Simplification Questions

FACTS  AND  FORMULAE  FOR  SIMPLIFICATION  QUESTIONS

 

 

1. BODMAS Rule: This rule depicts the correct sequence in which the operations are to be executed,so as to find out the value of a given expression. Here, 'B' stands for bracket , 'O' for of , 'D' for division and 'M' for multiplication, 'A' for addition and 'S' for subtraction.

Thus, in simplifying an expression, first of all the brackets must be removed, strictly in the order(), {} and [].

After removing the brackets, we must use the following operations strictly in the order:

(1) of    (2)division   (3) multiplication   (4)addition   (5)subtraction.

 Modulus of a real number : Modulus of a real number a is defined as |a| = aif a>0-aif a<0

 

2. Virnaculum (or bar) : When an expression contains Virnaculum, before applying the ‘BODMAS’ rule, we simplify the expression under the Virnaculum.

Q:

Mr. Ankit is on tour to Siachin and he has Rs. 360 for his expenditure. If he exceeds his tour by 4 days, he must trim down his daily expenditure by Rs.3. Forhow many days is Mr. Ankit is on tour?

A) 20 B) 22
C) 24 D) 26
 
Answer & Explanation Answer: A) 20

Explanation:
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Q:

If x = √2+1, then the value of x4-1/x4

A) 8√2 B) 18√2
C) 6√2 D) 24√2
 
Answer & Explanation Answer: D) 24√2

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Q:

What is the value of 34+122 ?

A) 13 B) 15
C) 17 D) 19
 
Answer & Explanation Answer: B) 15

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Q:

If (x + y)2 = xy + 1 and x3  y3 = 1, then what is the value of x – y?

A) 1 B) 0
C) -1 D) 2
 
Answer & Explanation Answer: A) 1

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Q:

If x+1x=5, then 6xx2+x+1 value is

A) 3 B) 2
C) 1 D) 0
 
Answer & Explanation Answer: C) 1

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Q:

If (x/5) + (5/x) = – 2, then what is the value of x3?

A) –125 B) 5
C) 1/125 D) 625
 
Answer & Explanation Answer: A) –125

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Q:

In the question, two equations I and II are given. You have to solve both the equations and give answer

x2-11x+28=0y2-18y+81=0

A) x > y B) x < y
C)  x=y, or relation cannot be established between x and y D) x ≥ y
 
Answer & Explanation Answer: B) x < y

Explanation:

x2 – 11x + 28=0

x2 – 7x – 4x + 28=0

x (x-7) – 4 (x-7)=0

(x-4) (x-7)=0 x=4, 7

y2 – 18y + 81=0

y2 –9y – 9y + 81=0

y (y-9) – 9 (y-9)=0

(y-9) (y-9)=0 y=9, 9

So, x<y.

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Q:

The sum of 6xy(2x - 4z) , 3yz(2x - 3z) and 4xz(3y - 2y2) is

A) 12x2y - 6xyz - 9yz2 + 8xy2z B) 12x2y - 6xyz + 9yz2 - 8xy2z
C) 12x2y - 6xyz - 9yz2 - 8xy2z D) 12x2y + 6xyz - 9yz2 - 8xy2z
 
Answer & Explanation Answer: C) 12x2y - 6xyz - 9yz2 - 8xy2z

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