c2b2+a2 B) b2+a2-2c2b2-a2
C) b2-a2-2c2b2+a2 D) b2-a2b2+a2+2c2
 
Answer & Explanation Answer: B) b2+a2-2c2b2-a2

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0 1912
Q:

If a--b = 4 and ab = 45, find the value of a3 - b3

A) 604 B) 370
C) 253 D) 199
 
Answer & Explanation Answer: A) 604

Explanation:

(a  b)2 = a2 + b2 -2ab  16 = a2 + b2  90  a2 + b2 = 106 a3  b3 = (a  b) (a2 + b2 + ab)  a3  b3 = 4 X (106 + 45)  a3  b3 = 4 X 151  a3  b3 = 604

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0 1908
Q:

What is the sum of a3+b3+c3-3abc, when the value of a=4, b=2 and c=-6?

A) 0 B) 2
C) 4 D) 6
 
Answer & Explanation Answer: A) 0

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0 1908
Q:

P(4,2) and R(-2,0) are vertices of a rhombus PQRS. What is the equation of diagonal QS.

A) x - 3y = -2 B) 3x + y = 4
C) 3x + y = -4 D) x - 3y = 2
 
Answer & Explanation Answer: B) 3x + y = 4

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1 1908
Q:

An army lost 10% of its men in war, 10% of the remaining died due to disease and 10% of the rest were declared disabled. Thus the strength of the army was reduced to 7,29,000 active men. The original strength of the army was

A) 1500000 B) 1000000
C) 1200000 D) 1100000
 
Answer & Explanation Answer: B) 1000000

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0 1907