Arithmetical Reasoning Questions

9 tens 10 ones equals

=> 9 x 10 + 10 x 1

=> 90 + 10

=> 100.

First ten odd numbers form an arithmetic progression of the form
1,3,5,7,9......
here a = first term = 1
d = common difference = 2
Average of first n numbers = (2a + (n - 1)d)/2
n th term of the AP = a + (n - 1)d
Substituting a = 1, d = 2 and n = 10 in the above formulas
average of first 10 numbers = 10
10 th term of the AP = 19
Therefore average of first 10 terms is 19 - 10 = 9 greater than
the last term. Hence the average is greater than the sum by
9/19 X 100 = 900/19 %

Two angles whose sum is 180 degrees are called supplementary angles.

Let number of bangles kushi purchase of each type = x

From the given data,

34x + 42x + 6x = 1722

x = 1722/82 = 21.

15 girls are absent => b = 2(g-15)...... eqn...(1)

45 boys are absent => g - 15 = 5(b-45).....eqn...(2)

=> g = 5(b-45) + 15

=> b = 2((5(b-45)+15)-15)

=> b = 2(5b - 225 + 15 - 15)

=> b = 2(5b-225)

=> b = 10b - 450

=> 9b = 450

=> b = 50

so from equation(2)

g - 15 = 5(b - 45)

=> g - 15 = 5(50-45)

=> g - 15 = 5(5)

=> g = 25 + 15

=> g = 40

Therefore, the number of boys = 50 and girls = 40

Here given 120 men = 200 children

therefore 1 child = 3/5 of Man------ step I

Now given that the food was consumed by 150 children

From step I we get 150 children =90 Men ( 1 child = 3/5 Man ie , 150 X 3/5 = 90)
So the food is for (120-90) men = 30 Men

The Multiples of 18 are 18, 36, 54, 72, 90, 108, 126, ....

• Multiples of 18 are nothing but numbers which are divisible by 18 leaving remainder 0.

• An infinite number of multiples of 18 can be achieved by adding 18 to each subsequent multiple.