Exams Questions and Answers

Q:

Which HTML attribute is used to define inline styles?

A) <header>	B) <strong>
C) <style>	D) <alt>

Answer & Explanation Answer: C) <style>

Explanation:

The style attribute specifies an inline style for an element. The style attribute will override any style set globally,

e.g. styles specified in the <style> tag or in an external style sheet.

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Filed Under: Web Technology
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Q:

Read the following information and answer the following questions below.

Bindu is standing exactly in the middle of a line of girls. Asha is 6th to the left of Bindu and Ritu is 16th to Bindu's right.

What should be the minimum number of girls in the line?

A) 22	B) 28
C) 33	D) 32

Answer & Explanation Answer: C) 33

Explanation:

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Filed Under: Arithmetical Reasoning
Exam Prep: Bank Exams

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Q:

The simple interest on Rs.10 for 4 months at the rate of 3 paise per month is

A) 0.3 Paise	B) 1.2 Paise
C) 30 Paise	D) 3 Paise

Answer & Explanation Answer: B) 1.2 Paise

Explanation:

Given Principal amount P = Rs. 10

Time T = 4 months

Rate of interest R = 3 ps

Interest I = PTR/100 = (10 x 4 x 3)/100 = 12/10 = 1.2 paise.

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Filed Under: Simple Interest
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Q:

What do eukaryotic cells have that prokaryotic cells do not?

A) Nucleus	B) Cytoplasm
C) Ribosomes	D) DNA

Answer & Explanation Answer: A) Nucleus

Explanation:

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Eukaryotic cells contain membrane-bound organelles, including a nucleus. Eukaryotes can be single-celled or multi-celled, such as you, me, plants, fungi, and insects.

Whereas Prokaryotic cells do not contain a nucleus or any other membrane-bound organelle. Bacteria are an example of prokaryotes.

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Filed Under: Biology
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Q:

A man covers half of his journey by train at 60 km/hr, half of the remaining by bus at 30 km/hr and the rest by cycle at 10 km/hr. Find his average speed during the entire journey?

A) 32 kmph	B) 20 kmph
C) 18 kmph	D) 24 kmph

Answer & Explanation Answer: D) 24 kmph

Explanation:

Let the total distance of the journey of a man = d kms

Now, the average speed of the entire journey = $\frac{d}{\frac{d}{120} + \frac{d}{120} + \frac{d}{40}}$ = 24 kmph.

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Filed Under: Time and Distance
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30 17396

Q:

A car mechanic purchased four old cars for Rs. 1 lakh. He spent total 2 lakh in the maintenance and repairing of these four cars. what is the average sale price of the rest three cars to get 50% total profit if he has already sold one of the four cars at Rs. 1.2 lakh?

A) 1.5 lakh	B) 1.1 lakh
C) 1.2 lakh	D) 1.65 lakh

Answer & Explanation Answer: B) 1.1 lakh

Explanation:

Total cost of 4 cars = 1+2 = 3 lakh

Total S.P of 4 cars = 3 x 1.5 = 4.5 lakh ( $S i n c e S . P = \frac{(100 + G a i n %)}{100} x C . P$ )

S.P of 1 car = 1.2 lakh

S.P of rest 3 cars = 4.5 - 1.2 = 3.3 lakh

Average S.P of all the 3 cars = 1.1 lakh

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Filed Under: Profit and Loss
Exam Prep: AIEEE , Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

64 17383

Q:

What is the right most integer of the expression $65776^{759} + 54697^{467}$ ?

A) 4	B) 6
C) 9	D) 0

Answer & Explanation Answer: C) 9

Explanation:

Last digit for the power of 6 is 6 (always)

Power cycle of 7 is 7, 9, 3, 1.

Now 467/4 gives a remainder of 3

Then the last digit is $7^{3}$ = 3

Last digit is 6 + 3 = 9.

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Filed Under: Numbers
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Q:

Two pipes A and B can fill a tank in 24 hours and $17 \frac{1}{7}$ hours respectively. Harihar opened the pipes A and B to fill an empty tank and some times later he closed the taps A and B , when the tank was supposed to be full. After that it was found that the tank was emptied in 2.5 hours because an outlet pipe "C" connected to the tank was open from the beginning. If Harihar closed the pipe C instead of closing pipes A and B the remaining tank would have been filled in :

A) 2 hours	B) 8 hours
C) 6 hours	D) 4 hours

Answer & Explanation Answer: B) 8 hours

Explanation:

Efficiency of Inlet pipe A = 4.16% $(\frac{100}{24})$

Efficiency of Inlet pipe B = 5.83% $(\frac{100}{17 \frac{1}{7}})$

Therefore, Efficiency of A and B together = 100 %

Now, if the efficiency of outlet pipe be x% then in 10 hours the capacity of tank which will be filled = 10 * (10 - x)

Now, since this amount of water is being emptied by 'C' at x% per hour, then

$\frac{10 x (10 - x)}{x} = 2.5 h r s$

=> x = 8

Therefore, in 10 hours 20% tank is filled only. Hence, the remaining 80% of the capacity will be filled by pipes A and B in 80/10 = 8 hours

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Filed Under: Time and Work
Exam Prep: AIEEE , Bank Exams , CAT
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