Exams Questions and Answers

Q:

Select the related word/letters/number from the given alternatives.

FG : UT : : HI : ?

A) HI	B) GH
C) SR	D) ED

Answer & Explanation Answer: C) SR

Explanation:

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Filed Under: Analogy
Exam Prep: Bank Exams

0 35808

Q:

In the following question, select the related number from the given alternatives.

5 : 124 : : 6 : ?

A) 215	B) 216
C) 217	D) 220

Answer & Explanation Answer: A) 215

Explanation:

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Filed Under: Analogy
Exam Prep: AIEEE , Bank Exams , CAT

0 35777

Q:

In Microsoft Word, ____________ view shows how the document would look when it is printed.

A) Web Layout	B) Normal Layout
C) Reading Layout	D) Print Layout

Answer & Explanation Answer: B) Normal Layout

Explanation:

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Filed Under: Computer
Exam Prep: Bank Exams

4 35773

Q:

Select the related word/letters/number from the given alternatives.

TC : NF : : QM : ?

A) JY	B) IY
C) HY	D) KP

Answer & Explanation Answer: D) KP

Explanation:

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Filed Under: Analogy
Exam Prep: Bank Exams

2 35769

Q:

The dimensions of a room are 10m x 7m x 5m. There are 2 doors and 3 windows in the room. The dimensions of the doors are 1m x 3m. One window is of size 2m x 1.5m and the other 2 windows are of size 1m x 1.5m. The cost of painting the walls at Rs. 3 per sq m is

A) Rs.174	B) Rs.274
C) Rs.374	D) Rs.474

Answer & Explanation Answer: D) Rs.474

Explanation:

Area of 4 walls = 2(l+b)h
=2(10+7) x 5 = 170 sq m
Area of 2 doors and 3 windows = 2(1x3)+(2x1.5)+2(1x1.5) = 12 sq m
area to be planted = 170 -12 = 158 sq m

Cost of painting = Rs. 158 x 3 = Rs. 474

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

37 35754

Q:

Select the related word/letters/number from the given alternatives.

JY : 35 : : RT : ?

A) 48	B) 38
C) 35	D) 24

Answer & Explanation Answer: B) 38

Explanation:

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Filed Under: Analogy
Exam Prep: Bank Exams

0 35732

Q:

The altitude drawn to the base of an isosceles triangle is 8cm and the perimeter is 32cm. Find the area of the triangle?

A) 50	B) 60
C) 70	D) 80

Answer & Explanation Answer: B) 60

Explanation:

let ABC be the isosceles triangle, the AD be the altitude

Let AB = AC = x then BC= 32-2x [because parameter = 2 (side) + Base]

since in an isoceles triange the altitude bisects the base so

BD = DC = 16-x

In a triangle ADC, ${(A C)}^{2} = {(A D)}^{2} + {(D C)}^{2}$

$x^{2} = 8^{2} + {(16 - x)}^{2}$ $\Rightarrow x = 10$

BC = 32-2x = 32-20 = 12 cm

Hence, required area = $\frac{1}{2} * B C * A D$ = $\frac{1}{2} * 12 * 10$ = 60 sq cm

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Filed Under: Area
Exam Prep: Bank Exams
Job Role: Bank PO

69 35727

Q:

Quantitatively, the inertia of an object is measured by ______________.

A) its weight	B) the product of its mass and velocity
C) its mass	D) the product of its mass and acceleration

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