Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

What is the value of 1xp-q+1+1xq-p+1?

A) 0 B) 1
C) x D) cant determine
 
Answer & Explanation Answer: B) 1

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Q:

What is the value of [(tan 5θ + tan 3θ)/4 cos 4θ (tan 5θ – tan 3θ)]?

A) sin 2θ B) cos 2θ
C) tan 4θ D) cot 2θ
 
Answer & Explanation Answer: B) cos 2θ

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Q:

In ΔABC, D and E are points on side AB and AC respectively. DE is parallel to BC. If lengths of AD, DB and DE are 8 cm, 6 cm and 7.2 cm respectively, find length of BC?

A) 12.6 cm B) 9.3 cm
C) 8.1 cm D) 5.4 cm
 
Answer & Explanation Answer: A) 12.6 cm

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Q:

The sum of two numbers is 7 and the sum their squares is 23, their product is equal to:

A) 10 B) 11
C) 12 D) 13
 
Answer & Explanation Answer: D) 13

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Q:

Point A (4 , 2) divides segment BC in the ratio 2:5. Co-ordinates of B are (2 , 6) and C are (7 , y). What is the value of y?

A) 8 B) -8
C) 6 D) -6
 
Answer & Explanation Answer: B) -8

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Q:

If 4x2= 152- 92, then value of x is

A) 9 B) 6
C) 3 D) 12
 
Answer & Explanation Answer: B) 6

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Q:

If (5x – y)/(5x + y) = 3/7, then what is the value of (4x2 + y2  4xy)/(9x2 + 16y2 + 24xy) ?

A) 0 B) 3/7
C) 18/49 D) 1/6
 
Answer & Explanation Answer: A) 0

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Q:

Two equal circles intersect such that each passes through the centre of the other. If the length of the common chord of the circles is 10√3 cm, then what is the diameter of the circle?

A) 10 cm B) 15 cm
C) 20 cm D) 30 cm
 
Answer & Explanation Answer: C) 20 cm

Explanation:

Let there be 2 circles with centre O1 and OAB is the common chord

Since both passes through the center of each other as shown in figure

So O1O is the radius of both

Let O1O = r = AO1= AO

AX = AB / 2 = 5√3 cm (since OX perpendicular to chord bisects it)

AOO1 forms an equilateral triangle with on side = radius = r

Sin 60 = √3/2 = AX / AO = 5√3/r

So r = 10 cm

So diameter = 20 cm

 

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