255+ Data Interpretation Questions and Answers With Explanation

Q:

The following table represents the rainfall (in mm) of five states from June to September in a year.

Consider the information and answer questions based on it.

Which state shows a gradual increase in its rainfall from June to September?

A) HP	B) WB
C) GA	D) TN

Answer & Explanation Answer: C) GA

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Q:

Study the following graph carefully and answer the questions given below:

Distribution of candidates who were enrolled for MBA entrance exam and the candidates (out of those enrolled) who passed the exam in different institutes:

1. What percentage of candidates passed the Exam from institute T out of the total number of candidates enrolled from the same institute?

A. 50% B. 62.5% C. 75% D. 80%

2. Which institute has the highest percentage of candidates passed to the candidates enrolled?

A. Q B. R C. V D. T

3. The number of candidates passed from institutes S and P together exceeds the number of candidates enrolled from institutes T and R together by:

A. 228 B. 279 C. 399 D. 407

4. What is the percentage of candidates passed to the candidates enrolled for institutes Q and R together?

A. 68% B. 80% C. 74% D. 65%

5. What is the ratio of candidates passed to the candidates enrolled from institute P?

A. 9:11 B. 14:17 C. 6:11 D. 9:17

Answer

1. ANSWER : C

Explanation - Required percentage= $\frac{9 % o f 5700}{8 % o f 8550} \times 100$ % = $\frac{9 \times 5700}{8 \times 8550} \times 100$ % = 75%

2. ANSWER : B

Explanation - The percentage of candidates passed to candidates enrolled can be determined for each institute as under:

P = $\frac{18 % o f 5700}{22 % o f 8550} \times 100$ % = 54.55%

Q = $\frac{17 % o f 5700}{15 % o f 8550} \times 100$ % = 75.56%

R = $\frac{13 % o f 5700}{10 % o f 8550} \times 100$ % = 86.67%

S = $\frac{16 % o f 5700}{17 % o f 8550} \times 100$ % = 62.75%

T = $\frac{9 % o f 5700}{8 % o f 8550} \times 100$ % = 75%

V= $\frac{15 % o f 5700}{12 % o f 8550} \times 100$ % = 83.33%

X= $\frac{12 % o f 5700}{16 % o f 8550} \times 100$ % = 50%

Highest of these is 86.67% corresponding to institute R.

3. ANSWER : C

Explanation - Required difference = [(16% + 18%) of 5700] - [(8% + 10%) of 8550]

= [(34% of 5700) - (18% of 8550)]

= (1938 - 1539)

= 399

4. ANSWER : B

Explanation - Candidates passed from institutes Q and R together = [(13% + 17%) of 5700] = 30% of 57000.

Candidates enrolled from institutes Q and R together = [(15% + 10%) of 8550] = 25% of 8550.

Required Percentage = $\frac{30 % o f 5700}{25 % o f 8550} \times 100$ % = 80%

5. ANSWER : C

Explanation - Required ratio = $\frac{18 % o f 5700}{22 % o f 8550}$ = 6/11

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Q:

Read the given chart and answer the following question.

In south, what is the percentage of seats won by party A (round to one decimal)?

A) 30%	B) 30.8%
C) 30.5%	D) 31%

Answer & Explanation Answer: B) 30.8%

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Q:

Refer the below data table and answer the following question.

What is the average bonus in Rs. ?

A) 7720005	B) 200000
C) 514667	D) 268000

Answer & Explanation Answer: C) 514667

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Q:

Study the following table carefully and answer the questions based on it.

The following table shows the domestic sales of cars of five manufacturers from 2005 to 2010.
(All the figures are in thousands)

During 2010, the sales of which manufacturer has shown the maximum percentage increase over the previous year?

A) L	B) M
C) N	D) P

Answer & Explanation Answer: C) N

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Q:

Refer the below table and answer the following question.

The chart shows India's exports in 2015. Steel was what percent of total exports?

A) 26.71 percent	B) 29.21 percent
C) 31.71 percent	D) 24.21 percent

Answer & Explanation Answer: A) 26.71 percent

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Q:

The following table shows the number of new employees added to different categories of employees in a company and also the number of employees from these categories who left the company every year

1.What is the difference between the total number of Technicians added to the Company and the total number of Accountants added to the Company during the years 1996 to 2000?

