Arithmetical Reasoning Questions

Here given formula is 

a2 + b2 + c2 -ab- bc - ca = 0

and it is possible if and only if a = b = c.

From the trial and error method, 

1) Let a = b = c = 1

Now substitute these values of a, b, c in the above formula.

We get 1 + 1 + 1 - 1 - 1 - 1 = 3 - 3 = 0

2) Now, let a = b = c = 4

Now substitute these values of a, b, c in the above formula.

We get 16 + 16 + 16 - 16 - 16 - 16 = 48 - 48 = 0.

Hence, it is possible that 

a2 + b2 + c2 -ab- bc - ca = 0 iff a = b = c.

A tangent contains ZERO chords, as it touches the circle at only one point.

Hence, it does not contain any chord.

Let R, G and B represent the number of balls in red, green and blue boxes respectively.

Then, .

R + G + B = 108 ...(i),

G + R = 2B ...(ii)

B = 2R ...(iii)

From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.

Putting G = 3R and B = 2R in (i), we get:

R + 3R + 2R = 108 6R = 108 R = 18.

Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.

Indeterminate are those,which mathematics can’t determine.

Because we don’t actually know which one is the exact answer for this due to having lots of results for this.

Explanation::

• Let us think by this analogy that,

0 / 1 = 0

0 / 2 = 0

…………

………..

we can say 0 / n = 0 from this we can write, 0/0 = 0

• Again, another analogy,(from limiting concept of 1/0 = infinity)

1 / 0 = +∞ or -∞

2 /0 = +∞ or -∞

………

.…….

we can say 0 / 0 = ∞

• Again, another analogy,

1 / 1 = 1

2/2 = 1

.……..

………..

we can say, 0/0 = 1

Now, you see it’s confusing. Every analog is mathematically correct then which one is the right answer for 0/0.  Therefore Mathematics can’t determine this fact.

So, 0/0 is indeterminate.

Binary system is what the representation uses only two digits 0 & 1.

It uses only the powers of 2.