Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

If Cot θ = 21/20, then what is the value of Sec θ?

A) 29/21 B) 21/29
C) 29/20 D) 20/29
 
Answer & Explanation Answer: A) 29/21

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1 1915
Q:

Reduce 3596 / 4292 to lowest terms.

A) 29/37 B) 17/43
C) 31/37 D) 19/23
 
Answer & Explanation Answer: C) 31/37

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0 1915
Q:

In each of the following questions two equations I and II are given. Solve both the equations and give answer:
I. x2+2x-195=0II. y2+30y+225=0

A) x = y or relation can’t be established between x and y B) x > y
C)  x < y D)  x ≥ y
 
Answer & Explanation Answer: D)  x ≥ y

Explanation:

 I. x2 + 2x - 195 = 0 = (x+15) (x-13) => x = -15, 13

II. y2 + 30y + 225 = 0 = (y+15) (y+15) => y = -15, -15

So x ≥ y

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0 1911
Q:

If a2sec2x - b2tan2x = c2 then the value of sec2x + tan2x is equal to (assume b2 ≠ a2 )

A) b2-a2+2c2b2+a2 B) b2+a2-2c2b2-a2
C) b2-a2-2c2b2+a2 D) b2-a2b2+a2+2c2
 
Answer & Explanation Answer: B) b2+a2-2c2b2-a2

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0 1908
Q:

If a--b = 4 and ab = 45, find the value of a3 - b3

A) 604 B) 370
C) 253 D) 199
 
Answer & Explanation Answer: A) 604

Explanation:

(a  b)2 = a2 + b2 -2ab  16 = a2 + b2  90  a2 + b2 = 106 a3  b3 = (a  b) (a2 + b2 + ab)  a3  b3 = 4 X (106 + 45)  a3  b3 = 4 X 151  a3  b3 = 604

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0 1906
Q:

P(4,2) and R(-2,0) are vertices of a rhombus PQRS. What is the equation of diagonal QS.

A) x - 3y = -2 B) 3x + y = 4
C) 3x + y = -4 D) x - 3y = 2
 
Answer & Explanation Answer: B) 3x + y = 4

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1 1906
Q:

If cot(A/2) = x, then the value of x is

A) √[(1 + cosA)/(1 -­ cosA)] B) cosecA -­ cotA
C) √[(1 -­ cosA)/2] D) √[(1 + cosA)/2]
 
Answer & Explanation Answer: A) √[(1 + cosA)/(1 -­ cosA)]

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0 1902
Q:

What is the simplified value of Sec ACot A + Tan A2 ?

A) 1 – cos2A B) 2sin2A
C) sec2A D) 0
 
Answer & Explanation Answer: A) 1 – cos2A

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0 1902