Number Series Questions

Q:

Find the missing term in the following series ?

10000, 11000, 9900, 10890, ?, 10781

A) 10423 B) 9801
C) 10241 D) 9712
 
Answer & Explanation Answer: B) 9801

Explanation:

Clearly, alternatively we add and subtract 10% of a term to obtain the next term of the series.
Thus, 10000 + (10% of 10000)= 11000;
11000 - (10% of 11000) = 9900;
 9900 + (10% of 9900)  = 10890;
10890 - (10% of 10890) = 9801.
 9801 + (10% of 9801)  = 9801+980 = 10781.
So, missing term = 10890- (10% of 10890)= 9801.

Report Error

View Answer Report Error Discuss

Filed Under: Number Series
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
Job Role: Analyst , Bank Clerk , Bank PO

90 61328
Q:

Find the wrong number in the series

7, 28, 63, 124, 215, 342, 511

A) 28 B) 124
C) 215 D) 342
 
Answer & Explanation Answer: A) 28

Explanation:

Here the number follows the given rule 

 23-1, 33-1, 43-1, 53-1, ...

 

But 28 has been given in problem series.

 

so 28 is wrong number.

Report Error

View Answer Report Error Discuss

Filed Under: Number Series
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank PO

126 60834
Q:

1, 2, 3, 10, ?, 9802

A) 99 B) 199
C) 299 D) 999
 
Answer & Explanation Answer: A) 99

Explanation:

2 = 12 + 13 = 22 - 110 = 32 + 1Now 102 - 1 = 999802 = 992 + 1

 

Report Error

View Answer Report Error Discuss

Filed Under: Number Series
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

842 57527
Q:

Which fraction comes next in the sequence

23, 13, 527, 781, ?

A) 1/27 B) 11/278
C) 9/48 D) 7/123
 
Answer & Explanation Answer: A) 1/27

Explanation:

Clearly, the numerators of the fractions in the given sequence follow the series of 2, 3, 5, 7,... and the denominator follows 3, 9, 27, 81, 243, ...
Then, the next term in the given sequence is  935 = 9243 = 127 .

Report Error

View Answer Report Error Discuss

Filed Under: Number Series
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
Job Role: Bank PO , Bank Clerk , Analyst

27 55510
Q:

prp  qrp  prr  pqr  qrp  rpr  qqr  rpr  qpr  qrr qpr  qpr

If every third letter starting from the left is replaced by a number beginning with 1 then which letter/ number will be 16th from the right?

A) q B) r
C) 6 D) 7
 
Answer & Explanation Answer: D) 7

Explanation:

New sequence is as follows:

pr1  qr2  pr3  pq4  qr5  rp6  qq7  rp8  qp9  qr10  qp11  qp12

16th from the right  end is 7

Report Error

View Answer Report Error Discuss

Filed Under: Number Series

8 54337
Q:

In the following question, select the missing number from the given series.

 

13, 22, 66, ?, 225, 234, 702, 711

 

A) 65 B) 75
C) 80 D) 70
 
Answer & Explanation Answer: B) 75

Explanation:
Report Error

View Answer Report Error Discuss

Filed Under: Number Series
Exam Prep: Bank Exams

3 53481
Q:

Find the next number in the given number series?

10, 6, 8, 15, ?

A) 34 B) 24
C) 28 D) 30
 
Answer & Explanation Answer: A) 34

Explanation:

The given number series is 10, 6, 8, 15, ?

10

10 x 0.5 + 1 = 6

6 x 1 + 2 = 8

8 x 1.5 + 3 = 15

15 x 2 + 4 = 34

 

Hence, the next number in the given series is 34.

Report Error

View Answer Report Error Discuss

Filed Under: Number Series
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

9 53224
Q:

Which Number would come in place of the underline mark in the series.

3, 9, 21, ___ , 93

A) 39 B) 45
C) 48 D) 51
 
Answer & Explanation Answer: B) 45

Explanation:

First difference is 6 and second is 12. But if we take third as 18, then fourth difference will be 24. Then 93 can not be the last term.

So we have to take the difference as 6, 12, 24 and 48. 

So Answer is 21+24 = 45 

Report Error

View Answer Report Error Discuss

Filed Under: Number Series

18 52640