A. 128 B. 112 C. 96 D. 88

2. What was the total number of Peons working in the Company in the year 1999?

A. 1312 B. 1192 C. 1088 D. 968

3. For which of the following categories the percentage increase in the number of employees working in the Company from 1995 to 2000 was the maximum?

A. Managers B. Technicians C. Operators D. Accountants

4. What is the pooled average of the total number of employees of all categories in the year 1997?

A. 1325 B. 1195 C. 1265 D. 1235

5. During the period between 1995 and 2000, the total number of Operators who left the Company is what percent of total number of Operators who joined the Company?

A. 19% B. 21% C. 27% D. 29%

Answer

1. ANSWER : D

Explanation - Required difference

= (272 + 240 + 236 + 256 + 288) - (200 + 224 + 248 + 272 + 260)

= 88.

2. ANSWER : B

Explanation - Total number of Peons working in the Company in 1999

= (820 + 184 + 152 + 196 + 224) - (96 + 88 + 80 + 120)

= 1192.

3. ANSWER : A

Explanation - Number of Managers working in the Company:

In 1995 = 760.
In 2000 = (760 + 280 + 179 + 148 + 160 + 193) - (120 + 92 + 88 + 72 + 96)= 1252.

Therefore, Percentage increase in the number of Managers

= $\frac{(1252 - 760)}{760} \times 100$ %= 64.74%

Number of Technicians working in the Company:
In 1995 = 1200.
In 2000 = (1200 + 272 + 240 + 236 + 256 + 288) - (120 + 128 + 96 + 100 +112) = 1936.

Therefore, Percentage increase in the number of Technicians

= $\frac{(1936 - 1200)}{1200} \times 100$ % = 61.33%

Number of Operators working in the Company:

In 1995 = 880.
In 2000 = (880 + 256 + 240 + 208 + 192 + 248) - (104 + 120 + 100 + 112 + 144) = 1444.

Therefore, Percentage increase in the number of Operators

= $\frac{(1444 - 880)}{880} \times 100$ % = 64.09%

Number of Accountants working in the Company:

In 1995 = 1160.
In 2000 = (1160 + 200 + 224 + 248 + 272 + 260) - (100 + 104 + 96 + 88 + 92) = 1884.

Therefore, Percentage increase in the number of Accountants

= $\frac{(1884 - 1160)}{1160} \times 100$ % = 62.14%

Number of Peons working in the Company:

In 1995 = 820.
In 2000 = (820 + 184 + 152 + 196 + 224 + 200) - (96 + 88 + 80 + 120 + 104) = 1288.

Therefore, Percentage increase in the number of Peons

= $\frac{(1288 - 820)}{820} \times 100$ % = 57.07%

Clearly, the percentage increase is maximum in case of Managers.

4. ANSWER : B

Explanation - Total number of employees of various categories working in the Company in 1997 are:

Managers = (760 + 280 + 179) - (120 + 92) = 1007.

Technicians = (1200 + 272 + 240) - (120 + 128) = 1464.

Operators = (880 + 256 + 240) - (104 + 120) = 1152.

Accountants = (1160 + 200 + 224) - (100 + 104) = 1380.

Peons = (820 + 184 + 152) - (96 + 88) = 972.

Therefore, Pooled average of all the five categories of employees working in the Company in 1997 = 1/5 x (1007 + 1464 + 1152 + 1380 + 972)

= 1/5 x (5975)

= 1195.

5. ANSWER : D

Explanation - Total number of Operators who left the Company during 1995 - 2000

= (104 + 120 + 100 + 112 + 144)

= 580.

Total number of Operators who joined the Company during 1995 - 2000

= (880 + 256 + 240 + 208 + 192 + 248

= 2024.

Therefore, Required Percentage

= (580/2024)x100% = 28.66% ~= 29%.

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Q:

The following table shows the number of children in each house of a society.

What is the average number of children per house?

A) 1.65	B) 1.9
C) 1.15	D) 1.4

Quantitative Aptitude - Data Interpretation Questions

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